BestFriend | Cortana/Voice enabled Bot | Machine Learning library

 by   nmetulev C# Version: Current License: MIT

kandi X-RAY | BestFriend Summary

kandi X-RAY | BestFriend Summary

BestFriend is a C# library typically used in Telecommunications, Media, Advertising, Marketing, Artificial Intelligence, Machine Learning applications. BestFriend has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

Sample UWP app to showcase the speech platform in the Universal Windows Platform including our favorite digital assistant. Detailed blog post here.
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              BestFriend has a low active ecosystem.
              It has 9 star(s) with 5 fork(s). There are 7 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 0 open issues and 1 have been closed. On average issues are closed in 9 days. There are 1 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of BestFriend is current.

            kandi-Quality Quality

              BestFriend has no bugs reported.

            kandi-Security Security

              BestFriend has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              BestFriend is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              BestFriend releases are not available. You will need to build from source code and install.
              Installation instructions are available. Examples and code snippets are not available.

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            BestFriend Key Features

            No Key Features are available at this moment for BestFriend.

            BestFriend Examples and Code Snippets

            No Code Snippets are available at this moment for BestFriend.

            Community Discussions

            QUESTION

            PyQt5 Login to Register Dialog Auto Close
            Asked 2021-Apr-17 at 18:51

            I have a login and register dialog, and of course a main window. So, I want the users to be able to switch between login and register dialog, and if the user enters correct credentials, the user can go to the main window. If the user registered a new credential, then the user will be redirected to the login window. That said, the first interface that the user see is the login dialog. Here are some codes for login-register dialog:

            ...

            ANSWER

            Answered 2021-Apr-17 at 18:28

            The problem is that when a dialog is closed, it exits its event loop (the one launched with exec) with a Rejected result.

            In your case, since the rejection doesn't match window.exec_() == QDialog.Accepted, the result is that that whole block is not evaluated, and the application simply exits.

            A simple solution would be to hide the login until the registration is completed (or rejected) and show it again afterwards.

            Since the login dialog should be shown anyway, there's no need for custom signals or if statements, as it's enough to call the registration dialog's exec_ in the redirect_to_register function, so that you can show again the login no matter the result of the registration.

            Unfortunately, there's a problem with that: in Qt, hiding a dialog results in a behavior similar to closing it (so, rejecting).
            The solution is to avoid the base implementation of QDialog (which overrides both hide() and setVisible()), and use that of QWidget instead:

            Source https://stackoverflow.com/questions/67141170

            QUESTION

            Easy SQL problem i can't solve without IF, ELSE statement in SQL
            Asked 2020-Oct-28 at 07:36

            Here's the deal

            I have two tables. The first one is called "boys"

            ...

            ANSWER

            Answered 2020-Oct-27 at 15:10

            You can left join twice:

            Source https://stackoverflow.com/questions/64557259

            QUESTION

            Fetching all objects of one class with self-referencing ManyToMany
            Asked 2020-Aug-23 at 07:30

            Think of this class:

            ...

            ANSWER

            Answered 2020-Aug-19 at 17:38

            I would create a query in PersonRepository.php with a leftJoin and a addSelect like so:

            Source https://stackoverflow.com/questions/63491266

            QUESTION

            Combining WHEN and LIST with CONTAINS in Kotlin
            Asked 2020-Jun-25 at 22:07

            If I do want to go a party when my girlfriend or my best friend is there, no matter what. If they are not there, I would not go if there was a murderer. But if no murderer is at the party, I would go still if funny Pete is there.

            The following is not valid Kotlin code as I cannot use .contains in this way. What would be a similar clean way of writing this?

            ...

            ANSWER

            Answered 2020-Jun-25 at 22:07

            QUESTION

            Spring Autowired and Builder annotations
            Asked 2020-Apr-02 at 09:59

            I have a spring AppUser class that has an @Autowired annotated field (FriendList) as so:

            ...

            ANSWER

            Answered 2020-Apr-01 at 20:34

            Regarding your @Autowired issue, is fine to use a new operator or a builder, as long as you let spring container manage that new bean for you.

            For example you could do something like:

            Source https://stackoverflow.com/questions/60976452

            QUESTION

            Exclude function types from an object type
            Asked 2019-Oct-03 at 02:21

            In the following excerpt of code:

            ...

            ANSWER

            Answered 2019-Oct-03 at 00:56

            This is one of the listed examples of the Distributive Conditional Types examples on the "Advanced Types" page of the Typescript handbook.

            Conditional types are particularly useful when combined with mapped types:

            Source https://stackoverflow.com/questions/58210331

            QUESTION

            How to insert or set field in Spring JPA?
            Asked 2019-Sep-18 at 06:11

            I have an entity in my service that I'd like to update asynchronously @Async.

            For simplicity sake let it be the following entity:

            ...

            ANSWER

            Answered 2019-Sep-18 at 06:11

            As you can see in the linked answer, to perform an UPSERT in Oracle you need a MERGE clause. You can write a native query or use Java with FluentJPA.

            Source https://stackoverflow.com/questions/57977976

            QUESTION

            Should I assume weak pointer usage if there is any cyclic relationship?
            Asked 2019-Jan-06 at 23:46

            Say I've a Person class, with name, age, and bestFriend as properties. I'm confused about how to best represent bestFriend. Multiple Person instances can be pointing to the same bestFriend, which rules out unique_ptr. And there is also a possibility of a cyclic relationship, which rules out shared_ptr. So, is using weak_ptr ideal in this case? Would I even want to use smart pointers here instead of just raw pointers?

            ...

            ANSWER

            Answered 2019-Jan-06 at 23:46

            Pointers (both raw and smart) express certain ownership. Thus, to pick a proper pointer, you need to decide on the ownership. If something owns an object, then if this something dies, the object has to die too. Does my best friend has to die if I die? I don't think so. Thus, I don't own my best friend. This rules out unique_ptr and shared_ptr, since those are owning smart pointers.

            So we have two choices: weak_ptr or a raw pointer. This depends on how you are going to keep track of alive persons.

            The simplest approach might be to rely on smart pointers to keep track of alive persons. This means, you have some storage of shared_ptr to all persons, and then you store weak_ptr to point to them from another persons. In this case I know that if I have a friend and weak_ptr::lock() returns nullptr, this means my friend is dead. Convenient, but not very flexible. E.g. imagine you need to issue a letter to a family when a person dies. When would you do this? In person's destructor? This would be mix of responsibilities. In a custom deleter of a shared_ptr? That would break encapsulation, since this custom deleter might have many functions.

            Another approach is to keep track of alive persons by a dedicated manager. Again, you need some storage where all persons live. You can store them by value, or via shared_ptr - up to you. Then you store raw pointers to those objects. (Note: if you store them in a vector, which size is an object to change, storing raw pointer to them is not a good idea, because of possible reallocation). In this case you cannot tell by looking on a raw pointer, whether my best friend is still alive or not. We would need to check the manager to get this information. This is more flexible, but I'd say less safe, since we have dangling pointers built-in in our system.

            I'd recommend not to store raw pointers for that's sake, but to go for an ID. Store person's ID instead, and have a registry of persons by ID. This registry will handle all the mess and will properly detect situation, when somebody wants to access a dead person, trigger a post-man to issue a letter to relatives, etc. This also allows to distinguish situations when I don't have a best friend and when my best friend is dead. weak_ptr would return nullptr in both of these situations.

            PS If we were storing shared_ptr to best friends, that would mean a person would be alive only as long as they are someone's best friend... So true, but not in software development world, sorry.

            Source https://stackoverflow.com/questions/54066683

            QUESTION

            Typescript: How to extract only the optional keys from a type?
            Asked 2018-Dec-22 at 22:39

            Let's say I have a type like this:

            ...

            ANSWER

            Answered 2018-Dec-22 at 22:39

            QUESTION

            Rename all other levels to "Other"
            Asked 2018-Dec-12 at 01:08

            I have a dataframe containing all the calls that I have done in the last year. Under the column "Name" there are the names of the people in my contact list. In R this column contains 30 factors, I want to have only 3 factors: Mom, Dad, BestFriend and Others. I'm using this snippet:

            library(plyr) call$Name <- mapvalues(call$Name, from = 'Mikey Mouse', to = 'BFF') call$Name <- mapvalues(call$Name, from = c('Rocky Balboa','Uma Thurman'), to = c('Dad','Mom'))

            How can I rename all other levels aside those 3 to Other?

            ...

            ANSWER

            Answered 2018-Dec-12 at 00:00

            We can first create a level 'Others' (assuming it is a factor), assign the levels that are not %in% the vector of levels ('nm1') to 'Other'

            Source https://stackoverflow.com/questions/53734068

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install BestFriend

            (Note: it may take a small amount of time for Cortana to refresh its installed voice commands.).
            Ensure Cortana is signed in with an MSA account. This can be achieved by opening Cortana once and following the sign-in process.
            Set the API key and botID in BestFriendService/Bot.cs. (I used PersonalityForge bot as it was the fastest)
            Run the application normally once (eg, via F5 debug or deploy/launch). This installs the voice command definitions.
            Close the app.
            Click on the microphone icon in Cortana's search bar.
            Say one of the supported voice commands (see below)

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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            https://github.com/nmetulev/BestFriend.git

          • CLI

            gh repo clone nmetulev/BestFriend

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            git@github.com:nmetulev/BestFriend.git

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