A2 | Similar to Lua and Javascript | Infrastructure Automation library
kandi X-RAY | A2 Summary
kandi X-RAY | A2 Summary
Similar to Lua and Javascript, it includes a register-based virtual machine.
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QUESTION
I'm trying to create a new variable based on some conditions. I have the following data:
...ANSWER
Answered 2021-Jun-15 at 16:13We can use a group by operation in dplyr
i.e. grouped by 'ID', extract the 'code' where the 'type' value is "large" (assuming there are no duplicate values for 'type' within each 'ID'
QUESTION
I am relatively new in dealing with txt and json datasets. I have a dialogue dataset in a txt file and i want to convert it into a csv file with each new line converted into a column. and when the next dialog starts (next paragraph), it starts with a new row. so i get data in format of
...ANSWER
Answered 2021-Jun-15 at 19:08A CSV file is a list of strings separated by commas, with newlines (\n
) separating the rows.
Due to this simplistic layout, it is often not suitable for containing strings that may contain commas within them, for instance dialogue.
That being said, with your input file, it is possible to use regex to replace any single newlines with a comma, which effectively does the "each new line converted into a column, each new paragraph a new row" requirement.
QUESTION
I have been trying to sort the Column values from A to Z which are populated in the List Box.
I have tried with the following but it does not adjust it. Any help will be appreciated.
...ANSWER
Answered 2021-Jun-15 at 18:37You need to sort the range using the Range.Sort method
QUESTION
I'm trying to parallelize a merge-sort algorithm. What I'm doing is dividing the input array for each thread, then merging the threads results. The way I'm trying to merge the results is something like this:
...ANSWER
Answered 2021-Jun-15 at 01:58I'm trying to parallelize a merge-sort algorithm. What I'm doing is dividing the input array for each thread, then merging the threads results.
Ok, but yours is an unnecessarily difficult approach. At each step of the merge process, you want half of your threads to wait for the other half to finish, and the most natural way for one thread to wait for another to finish is to use pthread_join()
. If you wanted all of your threads to continue with more work after synchronizing then that would be different, but in this case, those that are not responsible for any more merges have nothing at all left to do.
This is what I've tried:
QUESTION
ANSWER
Answered 2021-Jun-15 at 18:00Here is an option with max.col
.
- Get the column index for the
max
value in a row for selected columns and specify theties.method
as 'first' or 'last' - Use the index to extract the column name
- Create a
data.frame
with the column names extracted along with the 'ID' column
QUESTION
Dataset looks like this : This is a sample dataset for number of employee login activity named - activity
I need to calculate few metrics, was able to do in python data frames, but new in mySQL.
what is the average number of employee active per day for month of jan 2018 by dept ( was able to do somewhat half of it, but results coming are not correct.
number of unique active employee (login >0) per month for jan 2018 for each dept_id (was able to do it)
month over month growth for all dept_id from dec-2017 to jan 2018 where at least one employee was active (login >0) - no idea how to do this in sql
fraction of users who were active in each dept_id for dec 2017 and were also active in the same dept_id for jan 2018
how many employee login in on 3 or more consecutive days in jan 2018
Any help would be appreciated.
Query written for case 1:
...ANSWER
Answered 2021-Jun-15 at 16:59Let me know if this works otherwise I will update the answer, I don't have MYSQL installed so wasn't able to check.
And the date is a keyword in oracle but not sure in MYSQL so use it in quotes like "date".
Case 1:
QUESTION
So I was really ripping my hair out why two different sessions of R with the same data were producing wildly different times to complete the same task.
After a lot of restarting R, cleaning out all my variables, and really running a clean R, I found the issue: the new data structure provided by vroom
and readr
is, for some reason, super sluggish on my script. Of course the easiest thing to solve this is to convert your data into a tibble as soon as you load it in. Or is there some other explanation, like poor coding praxis in my functions that can explain the sluggish behavior? Or, is this a bug with recent updates of these packages? If so and if someone is more experienced with reporting bugs to tidyverse, then here is a repex
showing the behavior cause I feel that this is out of my ballpark.
ANSWER
Answered 2021-Jun-15 at 14:37This is the issue I had in mind. These problems have been known to happen with vroom, rather than with the spec_tbl_df
class, which does not really do much.
vroom
does all sorts of things to try and speed reading up; AFAIK mostly by lazy reading. That's how you get all those different components when comparing the two datasets.
With vroom:
QUESTION
Overview
I am trying to tabulate time over days under Google Sheets and see each person's availability based on their start and end times which changes almost every week.
File Information I have this Sample Availability Timesheet with two Sheet-Tabs.
Master Sheet-Tab: This Sheet-Tab contains the list of employees with their respective start-time & end-time.
Availability Sheet-Tab: This Sheet-Tab contains the list of employees and a timescale with one hour hop. The resource availability is marked with Y, and by N if the resource is not available using the following formula:
...ANSWER
Answered 2021-Jun-15 at 14:04Updated formula:
=IF(VALUE(VLOOKUP($A2, Master!$A:$M, 13, 0)) > VALUE(VLOOKUP($A2, Master!$A:$M, 12, 0)), IF(ISBETWEEN(B$1, VALUE(VLOOKUP($A2, Master!$A:$M, 12, 0)), VALUE(VLOOKUP($A2, Master!$A:$M, 13, 0))), "Y", "N"), IF(OR(B$1 <= VALUE(VLOOKUP($A2, Master!$A:$M, 13, 0)), B$1 >= VALUE(VLOOKUP($A2, Master!$A:$M, 12, 0))), "Y", "N"))
Screenshot from the sheet you've shared with the formula working:
This version is an extension of the formula you shared. If someone is working from 4PM to 2AM then the way IFBETWEEN
is being used will throw an error because 2AM is numerically less than 4PM and hence there is nothing in between.
So in cases where someone starts at a PM time and ends at AM time the formula checks for all slots between 12AM and the person working AM and marks them a Y. At the same time the formula also checks for all times in PM that are greater than the person working PM and marks them a Y as well.
If the person starts at a PM time and ends at a greater PM time then it uses your initial version of the formula.
I have made a slight modification to your formula and it should work now.
=IF($C9>$B9, IF(ISBETWEEN(B$1, VLOOKUP($A2, $A$8:$C, 2, 0), VLOOKUP($A2, $A$8:$C, 3, 0)), "Y", "N"), IF(OR(B$1 <= VLOOKUP($A2, $A$8:$C, 3, 0), B$1 >= VLOOKUP($A2, $A$8:$C, 2, 0)), "Y", "N"))
Please remember to remove the dates from some of the cells ex in your sheet the value in C2
is 12/31/1899 2:00:00 and it should be changed to just 2:00:00.
QUESTION
I'm working with some data where I have hourly observations for patients. In some cases, some of the features for a specific patient are completely empty. I'm trying to find a way to impute the data by using constant average that's based off a population subset of 50 other patients who have the same gender and a similar age. I've given a simplified look at the data below:
HR O2Sat Temp Platelets Age Gender PatientID 80 98 36.5 NaN 52 1 A0 82 96 37.0 NaN 52 1 A0 82 100 36.3 160 53 1 A1 90 93 36.6 165 53 1 A1 83 95 35.9 140 23 0 A2 79 98 36.2 155 23 0 A2 88 92 36.6 163 60 0 A3 90 91 36.3 165 60 0 A3 81 95 37.1 NaN 20 0 A4 81 92 36.9 NaN 20 0 A4I've reordered the dataframe by age and have this code so far
data = data.sort_values(['Age']).groupby(['PatientID','Gender']).apply(lambda x: x.fillna(x.mean()))
But I know that that's going to use all of the available data to find the mean but I'm not sure how to limit it to 50 patients of a similar age.
...ANSWER
Answered 2021-Jun-15 at 13:43I think I get what you want now. You want to fill the gaps with matching records for the right age and category. I created a simple example to debug.
QUESTION
I need to generate a list of dates in a dataframe by days and that each day is a row in the new dataframe, taking into account the start date and the end date of each record.
Input Dataframe:
A B Start End A1 B1 2021-05-15 00:00:00 2021-05-17 00:00:00 A1 B2 2021-05-30 00:00:00 2021-06-02 00:00:00 A2 B3 2021-05-10 00:00:00 2021-05-12 00:00:00 A2 B4 2021-06-02 00:00:00 2021-06-04 00:00:00Expected Output:
A B Start End A1 B1 2021-05-15 00:00:00 2021-05-16 00:00:00 A1 B1 2021-05-16 00:00:00 2021-05-17 00:00:00 A1 B2 2021-05-30 00:00:00 2021-05-31 00:00:00 A1 B2 2021-05-31 00:00:00 2021-06-01 00:00:00 A1 B2 2021-06-01 00:00:00 2021-06-02 00:00:00 A2 B3 2021-05-10 00:00:00 2021-05-11 00:00:00 A2 B3 2021-05-11 00:00:00 2021-05-12 00:00:00 A2 B4 2021-06-02 00:00:00 2021-06-03 00:00:00 A2 B4 2021-06-03 00:00:00 2021-06-04 00:00:00 ...ANSWER
Answered 2021-Jun-15 at 11:48Use:
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