kemon | Source Pre and Post Callback | Monitoring library

by didi C Version: Current License: Apache-2.0

X-Ray Key Features Code Snippets Community Discussions(3)Vulnerabilities Install Support

kandi X-RAY | kemon Summary

kemon is a C library typically used in Performance Management, Monitoring applications. kemon has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

Kemon is an open source Pre and Post callback-based framework for macOS kernel monitoring [1]. With the power of Kemon, we can easily implement XPC/IPC communication monitoring [2], Mandatory Access Control (MAC) policy filtering, network traffic and kernel extension firewall, etc. In general, from an attacker's perspective, this framework can help achieve more powerful Rootkit. From the perspective of defense, Kemon can help construct more granular monitoring capabilities.

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Quality

Security

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Support

kemon has a low active ecosystem.

It has 362 star(s) with 75 fork(s). There are 39 watchers for this library.

It had no major release in the last 6 months.

There are 3 open issues and 2 have been closed. On average issues are closed in 1 days. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of kemon is current.

Quality

kemon has no bugs reported.

Security

kemon has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

License

kemon is licensed under the Apache-2.0 License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

kemon releases are not available. You will need to build from source code and install.

Installation instructions are available. Examples and code snippets are not available.

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kemon Key Features

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kemon Examples and Code Snippets

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Community Discussions

Trending Discussions on kemon

Regexp search result hightlight with accent

How to solve the problem of 'CPU Limit Exceeded'?

Is it possible to use a string with multiple words as json key?

QUESTION

Regexp search result hightlight with accent

Asked 2021-Mar-03 at 03:29

Can someone help me to improve my search please ? I try to highlight several words when a user write one or many things in the input. I am using this function :

...

ANSWER

Answered 2021-Mar-03 at 03:29

To search accented text without accent in the search terms you can define an accent map, and compose a regex from that:

Source https://stackoverflow.com/questions/66444282

QUESTION

How to solve the problem of 'CPU Limit Exceeded'?

Asked 2020-Feb-02 at 11:35

I am trying to solve the "Aaj Kemon Bodh Korcho" problem on Toph:

There is a match between Barcelona and Real Madrid. [...] There is a GOAL in each and every second of the match. All the goals may not be valid i.e. some of the goals can be done from OFF SIDE which is out of the rules.

[Output] “Aaj Kemon Bodh Korcho” (without quotes) if Barcelona won the match, “Hala Madrid” (without quotes) if Real Madrid won the match or “Meh :\” (without quotes) if there is no winner.

[...] The goals that are done from OFF SIDE are belongs (sic) to a famous series [...]:

0, 1, 1, 2, 3, 5, 8 …, …, …, …, …, n^th term
Input
You’re given an integer number T which denotes the number of test cases (T <=100). In (sic) each of the T line contains a string (S) of following characters (B, M). The maximum length of the string will not be greater than 10⁵. Note that, the starting index will be 0.

Here,
If the i^th character is B then it denotes a goal is done by Barcelona at i^th second.
If the i^th character is M then it denotes a goal is done by Real Madrid at i^th second.
Output
For each of the T lines you have to print the case number first according to the format Case #X where X is the case number. Then you have to print Aaj Kemon Bodh Korcho if Barcelona won the match or Hala Madrid if Real Madrid won the match. Otherwise print Meh :\ . For more clarification see the samples below.
Sample ...

ANSWER

Answered 2020-Feb-02 at 11:35

In your program, you have this line del store_1[y]. This is an O(n) operation according to here. So, your code works in O(n²). That is why you are getting CPU Time Exceeded.

Maintain 2 counters , b=0 and m=0. Iterate through the given string and find if the given index is part of the set, If yes, don't do anything. Else check if it is B or M. Accordingly, increment the counters and do the necessary check in the end.

Also, instead of generating Fibonacci series multiple times, you can actually generate it once and use the results again and again for the test cases.

Source https://stackoverflow.com/questions/60016724

QUESTION

Is it possible to use a string with multiple words as json key?

Asked 2017-Sep-30 at 07:40

it's common to have json keys without spaces. I can access a value of a json simply calling it's key. But if my json looks like

...

ANSWER

Answered 2017-Sep-30 at 07:37

You just do:

Source https://stackoverflow.com/questions/46500623

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