lgamma | Implementations of polygamma , lgamma , and beta functions | GPU library

 by   rachtsingh C Version: Current License: MIT

kandi X-RAY | lgamma Summary

kandi X-RAY | lgamma Summary

lgamma is a C library typically used in Hardware, GPU, Pytorch applications. lgamma has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

Implementations of polygamma, lgamma, and beta functions for PyTorch. It's very hacky, but that's usually ok for research use. You'll probably need to pass in the correct CUDA path to build.py, which is run inside make.sh, so modify it to instead call.
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              lgamma has a low active ecosystem.
              It has 23 star(s) with 5 fork(s). There are no watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 2 open issues and 1 have been closed. On average issues are closed in 12 days. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of lgamma is current.

            kandi-Quality Quality

              lgamma has no bugs reported.

            kandi-Security Security

              lgamma has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              lgamma is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              lgamma releases are not available. You will need to build from source code and install.
              Installation instructions are not available. Examples and code snippets are available.

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            lgamma Key Features

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            lgamma Examples and Code Snippets

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            Community Discussions

            QUESTION

            Difference between log likelihood by hand and logLike function
            Asked 2020-Dec-30 at 15:26

            I'm trying to compare the value of the log likelihood function given by the logLik function and the value calculate by hand for a Gamma distribution. The value given by the logLik function is:

            ...

            ANSWER

            Answered 2020-Dec-30 at 15:15

            You've interverted scale and shape and there's a couple of sign errors in your code.

            Source https://stackoverflow.com/questions/65508908

            QUESTION

            How to write a for loop to compute max of each column for a dataset in R?
            Asked 2020-Oct-17 at 09:33

            A similar question in How to write a double for loop in r with choosing maximal element in one loop?.

            The same setup:

            If I want to sample theta[j] as first for j=1,2,...,71, then draw replicated( like 1000 times) yrep[k] form Bin(n[j], theta[j]), n[j] is known.

            For theta[1], we have yrep[1,1], yrep[1,2], ..., yrep[1,1000]. Then for all theta[j], we will have a matrix of data set of yrep[i,j], i=1,...,71, j=1,..,1000.Then compute mean, max or min of each column yrep[1,1], yrep[1,2], yrep[1,3], ... yrep[1,71], we will get 1000 mean, max or min.

            How to write this for loop?

            I first try to write a loop to sample theta[j] and yrep. I do not know how to add a code to compute the maximal, mean, and minimal in this loop. I am not sure if this code is right:

            ...

            ANSWER

            Answered 2020-Oct-17 at 09:33

            This is not very well tested.
            There is no need for loops to sample from distributions included in base R, those functions are vectorized on their arguments. Code following the lines below should be able to do what the question asks for.

            Source https://stackoverflow.com/questions/64399321

            QUESTION

            How to write a double for loop in r with choosing maximal element in one loop?
            Asked 2020-Oct-16 at 20:24

            I want to sample theta[j] as first for j=1,2,...,71, then draw replicated( like 1000 times) yrep[k] form Bin(n[j], theta[j]), n[j] is known.

            Then for each theta[j], I have 1000 yrep. If I want to choose the maximal element among this 1000 yrep. Finally, I will have 71 maximal elements.

            My for loop in R is as follows:

            ...

            ANSWER

            Answered 2020-Oct-16 at 14:28

            You should provide us some data to work with, i didn't got to test it but i think this works:

            Source https://stackoverflow.com/questions/64390796

            QUESTION

            .in'ig.status: error: cannot find input file: `Makefile
            Asked 2020-Jun-30 at 18:05

            I'm new to GNU and I've been trying to compile a package using Autotools on Mac. After executing the command ./configure, I get the following:

            ...

            ANSWER

            Answered 2020-Jun-30 at 18:05

            Maybe some files in your system should have been converted from using Windows line endings CRNL to using POSIX line endings NL? The extra CR character is causing the cursor to go back to the beginning of the line without a newline, and it's causing the name of your file to be MakefileCR (or, Makefile\r) rather than just Makefile. Obviously the file named Makefile\r.in does not exist.

            Source https://stackoverflow.com/questions/62662905

            QUESTION

            Parsing file with find gives strange results with different files
            Asked 2020-Jun-25 at 22:20

            I tried asking this question before and rightfully was informed I need to provide a fully working example so others can reproduce my result and then give guidance.

            Here is a shortened version of my code for parsing the file. The point of readFileToStrings is to save the file into seperate strings based on the patterns [Atoms], [GTO], and [MO].

            ...

            ANSWER

            Answered 2020-Jun-25 at 22:20

            There is an issue here:

            Source https://stackoverflow.com/questions/62583909

            QUESTION

            Understanding why sapply in R returns vector of longer length
            Asked 2019-Dec-13 at 22:21

            I am parsing through individual lines of code in R to get a better understanding of a large function. While I know sapply apples a function over a vector, I am having trouble understanding what it is doing in a specific instance. Unfortunately, I cannot find a clear explanation on this exact question elsewhere.

            If you simulate data with the sample below code, the variable Y is a vector with 2000 values and calc_sizes is the number of unique values in Y (87 unique values). When sapply is applied to likelihoods it is done in the context of likelihoods[calc_sizes]<-sapply(calc_sizes, nb.likelihood). This returns a vector of 688 values

            What is sapply doing here, and how/why does it return a vector of 688 and not 87?

            To be clear, the code is functioning properly - there is no technical issue. I would just prefer to understand and learn as opposed to blindly writing code that eventually worked (and so I don't have to bug this forum so often).

            You should be able to copy and paste the code verbatim to get the results mentioned. Thank you for any insight!

            ...

            ANSWER

            Answered 2019-Dec-13 at 20:50

            When you do likelihoods[calc_sizes] <- sapply(calc_sizes, nb.likelihood) you are saving the results of sapply(calc_sizes, nb.likelihood) into the vector likelihoods on the positions calc_sizes.

            Since calc_sizes values goes from 1 to 688, R transform likelihoods into a 688 length vector. But if you run table(is.na(calc_sizes)) you will see only 87 positions are not missing.

            Source https://stackoverflow.com/questions/59329449

            QUESTION

            Why optim() always gives me the same result?
            Asked 2019-Nov-11 at 14:51

            I'm trying to use bootstrapping to calculate the confidence interval of MLE of parameter v. But in every iteration, optim() gives me the same result. Why is this happenning?

            Here's my code:

            ...

            ANSWER

            Answered 2019-Nov-10 at 02:11
            > dofloglik = function(v, x) { n <- length(x) 
            +                              loglik <- n*lgamma((v+1)/2) - n*lgamma(v/2)
            +                                        - (n/2)*log(v*pi) - ((v+1)/2)*sum(log(1+x^2/v))
            +                              return(-loglik) }
            > 
            > dofloglik(1, 1:4)
            [1] 2.28946
            > dofloglik(1, 2:5)
            [1] 2.28946
            > dofloglik(1, 3:6)
            [1] 2.28946
            

            Source https://stackoverflow.com/questions/58785122

            QUESTION

            Why is optimization of dmultinom MLE falsely converging in R?
            Asked 2019-Jun-19 at 21:53

            I'm writing a Lincoln-Petersen MLE function in R. I have two versions of my distribution function, one that uses the gamma function, and one that uses Rs internal dmultinom (which uses lgamma). Both return identical results when I plug in sample values, however the dmultinom version fails to provide acceptable MLE estimates. I'm curious as to what is causing this.

            ...

            ANSWER

            Answered 2019-Jun-19 at 21:53

            dmultinom(c(m_2,n_1-m_2,n_2-m_2,N-r),prob=......) is the same as dmultinom(c(m_2,n_1-m_2,n_2-m_2,as.integer(N-r)),prob=......). So a small variation of N does not change this value, because as.integer(N-r) does not change:

            Source https://stackoverflow.com/questions/56673763

            QUESTION

            perl6: why is array skipping calculated values inside declaration?
            Asked 2019-Jan-21 at 21:41

            I am learning Perl6 from Perl5.

            In order to make this compile, I'll post the whole program:

            ...

            ANSWER

            Answered 2019-Jan-21 at 21:41

            (It turned out that this answer completely missed what was ailing @con. But I'll not delete it because it gathers together some hopefully useful links regarding rational numerics.)

            What's wrong?

            why is array skipping calculated values inside declaration?

            It isn't.

            I am learning Perl6 ...

            Numbers like 1.3 are decimals in math and in Perl 6. Some explanations:

            ... from Perl5

            Something about this belongs in one of the Perl 5 to Perl 6 guide docs. Would you be willing to open a new doc issue?

            [1.0/15.0, 10.0/62.0],#this isn't evaluated

            [1.0/10, 2/50.0],#neither is this

            They're all evaluated.

            In math and in P6 a literal 1.0 is a decimal is a rational. foo / bar is also a rational.

            (Well, it is if foo and bar are both integers or rationals and either the denominator of the result remains 64 bits or less or one of foo or bar is an arbitrary precision FatRat rational.)

            However, Perl6 doesn't seem to like values like I have indicated here.

            You haven't explained the situation in which you're seeing something that makes you think P6 doesn't like them.

            A strong possibility is that, per Brad Gilbert++'s comment, you are seeing values like, say, <1/15> instead of 0.066667. The former is a P6 literal value that 100% accurately denotes 1/15. To 100% accurately denote that in decimal the display would have to be 0.06666666666666... with a ... or some such at the end to denote an infinitely repeating final 6. But <1/15> denotes the same number and is shorter and arguably simpler so dd and .perl use the <1/15> form instead.

            How can I get Perl6 to evaluate expressions like this when I'm declaring the 2D array?

            You don't have to do anything. It's evaluating them. :)

            Source https://stackoverflow.com/questions/54203383

            QUESTION

            jq "strptime/1 is not implemented on this platform" when trying to use 'fromdate'
            Asked 2019-Jan-08 at 22:53

            i run jq v1.6 on Windows 10,

            my input is "2009-12-20 08:00:00" and i want to get the Day of Week.

            my test filter is ("2009-12-20 08:00:00" | sub(" "; "T") + "Z" | fromdate | gmtime) but all i get is an error:

            jq: error: strptime/1 not implemented on this platform

            Tried so many things, but nothing worked.

            builtins returns the relevant functions:

            ...

            ANSWER

            Answered 2019-Jan-08 at 22:53

            Here are two alternatives for solving the problem on a Windows 10 machine:

            Install Linux for Windows

            Then, once jq has been installed (e.g. using linuxbrew), you could use this filter:

            Source https://stackoverflow.com/questions/54100199

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install lgamma

            You can download it from GitHub.

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            gh repo clone rachtsingh/lgamma

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