standard | This repo is building the .NET Standard | DevOps library
kandi X-RAY | standard Summary
kandi X-RAY | standard Summary
Going forward, the .NET team is using to develop the code and issues formerly in this repository. We do not have plans for new versions of .NETStandard and instead recommend that libraries use the .NET target frameworks like net5.0 and later to get API additions over previous versions of .NETStandard. For more information see
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Top functions reviewed by kandi - BETA
Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of standard
standard Key Features
standard Examples and Code Snippets
// bad
isNaN('1.2'); // false
isNaN('1.2.3'); // true
// good
Number.isNaN('1.2.3'); // false
Number.isNaN(Number('1.2.3')); // true
// bad
isFinite('2e3'); // true
// good
Number.isFinite('2e3'); // false
Number.isFinite(parseInt('2e3', 10)); //
def standard_lstm(inputs, init_h, init_c, kernel, recurrent_kernel, bias,
mask, time_major, go_backwards, sequence_lengths,
zero_output_for_mask):
"""LSTM with standard kernel implementation.
This implementati
def standard_gru(inputs, init_h, kernel, recurrent_kernel, bias, mask,
time_major, go_backwards, sequence_lengths,
zero_output_for_mask):
"""GRU with standard kernel implementation.
This implementation can be ru
def run_standard_tensorflow_server(session_config=None):
"""Starts a standard TensorFlow server.
This method parses configurations from "TF_CONFIG" environment variable and
starts a TensorFlow server. The "TF_CONFIG" is typically a json string
Community Discussions
Trending Discussions on standard
QUESTION
I'm creating a program to analyze security camera streams and got stuck on the very first line. At the moment my .js file has nothing but the import of node-fetch and it gives me an error message. What am I doing wrong?
Running Ubuntu 20.04.2 LTS in Windows Subsystem for Linux.
Node version:
...ANSWER
Answered 2022-Feb-25 at 00:00Use ESM syntax, also use one of these methods before running the file.
- specify
"type":"module"
inpackage.json
- Or use this flag
--input-type=module
when running the file - Or use
.mjs
file extension
QUESTION
I just updated my Android studio to the version 2021.1.1 Canary 12. After struggling to make it work, I had to also upgrade my Gradle and Gradle plugin to 7.0.2. Now I can compile my project and launch my app on my mobile, everything is working. But when I try to generate a Signed APK, I get a strange message after building telling me: APK(s) generated successfully for module 'android-mobile-app-XXXX.app' with 0 build variants:
Even though the build seem to be successful I cannot find the generated APK anywhere (and considering the time it takes to give me that error, I don't even think it is building anything). Now, I have been generating an APK every week for years now, so I know my way around the folders, the different build variant output folders etc... Nothing changed in my way of generating an APK. I do it via AS and follow the very standard procedure.
Can someone point to me what am I missing here? I assume there is a way to select a specific build variant when generating a signed APK, how does it works?
PS: Obviously, I am selecting my variant here during the process:
PS2: I can generate a debug APK without any issue whatsoever.
...ANSWER
Answered 2021-Oct-05 at 07:39After a few days of struggle, I ended up switching to Bundle. It achieves the same purpose for me and it actually works so... That's my solution here.
QUESTION
A standard idiom is
...ANSWER
Answered 2022-Mar-14 at 22:53The boolean conversion operator for std::basic_istream
is explicit
. This means that instances of the type will not implicitly become a bool
but can be converted to one explicitly, for instance by typing bool(infile)
.
Explicit boolean conversion operators are considered for conditional statements, i.e. the expression parts of if
, while
etc. More info about contextual conversions here.
However, a return statement will not consider the explicit
conversion operators or constructors. So you have to explicitly convert that to a boolean for a return
.
QUESTION
Is there a way to obtain the greatest value representable by the floating-point type float
which is smaller than 1
.
ANSWER
Answered 2022-Mar-08 at 23:51You can use the std::nextafter
function, which, despite its name, can retrieve the next representable value that is arithmetically before a given starting point, by using an appropriate to
argument. (Often -Infinity
, 0
, or +Infinity
).
This works portably by definition of nextafter
, regardless of what floating-point format your C++ implementation uses. (Binary vs. decimal, or width of mantissa aka significand, or anything else.)
Example: Retrieving the closest value less than 1 for the double
type (on Windows, using the clang-cl compiler in Visual Studio 2019), the answer is different from the result of the 1 - ε
calculation (which as discussed in comments, is incorrect for IEEE754 numbers; below any power of 2, representable numbers are twice as close together as above it):
QUESTION
I have a single even-sized vector that I want to transform into a vector of pairs where each pair contains always two elements. I know that I can do this using simple loops but I was wondering if there is a nice standard-library tool for this? It can be assumed that the original vector always contains an even amount of elements.
Example:
...ANSWER
Answered 2022-Feb-14 at 14:26There's a quick-and-dirty approach, which will kinda-hopefully-maybe do what you asked for, and will not even copy the data at all... but the downside is that you can't be certain it will work. It relies on undefined behavior, and can thus not be recommended. I'm describing it because I believe it's what one imagines, intuitively, that we might be able to do.
So, it's about using std::span
with re-interpretation of the vector data:
QUESTION
In iOS 15, UITableView
adds a separator between a section header and the first cell:
How can I hide or remove that separator?
A few notes:
- The header is a custom view returned from
tableView(_:viewForHeaderInSection:)
. - When looking at the view debugger, I can see that the extra separator is actually a subview of the first cell, which now has a top and a bottom separator.
- Other than setting
tableView.separatorInset
to change the inset of cell separators, this is a completely standard table view with no customizations.
ANSWER
Answered 2021-Sep-07 at 09:21Option 1:
Maybe by using UITableViewCellSeparatorStyleNone
with the table view and replacing the system background view of the cell with a custom view which only features a bottom line?
Option 2: Using hint from https://developer.apple.com/forums/thread/684706
QUESTION
I know that compiler is usually the last thing to blame for bugs in a code, but I do not see any other explanation for the following behaviour of the following C++ code (distilled down from an actual project):
...ANSWER
Answered 2022-Feb-01 at 15:49The evaluation order of A = B
was not specified before c++17, after c++17 B
is guaranteed to be evaluated before A
, see https://en.cppreference.com/w/cpp/language/eval_order rule 20.
The behaviour of valMap[val] = valMap.size();
is therefore unspecified in c++14, you should use:
QUESTION
Last week, I had a discussion with a colleague in understanding the documentation of C++ features on cppreference.com. We had a look at the documentation of the parameter packs, in particular the meaning of the (optional)
marker:
(Another example can be found here.)
I thought it means that this part of the syntax is optional. Meaning I can omit this part in the syntax, but it is always required to be supported by the compiler to comply with the C++ standard. But he stated that it means that it is optional in the standard and that a compiler does not need to support this feature to comply to the standard. Which is it? Both of these explanations make sense to me.
I couldn't find any kind of explanation on the cppreference web site. I also tried to google it but always landed at std::optional
...
ANSWER
Answered 2021-Aug-21 at 20:22It means that particular token is optional. For instance both these declarations work:
QUESTION
In the following example function f()
returning incomplete type A
is marked as deleted:
ANSWER
Answered 2021-Dec-19 at 10:26Clang is wrong.
[dcl.fct.def.general]
2 The type of a parameter or the return type for a function definition shall not be a (possibly cv-qualified) class type that is incomplete or abstract within the function body unless the function is deleted ([dcl.fct.def.delete]).
That's pretty clear I think. A deleted definition allows for an incomplete class type. It's not like the function can actually be called in a well-formed program, or the body is actually using the incomplete type in some way. The function is a placeholder to signify an invalid result to overload resolution.
Granted, the parameter types are more interesting in the case of actual overload resolution (and the return type can be anything), but there is no reason to restrict the return type into being complete here either.
QUESTION
Following a previous question of mine, most comments say "just don't, you are in a limbo state, you have to kill everything and start over". There is also a "safeish" workaround.
What I fail to understand is why a segmentation fault is inherently nonrecoverable.
The moment in which writing to protected memory is caught - otherwise, the SIGSEGV
would not be sent.
If the moment of writing to protected memory can be caught, I don't see why - in theory - it can't be reverted, at some low level, and have the SIGSEGV converted to a standard software exception.
Please explain why after a segmentation fault the program is in an undetermined state, as very obviously, the fault is thrown before memory was actually changed (I am probably wrong and don't see why). Had it been thrown after, one could create a program that changes protected memory, one byte at a time, getting segmentation faults, and eventually reprogramming the kernel - a security risk that is not present, as we can see the world still stands.
- When exactly does a segmentation fault happen (= when is
SIGSEGV
sent)? - Why is the process in an undefined behavior state after that point?
- Why is it not recoverable?
- Why does this solution avoid that unrecoverable state? Does it even?
ANSWER
Answered 2021-Dec-10 at 15:05When exactly does segmentation fault happen (=when is SIGSEGV sent)?
When you attempt to access memory you don’t have access to, such as accessing an array out of bounds or dereferencing an invalid pointer. The signal SIGSEGV
is standardized but different OS might implement it differently. "Segmentation fault" is mainly a term used in *nix systems, Windows calls it "access violation".
Why is the process in undefined behavior state after that point?
Because one or several of the variables in the program didn’t behave as expected. Let’s say you have some array that is supposed to store a number of values, but you didn’t allocate enough room for all them. So only those you allocated room for get written correctly, and the rest written out of bounds of the array can hold any values. How exactly is the OS to know how critical those out of bounds values are for your application to function? It knows nothing of their purpose.
Furthermore, writing outside allowed memory can often corrupt other unrelated variables, which is obviously dangerous and can cause any random behavior. Such bugs are often hard to track down. Stack overflows for example are such segmentation faults prone to overwrite adjacent variables, unless the error was caught by protection mechanisms.
If we look at the behavior of "bare metal" microcontroller systems without any OS and no virtual memory features, just raw physical memory - they will just silently do exactly as told - for example, overwriting unrelated variables and keep on going. Which in turn could cause disastrous behavior in case the application is mission-critical.
Why is it not recoverable?
Because the OS doesn’t know what your program is supposed to be doing.
Though in the "bare metal" scenario above, the system might be smart enough to place itself in a safe mode and keep going. Critical applications such as automotive and med-tech aren’t allowed to just stop or reset, as that in itself might be dangerous. They will rather try to "limp home" with limited functionality.
Why does this solution avoid that unrecoverable state? Does it even?
That solution is just ignoring the error and keeps on going. It doesn’t fix the problem that caused it. It’s a very dirty patch and setjmp/longjmp in general are very dangerous functions that should be avoided for any purpose.
We have to realize that a segmentation fault is a symptom of a bug, not the cause.
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