hashmap | A Golang lock-free thread-safe HashMap optimized for fastest read access | Map library
kandi X-RAY | hashmap Summary
kandi X-RAY | hashmap Summary
A Golang lock-free thread-safe HashMap optimized for fastest read access.
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of hashmap
hashmap Key Features
hashmap Examples and Code Snippets
private static void iterateIdentityHashMap(IdentityHashMap identityHashMap) {
// Iterating using entrySet
System.out.println("Iterating values: ");
Set> entries = identityHashMap.entrySet();
for (Map.Entry entry: en
public static IdentityHashMap createWithSimpleData() {
IdentityHashMap identityHashMap = new IdentityHashMap<>();
identityHashMap.put("title", "Harry Potter and the Goblet of Fire");
identityHashMap.put("author", "J. K.
Community Discussions
Trending Discussions on hashmap
QUESTION
I'm making this method with multiple parameters: createExportJob (String testId, Long otherId )
to reduce duplicate code. this example of the method should be the minimum amount of parameters the method should use.
ANSWER
Answered 2021-Mar-03 at 14:28I would do something like this:
QUESTION
I wanna be able to create a hashmap using a javascript object with dynamic keys using useState in react hooks. What I figured so far is that to append a new key value pair, I can just do the following:
...ANSWER
Answered 2021-Jun-14 at 20:00Your second version is close. It will work if map[key]
is already set
But otherwise map[key]
is undefined, and trying to spread [...undefined]
will give you the not iterable error
You can first define the currentValues, and if none use an empty array
QUESTION
I have a recursive structure, where field of a structure is a reference to other struct of same type:
...ANSWER
Answered 2021-Jun-14 at 12:14You are using a &, but want a &mut, rust references are immutable by default: Playground: https://play.rust-lang.org/?version=stable&mode=debug&edition=2018&gist=be82b8ba01dff60e106af9e59df8228e
QUESTION
I'm trying to access each element from a string object and concatenate it with another string:
Current output: from object -> hrsize
...ANSWER
Answered 2021-Jun-14 at 11:15Why don't you simply use a map literal:
QUESTION
I've reviewed several other questions similar to this, but the ones I read didn't help solve my issue. My goal is to print the menu value based on the int user input, and continue offering a selection until the user hits 6 to exit out. Here is my code (I'm new to Java).
...ANSWER
Answered 2021-Jun-13 at 16:23As @user15793316 already said, System.in.read()
does not read the actual number. You can make use of Scanner instead:
QUESTION
All three lines below compiled, are there any differences? If not, is it a good Java practice to always stick to the first one as it has the least amount of code?
...ANSWER
Answered 2021-Jun-13 at 21:40It is totally equivalent rows (see diamond):
QUESTION
I am working with a Java Lib in Kotlin. One (important) function needs a java.util.HashMap as parameter.
In Java most Types are a part of java.lang.Object. Not so in Kotlin, they are part of Any.
I need to put in the HashMap a String Key and Values from type String and int. Like this:
...ANSWER
Answered 2021-Jun-13 at 21:36Any and Object are mapped types. Java code sees every class as a descendent of Object (whether or not it was defined in Kotlin), and Kotlin sees every class as a descendent of Any (whether or not it was defined in Java). When you pass objects from Kotlin to a Java class, they satisfy the Object type requirement.
Kotlin can also refer to the Object type, but it's cleaner not to, or it causes issues like what you ran into. You can use Any to represent the same thing. The Java method that takes it as an argument won't complain. You also don't need to specify java.util.HashMap
because the Kotlin HashMap and Java HashMap are the same class. The Kotlin version is just a typealias
of the Java HashMap.
Your code above is equivalent to:
QUESTION
I have two classes. A film that keeps authors in it. And the author himself. I want to make the connection ManyToMany for them using EntityManager, where then I can get the data for Set.
Class movie:
...ANSWER
Answered 2021-Jun-13 at 19:38I think the Lombok generated hashCode
method is causing an infinite loop as Movie references Authors, each of which references the same instance of Movie.
You can probably confirm this by checking bytecode, or just ditch the @Data
annotation and manually code equals
and hashCode
on Entities.
Alternatively you should be able to break the cycle with an @EqualsAndHashCode.Exclude
annotation on the movies property of Author - https://projectlombok.org/features/EqualsAndHashCode
QUESTION
Was unable to find the solution even after trying many things so posting here hoping to get some workaround or fix for this issue.
Basically, if the @XmlPath(".")
has been used on a Map
and if there is XMLAdapter
on it then it fails during the unmarshalling
. The marshaling
works perfectly only the unmarshalling
fails.
In short, I would like to perform the unmarshalling
as mentioned here but along with Map
I will have one more @XmlElement
. So one field is annotated with (Map field) @XmlPath(".")
and another String field with @XmlElement
and then I would like to perform unmarshalling
.
Following is the XML
that I am trying to unmarshal
:
ANSWER
Answered 2021-Jun-13 at 17:09I was able to get it by using the BeforeMarshal
and AfterMarshal
methods. Posting here so it can be helpful to someone in the future:
QUESTION
I have a Map
field which can contain complex types. The value (Object)
can contain Map, String or ArrayList
my goal is to write a method that can recursively loop over the Map
and create a nested DOM
elements and write into List
. I was able to complete it halfway through it and after that, I am unable to understand how to proceed in the recursive
approach.
Basically, I want my Marshalling
method to handle any complex/nested values such as Map
and String
and create a DOM Element
recursively and store it in List
.
My input Map
can be anything like (can be more nested/complex or simple):
ANSWER
Answered 2021-Jun-13 at 17:06I tried a lot of things and did some research, I was able to get it, posting the answer here as it can be useful to someone in the future:
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