NumberSearch | Line of business tooling for VOIP services | TCP library
kandi X-RAY | NumberSearch Summary
kandi X-RAY | NumberSearch Summary
Lookup available phone numbers for purchase.
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of NumberSearch
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Trending Discussions on NumberSearch
QUESTION
my code is like that..
i m using isNaN()
but problem is still valid
ANSWER
Answered 2021-Feb-21 at 02:04Scroll for answer to edited question.
QUESTION
My code is below. I'm using isNaN()
but the problem is it's still valid
ANSWER
Answered 2021-Feb-17 at 02:17The issue is that sum = sum + Number(str[i])
is being executed even if isNaN(Number(str[i])) === true
because it is outside of the if
block. You need to wrap it inside of the else
block so that it only executes if the previous condition is false.
QUESTION
I have given some data in an array and i am trying to match that with the input given in a text field and if it matches it should display a checkmark and if it does not match it should display a crossmark.
But it either displays checkmark on all the numbers i enter or crossmark. My js code is like this
**
...ANSWER
Answered 2021-Feb-02 at 15:17Once you find your number, you should exit the loop. In the current state of affairs you basically only checking if the last number in the array is similar to the input.
So what you should do is exit the loop once you find a match. Like this:
QUESTION
After searching a while and coming up empty I decided to post in hopes someone can help send me to the right direction.
I am attempting to figure out a way to return a result that contains a hyphen while removing it from the search query. Some items may return multiple hypens
I.E.
Searching
020550407
would return the correct item(s)
-02055-0407
-02055-0407-1
There isn't a pattern to where each item has the hyphen, so it I need to be able to remove it from anywhere in the search query.
I've tried a couple different things, all with no luck.
Examples:
...ANSWER
Answered 2020-Nov-25 at 20:50You were close. This should work:
QUESTION
I have a recyclerview with load more, and I can't store the values in the database. So when I load the data, everything works perfectly. The problem occurs when I navigate to another fragment, and click onBackPressed, the onChanged of the observer is being called again and it is giving me the last values called from the API. Then as you can see in the code below, they are automatically being added to the list and published in UI
...ANSWER
Answered 2020-May-20 at 19:39I think that you are not observing your result
correctly.
For example, if the value of result
is Status.LOADING
what happens? After you enter that block, maybe there are other cases that you are not handling. We don't know because there is no other when
or else if
block.
Another way more "clean" would be:
QUESTION
I have a View with several form that I'm using for searching and displaying the results as partial View in like SearchByNumber, SearchByVehicle, etc.
I'm trying to load view and execute search for different forms by posting link with querystring like www.example.com/Search?number=101010 from different view.
For the first form, SearchByNumber I only have one parameter, string number and i'm returning view with dynamic Model and its working like it should, but I only manage to make search for this form.
Here is my controller:
...ANSWER
Answered 2019-Oct-23 at 14:08At the moment your Model
is only the search string that was entered, which seems rather incomplete. It would make a lot more sense if the Model
also contained the actual search results, which after all is what the user wants to see. And then you can also add the other search properties.
The MVC approach for this is to create a (View)Model class, somewhere in your project, something like this:
QUESTION
How to write a Java program to get a number from user,from that remove odd numbers and display even numbers without using an array(Ex: i/p:2345678, o/p:2468)
I can do with array.
...ANSWER
Answered 2019-Feb-06 at 10:10Parse int input to string, replace all odd digits, and print output (if needed parse back to int):
QUESTION
This is my code to add data from datatable to richtextbox on table format
dt = new DataTable();
SQLiteConnection conn = new SQLiteConnection("Data Source=" + folderPath + "\\" + databaseName);
InitializeComponent();
s = MyProperty.ToString();
conn.Open();
SQLiteCommand command = new SQLiteCommand("SELECT id,nameSearch,dt,totalRecords FROM ACCESSDETAILS Where id=" + s + " AND numberSearch IS NULL AND dt BETWEEN '" + datepicker + "' AND '" + datepicker1+ "'", conn);
SQLiteDataAdapter da = new SQLiteDataAdapter(command);
da.Fill(dt);
conn.Close()
var tab = new Table();
var gridLenghtConvertor = new GridLengthConverter();
tab.Columns.Add(new TableColumn() { Name = "ID", IsEnabled = true, Width = (GridLength)gridLenghtConvertor.ConvertFromString("30") });
tab.Columns.Add(new TableColumn() { Name = "Name", IsEnabled = true, Width = (GridLength)gridLenghtConvertor.ConvertFromString("80") });
tab.Columns.Add(new TableColumn() { Name = "Date", IsEnabled = true, Width = (GridLength)gridLenghtConvertor.ConvertFromString("100") });
tab.Columns.Add(new TableColumn() { Name = "TotalRecords", IsEnabled = true, Width = (GridLength)gridLenghtConvertor.ConvertFromString("auto") });
tab.RowGroups.Add(new TableRowGroup());
int i = 0;
foreach (DataRow dr in dt.Rows)
{
tab.RowGroups[0].Rows.Add(new TableRow());
var tabRow = tab.RowGroups[0].Rows[i];
tabRow.Cells.Add(new TableCell(new Paragraph(new Run(dr.ItemArray[0].ToString() + " | "))));
tabRow.Cells.Add(new TableCell(new Paragraph(new Run(dr.ItemArray[1].ToString() + " | "))));
tabRow.Cells.Add(new TableCell(new Paragraph(new Run(dr.ItemArray[2].ToString() + " | "))));
tabRow.Cells.Add(new TableCell(new Paragraph(new Run(dr.ItemArray[3].ToString()))));
i++;
}
rtf.Document.Blocks.Add(tab);
...ANSWER
Answered 2018-Nov-30 at 09:40You can generate columns when you create datatable. Refer below code as reference for your problem.
QUESTION
I want to have some search boxes on my page and my related codes are like below, my problem is why when i refresh the page the if clause: " if request.method=='GET':" executes without i click on any button ?
...ANSWER
Answered 2018-Mar-08 at 16:45A refresh of a page is a GET
request unless your last action was a POST
request so that is going to execute every time. What you could do is make the form a post and handle in a request.method == 'POST'
block. Another option if you wanted to continute with GET
would be have your view take an optional parameter such as search=None
and set up your urls accordingly. Then in your view you could check for if search
exists instead of request.method == 'GET'
.
QUESTION
function NumberSearch(str) {
var arr = str.split("");
var sum = 0;
var twoDigit = [];
var two;
var res = [];
var arrFormat = preProcess(arr);
console.log(arrFormat);
//this function returns an array that has all numbers from the string
function preProcess(ele) {
for (var i = 0; i < ele.length; i++) {
if (typeof ele[i] === 'number' && typeof ele[i + 1] === 'number') {
twoDigit.push(ele[i], ele[i + 1]);
two = twoDigit.join("");
res.push(two);
} else {
if (typeof ele[i] === 'number' && typeof ele[i + 1] !==
'number') {
res.push(ele[i]);
}
}
}
return res;
}
for (var k = 0; k < arrFormat.length; k++) {
sum = sum + arrFormat[k];
}
return sum;
}
console.log(NumberSearch("99Hello1"));
...ANSWER
Answered 2017-Nov-22 at 20:48You could use a regular expression for matching numbers and reduce the gotten array.
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