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A very moddable 19-key numpad kit built by nullbits. More info at nullbits.co.
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QUESTION
This is the python version of the same C++ question.
Given a number, num
, what is the fastest way to strip off the trailing zeros from its binary representation?
For example, let num = 232
. We have bin(num)
equal to 0b11101000
and we would like to strip the trailing zeros, which would produce 0b11101
. This can be done via string manipulation, but it'd probably be faster via bit manipulation. So far, I have thought of something using num & -num
Assuming num != 0
, num & -num
produces the binary 0b1
. For example,
ANSWER
Answered 2022-Mar-23 at 04:41You say you "Ultimately, [..] execute this function on a big list of numbers to get odd numbers and find the maximum of said odd numbers."
So why not simply:
QUESTION
I'm working on a convenience function in R that prints a publication quality LaTeX table from some common model objects. It all works just great for me on my Mac, but I've built it largely for a colleague who's on a PC, for whom the file writing fails when calling save_kable()
from the kableExtra
package.
We get no output whatsoever from this. No pdf and no error messages.
A simple reproducible example, which fails in the same way, is as follows:
...ANSWER
Answered 2022-Mar-20 at 00:14The problem turned out to be missing LaTeX dependencies. The kableExtra
package creates a .tex
file with a long list of required packages (see below), but MikTex, the Tex distribution we were using, was unable to automatically install them, and the errors didn't propagate through to R. Here is a post with some useful details.
There are a number of solutions, each for a different distribution.
Use TexLive, rather than MikTex. I use TexLive on my Mac, and it appears to have no trouble locating and installing the dependencies. The downside is that it's gigantic (>7GB to MikTex's <1GB).
For MikTex, you can get the packages downloaded with a combination of two approaches. First, set
keep_tex = TRUE
inkableExtra::save_kable()
, which should produce the .tex file for compilation. Next, compile it at the command line withxelatex yourtable.tex
. You can't uselatex yourtable.tex
, since this compiler can't work with the requiredfontspec
package. This may download all that you need. If it doesn't, check the log file for a missing.sty
file: we needed to manually download thetabu
package. You can manually install the missing files from MikTex Console: Packages > Search for "tabu" > "+" to install. Rinse, repeat until you have all the packages you need. You could do this for all the dependencies, but there are a lot, so might as well let the compiler do as much work as possible first, then backfill as needed.Compile with TinyTex in R. Create the
.tex
file as above (`keep_tex = TRUE'). Then:
QUESTION
From the Rust Tidbits: What Is a Lang Item?, there is a piece of code, I copied and put in the
src/main.rs
ANSWER
Answered 2022-Jan-14 at 08:01I found an example of #[lang = "start"]
in ~/.rustup/toolchains/nightly-x86_64-unknown-linux-gnu/lib/rustlib/src/rust/library/std/src/rt.rs
.
QUESTION
I'm working on a little demo of a Command Terminal that stores some stuff (Zones, items held within those zones, etc). I was inspired by this game called GTFO. Anyways, I'm trying to get an If Statement to accept multiple spellings of a command. For instance, the command (Help) could be full uppercase, full lowercase, grammatically correct, etc. However, while it does run up until the input, when I attempt to input Help or any variation of help, it stops dead. Tried dissecting it into a separate variable (helpCommand), but didn't work. Any suggestions?
...ANSWER
Answered 2021-Nov-19 at 16:09You are checking if the command they give is equal to the entire list of help commands. What you are looking for is:
QUESTION
I'm attempting to configure a Linked Service within my Data Factory. In this case, it's to a MariaDB instance on Ubuntu 20.04LTS.
I'm able to establish the connection from other parts of the virtual network just fine (ex. Windows 10 VM + HeidiSQL). However, when I attempt to configure (ip, database, credentials) and test the connection, I get:
...ANSWER
Answered 2021-Sep-28 at 13:38I ended up using "Azure Database for MySQL" and was able to have the Data Factory communicate to it.
QUESTION
I'm extremely new to coding in JavaScript and I'm setting up a simple event bot for a Discord server.
It's very simple in concept, all the bot really does is allow anyone to assign a "Dead" role to any member they mention.
...ANSWER
Answered 2021-Sep-25 at 23:41The member.roles.cache that you are attempting to search in is a Collection object, which extends the normal JavaScript Map. Maps store their values in a Key-Value pair. In this case the roles is the value and the key is an auto-generated Snowflake, which is basically a unique ID. Now, perhaps counter-intuitively, the .has() function is not actually searching if your cache (Map) has a value matching whatever you parse as a parameter, but if it has a key that matches it.
Searching if a Map has a specific value in it is a bit more tricky. There's a few ways to go about it. One of those is to quickly convert the Map to an Array and call .includes() on that array like so:
QUESTION
I am building a flutter app, and I am using a stream to subscribe to Firestore query results. Unfortunately, I don't understand how the snapshot listener metric works, combined with this tidbit from the documentation:
Does the 27 peak mean I've somehow created 27 listeners (when I should be making one)? I'm confused.
Also to note that I have made 0 interactions with my app, just left it running..
...ANSWER
Answered 2021-Jun-28 at 18:00In Firestore, every time you add the onSnapshot
method, you're creating a new Snapshot Listener for this user.
So according to you print, you have 1 user connected to your app (1 Active Connection) and this user has 27 listeners attached to it.
So it seems that either you're getting real time updates from 27 Firestore queries, or you're not closing your connections.
From the 3rd reference, from Firebase docs:
Is it bad?Let's say a user opens your app on their phone. The app then connects to Cloud Firestore and subscribes to 10 queries. This increases your metrics by 1 active connection and 10 snapshot listeners.
Even though you're not paying for those active connection or the listeners, every time a doc is read / updated, this will count as a new read, and those are charged in the end. So using way too many listeners is not the best practice.
What to do?The first thing I'd say is to double check if you're not keeping the listeners opened once the component / view is closed. If you find any, don't forget to detach them.
ReferencesQUESTION
{ [key: string]: V }
?
I'm trying to create a Typescript function to generate an object with a dynamic key whose name is provided in the function signature, without the return type getting widened to { [key: string]: V }
.
So I want to call:
createObject('template', { items: [1, 2, 3] })
and get back an object { template: { items: [1, 2, 3] } }
that isn't just an object with string keys.
Before you tell me this is impossible, let's make a rainbow:
...ANSWER
Answered 2021-Jun-23 at 01:31You can make mapped types iterate over any key or union of keys you want without having to resort to remapping-with-as
. Mapped types don't need to look like [P in keyof T]
... they can be [P in K]
for any keylike K
. The canonical example of this is the Record
utility type whose definition looks like this:
QUESTION
TL;DR: we have long-running imports which seem to hold locks on the parent partitioned table even though nothing is directly referencing the parent table.
BackgroundIn our system, we have inventories
and inventory_items
. Inventories tend to have 200k or so items, and it made sense for our access patterns to partition the inventory_items
table by inventory_id
using native partitioning (we're on Postgres 12). In other words, each inventory gets its own partitioned table of inventory_items. This is accomplished with the following DDL:
ANSWER
Answered 2021-Apr-09 at 15:59Creating a partition with CREATE TABLE ... PARTITION OF ...
requires an ACCESS EXCLUSIVE
lock on the partitioned table, which will conflict with all access to the partitioned table.
On the other hand, inserting into the partition requires an ACCESS SHARE
lock on the partitioned table while the insert statement is being planned. That causes a lock conflict.
I see two ways out:
Create new partitions in two steps:
QUESTION
To start off, regex is probably the least talented aspect within my programming belt, this is what I have so far:
\D{1,5}(PR)\D+$
\D{1,5}
because common stock symbols are always a maximum of 5 letters
(PR)
because that is part of the pattern that needs to be searched (more below in the background info)
\D+$
because I'm trying to match any single letter at the end of the string
A small tidbit of background
Preferred stock symbols are not standardized and so every platform, exchange, etc has their own way to display them. Having said that, most display a special character in their name, which makes those guys easy to detect. The characters are
[] {'.', '/', '-', ' ', '+'};
The trickier ones all have a similar pattern:
{symbol}PR{0}
{symbol}p{0}
{symbol}P{0}
Where 0
is just any single letter A-Z
Here is a sample data set for the trickier ones:
...ANSWER
Answered 2021-Mar-04 at 19:19This should do it:
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