Criterion | A cross-platform C and C++ unit testing framework for the 21st century | Unit Testing library
kandi X-RAY | Criterion Summary
kandi X-RAY | Criterion Summary
A dead-simple, yet extensible, C and C++ unit testing framework.
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of Criterion
Criterion Key Features
Criterion Examples and Code Snippets
# Download best mp4 format available or any other best if no mp4 available
$ youtube-dl -f 'bestvideo[ext=mp4]+bestaudio[ext=m4a]/best[ext=mp4]/best'
# Download best format available but no better than 480p
$ youtube-dl -f 'bestvideo[height<=480]
def __init__(self, *input_types, **kwargs):
"""Create a `Defun` decorator.
Args:
*input_types: A list of `tf.DType`
**kwargs: Optional keyword arguments, including
func_name - (optional). A python string, the name to us
def __init__(self,
criterion,
description=None,
font_attr=DEFAULT_TENSOR_ELEMENT_HIGHLIGHT_FONT_ATTR):
"""Constructor of HighlightOptions.
Args:
criterion: (callable) A callable of the follo
public void setDiscounted(Integer discounted) {
this.discounted = discounted;
}
Community Discussions
Trending Discussions on Criterion
QUESTION
I'm working with this API: http://hp-api.herokuapp.com/api/characters, which returns an array of objects. I have an input in my HTML that has an "keyup" event listener.
...ANSWER
Answered 2022-Apr-17 at 04:25Assuming an input field with an id of "input", you can filter the results to match the value of the input field:
QUESTION
I have a data frame with dates and magnitudes. For every case where the dates are within 0.6 years from each other, I want to keep the date with the highest absolute magnitude and discard the other.
- This includes cases where multiple dates are all within 0.6 years from each other. Like
c(2014.2, 2014.4, 2014.5)
which should give `c(2014.4) if that year had the highest absolute magnitude. - For cases where multiple years could be chained using this criterion (like
c(2016.3, 2016.7, 2017.2)
, where 2016.3 and 2017.2 are not within 0.6 years from each other), I want to treat the dates that are closest to one another as a pair and consider the extra date in the criterion as a next candidate for another pair, (so the output will read like thisc(2016.3,
2016.7,2017.2)
if 2016.3 had the highest absolute magnitude).
data:
...ANSWER
Answered 2022-Mar-16 at 11:18You can try to perform complete clustering on dates by using hclust
. The manhattan (i.e. absolute) distances are calculated between pairs of dates. The "complete" clustering method will ensure that every member of a cluster cut at h
height will be distant at most h
from the other members.
QUESTION
This code scans the neighbouring elements with a given criterion. For example, it starts from
0.26373153 and picks 0.58720689 since the criterion says to select elements less than 0.6. Similarly, it moves from 0.58720689 to 0.54531058. The current output along with the desired output is attached.
How do I also get a time output for each iteration? Suppose the time loop starts at t=0 for 0.26373153 and then t>0 for the next values: 0.58720689,0.54531058,...
...ANSWER
Answered 2022-Mar-06 at 19:19I'm not sure about what do you need. If you need to compute how many tries the code does before to see another value less than 0.6, this can be easly done creating a variable that is increased at each iteration and set to 0 when you find a "correct" value.
If you need to compute how much time it runs before to find another value less than 0.6 you need to use the time
library. The istruction t1 = time.time()
saves in t1 the amount of seconds elapsed since epoch (epoch is January 1, 1970, 00:00:00) as floating point number (see here to more details), so when you start the research you save your time in one variable (say t1), when you find a value in the array that is less than 0.6 you save in another variable the current time (say t2), and at this point to know how much time is elapsed you need to compute (t2-t1); then save the value of t2 in t1 and continue like this.
EDIT: with your edit I have understood what you need.
Try this, but remember to add import time
:
QUESTION
I'm new here, I've tried to run a lmer model:
...ANSWER
Answered 2022-Feb-21 at 09:42It depends on what your research question is, but
the response when both fixed effects are zero is is 0.15716
a 1 unit change in
SET
is associated with a 0.08180 change inRI
a 1 unit change in
LOG_VP
is associated with a 0.03527 change inRI
Variance at the
API
level is 0.01431Variance at the
ODOUR
level is 0.00415Residual (unit level) variance is 0.00778
QUESTION
I am currently working on an neuronal network that can classify cats and dog and everything thats not cat nor dog. And my programm has this: error i can't solve:
" File "/home/johann/Schreibtisch/NN_v0.01/classification.py", line 146, in train(epoch) File "/home/johann/Schreibtisch/NN_v0.01/classification.py", line 109, in train loss = criterion(out, target) File "/home/johann/.local/lib/python3.8/site-packages/torch/nn/modules/module.py", line 889, in _call_impl result = self.forward(*input, **kwargs) File "/home/johann/.local/lib/python3.8/site-packages/torch/nn/modules/loss.py", line 1047, in forward return F.cross_entropy(input, target, weight=self.weight, File "/home/johann/.local/lib/python3.8/site-packages/torch/nn/functional.py", line 2693, in cross_entropy return nll_loss(log_softmax(input, 1), target, weight, None, ignore_index, None, reduction) File "/home/johann/.local/lib/python3.8/site-packages/torch/nn/functional.py", line 2388, in nll_loss ret = torch._C._nn.nll_loss(input, target, weight, _Reduction.get_enum(reduction), ignore_index) RuntimeError: 1D target tensor expected, multi-target not supported"
The code:
...ANSWER
Answered 2022-Feb-16 at 15:35The reason behind this error is that your targets list are list of lists like that:
QUESTION
I have tried the similar problems' solutions on here but none seem to work. It seems that I get a memory error when installing tensorflow from requirements.txt. Does anyone know of a workaround? I believe that installing with --no-cache-dir would fix it but I can't figure out how to get EB to do that. Thank you.
Logs:
...ANSWER
Answered 2022-Feb-05 at 22:37The error says MemoryError
. You must upgrade your ec2 instance to something with more memory. tensorflow
is very memory hungry application.
QUESTION
ANSWER
Answered 2022-Jan-23 at 00:00I can tell you the answer, but I cannot write complete r
code for it, since I don't know r
, I hope some one may edit my code for a complete answer.
suppose both sorts are ascending (you can generalize it to your case)
QUESTION
I am trying to access AIC, BIC , logLik and deviance data from a model summary
of an HLM fitted using maximum likelihood (ML) in lme4::lmer
, and combine with essentially the same model fitted with restricted maximum likelihood (REML). The structure of the objects returned from lmer
and summary
is a mess, and I am unable to find out where/how this data is stored.
[Update:] Based on the responses I've gotten, I have updated the code to reflect the progress made:
Code example:
...ANSWER
Answered 2022-Jan-09 at 17:21There are a few points:
- You have a typo here:
QUESTION
I am using the latest version of foolbox (3.3.1), and my code simply load a RESNET-50 CNN, adds some layers for a transferred learning application, and loads the weights as follows.
...ANSWER
Answered 2021-Nov-23 at 12:13I think you might have mixed up the parameters of the L2CarliniWagnerAttack
. Here is a simplified working example with dummy data:
QUESTION
Best practice when analysing data from an RCT is to adjust for the baseline measure (ancova). However, researchers often still ask for change from baseline in each group and their relative difference (given by the treatment x time interaction). When one adjusts for the baseline measure, contrasts involving time can only be made from the first post-baseline measure.
Is there a way to perform a contrast where you subtract the model prediction at each post-treatment time point from the baseline measure (e.g. the overall pre-treatment mean of the combined groups)? I could do this manually but wouldn’t get C.I.'s.
Some dummy data are below:
...ANSWER
Answered 2022-Jan-05 at 23:31As I said in a comment, the baseline is already set at its mean by default, so you get exactly the same the adjusted means as shown in the OP:
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