rmem | MTuner SDK - Memory profiling library | Monitoring library
kandi X-RAY | rmem Summary
kandi X-RAY | rmem Summary
[License] rmem is an SDK library for [MTuner] providing additional features and cross-platform support.
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QUESTION
I ask a Measurement Device to give me some Data. At first it tells me how many bytes of data are in the storage. It is always 14. Then it gives me the data which i have to encode into hex. It is Python 2.7 can´t use newer versions. Line 6 to 10 tells the Device to give me the measured data. Line 12 to 14 is the encoding to Hex. In other Programs it works. but when i print result(Line 14) then i get a Hex number with 13 Bytes PLUS 1 which can not be correct because it has an L et the end. I guess it is some LONG or whatever. and i dont need the last Byte. but i do think it changes the Data too, which is picked out from Line 15 and up. at first in Hex. Then it is converted into Int.
Is it possible that the L has an effect on the Data or not? How can i fix it?
...ANSWER
Answered 2020-Nov-16 at 07:20Python 2 has two built-in integer types, int
and long
. hex
returns a string representing a Python hexadecimal literal, and in Python 2, that means that long
s get an L
at the end, to signify that it's a long
.
QUESTION
UPDATE: added some java code and also the command used to start the job
I am running an indexing process as a job on an HPC server which allocates memory to jobs. I hit the memory ceiling during the indexing process, and I would like to ask for my data an usage scenario, what would be minimum memory for 1) indexing and 2) querying the index later.
Scenario:
- projected index size to be around 70GB
- projected record # to be around 150 million
- I use Java solr client, solr = 7.1.0
- During indexing I commit every 10k records
- I ran the job with 24GB allocated memory during indexing but it crashed about half way, i.e., 75million records indexed
- Query usage: very light, the index is only to be used by myself (one person) to access the data easily and query will only be sequential and mostly one field based
The Java code below is used to start a server in the 'embedded' mode:
...ANSWER
Answered 2019-Dec-15 at 13:02If the server is killing the job, your memory settings are probably too high - since it's the OS killing it, and not the JVM creating an out of memory exception. In effect you're telling the JVM to use more memory than the OS allows it to; reduce the memory made available to the JVM and let it run its GC instead.
If you give the JVM 24G, and the total allocated memory on your server is 24G, the JVM will eat everything and get killed when there is no more room available. On your laptop this setting is different and it doesn't get killed because it uses too much memory.
The JVM believes it has as access to at least as much memory as you tell it, and then the OS underneath sees that "oh, that jvm process is sure using a lot of memory .. and I'm all out of available memory .. guess I'll have to kill it". When this happens, the process just disappears and won't be able to log anything (except to the syslog or depending on your operating system, a different log, which will tell you that it what got killed).
QUESTION
The usual top
command on UNIX and Mac OS, was extended to hadoop in its recent versions, some information about it is given here.
It has the following headers,
APPLICATIONID USER TYPE QUEUE #CONT #RCONT VCORES RVCORES MEM RMEM VCORESECS MEMSECS %PROGR TIME NAME
I was wondering what #RCCONT
RVCORES
and RMEM
mean.
ANSWER
Answered 2017-Oct-31 at 19:42R stands for reserved. So they can be interpreted as:
QUESTION
I read How large should my recv buffer be when calling recv in the socket library in order to understand buffer in read. There are yet some points that i wish to know about read buffer in tcp socket connection. My application is sending video packets. when i set buff to 80000 sender could send the packets but when i set it less for example 8000 after sending few packets it stops with RST.
a)Is this buffer, TCP receive window? b)Is there any relation between this buffer and .net.ipv4.tcp_rmem , .net.ipv4.tcp_wmem ?if yes, Should i set read buffer based on rmem or wmem?
I would greatly appreciate any responses
...ANSWER
Answered 2017-Feb-02 at 04:39a)Is this buffer, TCP receive window?
No, it is just a buffer that you provide for the TCP stack to place bytes into when you call recv().
b)Is there any relation between this buffer and .net.ipv4.tcp_rmem , .net.ipv4.tcp_wmem?
No.
if yes, Should i set read buffer based on rmem or women?
You can pass any size buffer you want to recv(); it is unrelated to any of the above, except that there isn't any benefit to making the buffer you pass to recv() larger than the socket's current SO_RCVBUF size, since it's unlikely that recv() would ever return more bytes at once than can be present in the socket's internal buffer.
As for how to decide what size buffer to use -- consider that a larger buffer will (of course) take up more memory, and if you are allocating that buffer on the stack, a very large buffer might cause a stack overflow. On the other hand, a smaller buffer means that you can read fewer bytes with any given call to recv(), so you may have to call recv() more times to read in the same total number of bytes.
Note that number of bytes of data returned by recv() may be any number from 1 byte up to the total size of the buffer that you passed in to recv()'s third argument, and there is no way to predict how many bytes you'll get. In particular, with TCP the number of bytes you receive from any particular call to recv() will not have any correlation to the number of bytes previously passed to any particular call to send() on the sending side. So you just need to use a "reasonably sized" array (for whatever definition of "reasonably sized" you prefer) and recv() as many bytes into it as possible, and then handle that many bytes (based on recv()'s return value).
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