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Trending Discussions on EASTL
QUESTION
we use EASTL and I can't use std::static_pointer_cast.
I receive a pointer to base class in my function and don't know, how to correctly cast it:
ANSWER
Answered 2021-May-10 at 16:03std::shared_ptr(static_cast(command.context.get()))
QUESTION
I am trying to clone this repository: https://github.com/electronicarts/EASTL But almost all of the submodules are adding this repository as a submodule! (see: https://github.com/electronicarts/EASTL/tree/master/test/packages)
This creates an infinite recursion, and it keeps cloning forever.
Is there a solution for this?!
...ANSWER
Answered 2021-Mar-25 at 23:26The infinite recursion happens if you specify the --recurse-submodules
option to git clone
. As a workaround, you could:
Clone the repository without submodules:
QUESTION
I am storing the ownership of some objects inside an unordered_set
, using unique_ptr
s.
But I don't know a good way to erase one of them from the set, when the time comes.
Code looks something like this:
...ANSWER
Answered 2020-Feb-14 at 05:29This is a tough case. erase
has an overload that takes a const key_type&
parameter, so we can try to create a "stale" unique_ptr
to get the hash value of the element to be erased:
QUESTION
As per this answer:
std::vector of std::vectors contiguity
A vector of vectors is not contiguous. EASTL claims that their vector is contgiuous (see: https://github.com/electronicarts/EASTL/blob/master/include/EASTL/vector.h it). Does this contiguity apply to a vector of vectors?
...ANSWER
Answered 2020-Feb-20 at 01:27What they mean is that the memory allocated by their vectors will be contiguous. Any memory allocated by the contained elements are not a part of this.
So yes, their vectors are contiguous. And no, that does not apply to all the contained elements as a group.
QUESTION
I'm getting results from a Query of installations and equipment number, however if I have more than one equipment in an installation I want to omit that data.
...ANSWER
Answered 2019-Nov-11 at 16:45It seems that you need to group by a~anlage
only:
QUESTION
I'm trying to replace my std stl usage to EASTL and since i have a lot of cpp/h files, i'm relying in 'Search in Files' option of vs-code, with the following pattern:
((?<=#include \<)([^\/(.h)]+?)(?=\>))
This matches completely fine in regexr.com, in both match and replace and in vs code as well but needs the option of PCRE2 engine being enabled due backreferences use.
Trying to reference the matching group #1 using $1
under Search sidebar view simply doesn't work, and just adds "$1".
But if i search & replace with the same input for each file manually, it works as intended.
Thanks.
...ANSWER
Answered 2019-Nov-05 at 03:39EDIT: The bug which prevented replace
from working properly with lookarounds has been fixed, see capture group in regex not working. It is working in the Insider's Build and will presumably be included in v1.39.
However, your regex:
((?<=#include \<)([^\/(.h)]+?)(?=\>))
should be changed to:
((?<=#include <)([^\/(.h)]+?)(?=>))
note the removal of escapes before <
and >
and then it works in the Insider's Build as of this date.
[And the PCRE2
mode has been deprecated since the original question. So you do not need that option anymore, PCRE2 will be used automatically if needed.]
There is a similar bug when using search/replace with newlines and the replace just literally inserts a $1
instead of the capture group's value. This bug has been fixed in the latest Insider's Build, see multiline replace issue and issue: newlines and replace with capture groups.
But I tried your regex in the Insider's Build and it has the same result as you had before - it inserts the literal $1
instead of its value. It appears to be a similar bug but due to the regex lookarounds.
So I tried a a simpler, but I think still correct, regex without the lookarounds:
^(#include\s+<)([^\.\/]+?)(>)
and replace with $1EASTL/$2.h$3
and it works as expected.
QUESTION
I have checked libcxx, eastl and boost, all of their pairs are trivial, no ebco. But all of them also implement their own compressed_pair and use it in utilities, unique_ptr(first -> pointer, second -> deleter) for example.
Now that ebco is useful, why don't their pairs not compress by default? Is there any trade-off for this optimization?
...ANSWER
Answered 2019-Sep-26 at 23:55Implementations of std::pair
cannot use empty base optimization (EBO), as the objects it contains are the member subobjects, first
and second
, and EBO only applies to base class subobjects.
Note that implementations of std::tuple
can use EBO, as its subobjects are exposed via std::get
, which allows the use of base class subobjects.
QUESTION
I am working on ABAP program - user input is to query column ANLAGE
and output is to get all records from table EADZ
(and only fields of EADZ
) based on ANLAGE
.
Statement and joins should work like this:
- Input
ANLAGE
, find in tableEASTL
, getsLOGIKNR
- Input
LOGIKNR
, find in tableEGERR
, getsEQUNR
- Input
EQUNR
, find in tableETDZ
, getsLOGIKZW
- Input
LOGIKZW
, find in tableEADZ
, gets all records (this is the final output)
Here is the code I tried:
...ANSWER
Answered 2019-Aug-28 at 12:23You can find the answer in the documentation.
If a column name appears multiple times and no alternative column name was granted, the last column listed is assigned.
In your case, at least two tables share the same column name. Therefore the values from the last mentioned table are used in the join.
You can solve this by listing the columns explicitly (or eadz~* in your case), giving an alias if required.
QUESTION
I want to have fmt::format return a wstring from EA's STL, but when I try to modify this code from the docs—which works fine:
...ANSWER
Answered 2019-Aug-11 at 04:29It seems that you need to use wformat_args
and explicitly specify wformat_context
for make_format_args
:
QUESTION
I have an function like this for an simple threadpool to enqueue an tasks on it, the following signatures are:
...ANSWER
Answered 2019-May-05 at 00:29It would look like this. I'm using std::invoke
(C++17) to be as generic as possible. You can replace it with a direct call if that's all you need.
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