xed | X-Apps Editor ( Cross-DE | Editor library

Their Types could be different.Also I recommend you to use

The DynamoDB console is showing you a base64-encoded representation of the underlying binary attribute value.

I'm assuming that's a reasonable thing to do so that the console can safely display arbitrary binary attribute values.

If you decode the displayed value, as follows, you can recover the original Python bytes:

1. I would highly recommend that you encode whatever you want to sign in base64 before signing. This is a standard approach for digital signatures, ensuring consistency of the signed data.
2. The output of the pyzbar.decode function is an array of "Decoded" objects, of which you're not retrieving the correct element.

Below the corrected code:

The bytes you have are IEEE-754 encodings of the numbers 46870, 46829.55078125, 46870.1015625, 46870, and 46917.20703125.

To decode them, copy the bytes into a float object in little-endian order, then interpret them as that float object. Details of how to do this will depend on the programming language used, which the question does not state.

To decode them manually, write out the 32 bits of each four bytes, with the bits of the fourth byte first (in the high-value positions), then the bits of the third byte, then the second, then the first. From those 32 bits, take the first one as a sign bit s. Take the next eight as bits for an exponent code e. Take the last 23 as bits for a significand code f.

Decode the sign bit: Let S = (−1)^s.

Decode the exponent bits: Interpret them as an unsigned eight-bit numeral, e. Then:

• If e is 255 and f is zero, then the number represented is +∞ or −∞ according to whether S is +1 or −1. The decoding is done, stop.
• If e is 255 and f is not zero, the data represents a NaN (Not a Number), and f contains supplementary information. In typical implementations, if the high bit of f is set, the NaN is a quiet, otherwise it is signaling. The decode is done, stop.
• If e is zero, let E = −126 and let F = 0.
• Otherwise, let E = e−127 and let F = 1.

Decode the significand bits: Let F = F + f•2⁻²³.

The number represented is S • F • 2^E.

There is a library called cryptography which can do exactly this:

You should use response.json() to get it as a JSON.

response.content returns a binary representation.

Since you used a named group usr in your regex, Django passes it as a keyword argument:

Here is an example code, some characters may fall out, but the gist is this:

Are you surprised to learn that this field is encrypted? Google would be in for a world of trouble if it wasn't. Even Chrome doesn't know how to decrypt this. It's done with the Windows cryptography APIs, and involved your Windows login password. You can't get them.