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kandi X-RAY | f2 Summary
F2 is a clean looking responsive theme for WordPress released for free under the [GPL][]. F2 Version 2.0 is completelely rebuilt based on the _s theme.
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QUESTION
I stumbled over the following piece of code. The "DerivedFoo"
case produces different results on MSVC than on clang or gcc. Namely, clang 13 and gcc 11.2 call the copy constructor of Foo
while MSVC v19.29 calls the templated constructor. I am using C++17.
Considering the non-derived case ("Foo"
) where all compilers agree to call the templated constructor, I think that this is a bug in clang and gcc and that MSVC is correct? Or am I interpreting things wrong and clang/gcc are correct? Can anyone shed some light on what might be going on?
Code (https://godbolt.org/z/bbjasrraj):
...ANSWER
Answered 2022-Feb-06 at 21:41It is correct that the constructor template is generally a better match for the constructor call with argument of type DerivedFoo&
or Foo&
than the copy constructors are, since it doesn't require a const
conversion.
However, [over.match.funcs.general]/8 essentially (almost) says, in more general wording, that an inherited constructor that would have the form of a move or copy constructor is excluded from overload resolution, even if it is instantiated from a constructor template. Therefore the template constructor will not be considered.
Therefore the implicit copy constructor of DerivedFoo
will be chosen by overload resolution for
QUESTION
I'm running Kafka schema registry version 5.5.2, and trying to register a schema that contains a reference to another schema. I managed to do this when the referenced schema was in the same package with the referencing schema, with this curl
command:
ANSWER
Answered 2022-Feb-02 at 10:55First you should registrer your other proto to the schema registry.
Create a json (named other-proto.json) file with following syntax:
QUESTION
The following code compiles without warnings in Visual Studio 2019 msvc x64:
...ANSWER
Answered 2022-Jan-18 at 08:13Does this mean that I should have written:
QUESTION
I'm having trouble understanding how/why parentheses work where they otherwise should not work®.
...ANSWER
Answered 2022-Jan-09 at 16:14Note: When referring to documentation and source code, I provide links to an unofficial GitHub mirror of R's official Subversion repository. The links are bound to commit 97b6424 in the GitHub repo, which maps to revision 81461
in the Subversion repo (the latest at the time of this edit).
substitute
is a "special" whose arguments are not evaluated (doc).
QUESTION
I need to create a logger facility that outputs from different places of code to the same or different files depending on what the user provides. It should recreate a file for logging if it is not opened. But it must append to an already opened file.
This naive way such as
...ANSWER
Answered 2021-Dec-13 at 05:54So here is a simple Linux specific code that checks whether a specified target file is open by the current process (using --std=c++17 for dir listing but any way can be used of course).
QUESTION
I'm currently writing a bash script to get the first value among the many comma separated strings. I have a file that looks like this -
...ANSWER
Answered 2021-Dec-10 at 23:00Solution 1: awk
You can use a single awk
command:
QUESTION
#include
int main()
{
auto f1 = [](auto&) mutable {};
static_assert(std::is_invocable_v); // ok
auto const f2 = [](auto&) {};
static_assert(std::is_invocable_v); // ok
auto const f3 = [](auto&) mutable {};
static_assert(std::is_invocable_v); // failed
}
...ANSWER
Answered 2021-Dec-10 at 19:09You get an error for this for the very same reason:
QUESTION
I have a function in Haskell that is defined as follows:
...ANSWER
Answered 2021-Nov-30 at 09:42Haskell values have types. Each value has a type. One type. It can't be two different types at the same time.
Thus, since x
is returned as the result of if
's consequent, the type of the whole if ... then ... else ...
expression is the same as x
's type.
An if
expression has a type. Thus both its consequent and alternative expression must have that same type, since either of them can be returned, depending on the value of the test. Thus both must have the same type.
Since x
is also used in the test, it must be Bool
. Then so must be y
.
QUESTION
I have a function where it is possible to generate a map and a coef_val
value, but I would like to know if it is possible to call this same function and get just the generated value, without plotting the graph? One possibility that I know exists is to make a new function, for example, f2
, without the plotting part, but I wouldn't want to do it this way. Is there another way?
ANSWER
Answered 2021-Nov-20 at 16:52You can redirect the plot to a NULL
file. Relevant section from help(pdf)
:
file: a character string giving the file path. [...] If it is ‘NULL’, then no external file is created (effectively, no drawing occurs) [...]
So, in order to not produce any plot:
QUESTION
I have a website made in ReactJS. In public/index.html
, I have
ANSWER
Answered 2021-Nov-01 at 04:02When you import a script using the
test.mjs:
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