stabber | Stabber acts as a stubbed XMPP service | TCP library

by profanity-im C Version: Current License: GPL-3.0

X-Ray Key Features Code Snippets Community Discussions(1)Vulnerabilities Install Support

kandi X-RAY | stabber Summary

stabber is a C library typically used in Networking, TCP applications. stabber has no bugs, it has no vulnerabilities, it has a Strong Copyleft License and it has low support. You can download it from GitHub.

Stabber acts as a stubbed XMPP service for testing purposes, supporting:. The project is work in progress, and is being developed alongside

Support

Quality

Security

License

Reuse

Support

stabber has a low active ecosystem.

It has 8 star(s) with 1 fork(s). There are 5 watchers for this library.

It had no major release in the last 6 months.

There are 5 open issues and 0 have been closed. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of stabber is current.

Quality

stabber has no bugs reported.

Security

stabber has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

License

stabber is licensed under the GPL-3.0 License. This license is Strong Copyleft.

Strong Copyleft licenses enforce sharing, and you can use them when creating open source projects.

Reuse

stabber releases are not available. You will need to build from source code and install.

Installation instructions are not available. Examples and code snippets are available.

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stabber Key Features

No Key Features are available at this moment for stabber.

stabber Examples and Code Snippets

No Code Snippets are available at this moment for stabber.

Community Discussions

Trending Discussions on stabber

Python compare two lists, add specific string to list if substring is in main list

QUESTION

Python compare two lists, add specific string to list if substring is in main list

Asked 2020-May-28 at 22:26

I have a python bot which scrapes a website for data. Once it has the data it's filtered and the names are read clearly; this is list 1. Then, in list 2, I have strings of set names and I'm trying to compare list 2 to list 1 to see if list 1 contains one of any of the strings from list 2, and if it does, list 1 will have a string inserted into it showing that it contains a string from list 2. This is my loop:

...

ANSWER

Answered 2020-May-28 at 22:26

for s in newbots:
    if s in bossbots:
        s = s+'bossbot'
    else:
        continue


# Another possible method with list comprehension.
[s+'bossbot' for s in newbots if s in bossbots]

Source https://stackoverflow.com/questions/62074731

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install stabber

You can download it from GitHub.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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