vdk | building streaming services | Video Utils library

 by   deepch Go Version: v0.0.20 License: MIT

kandi X-RAY | vdk Summary

kandi X-RAY | vdk Summary

vdk is a Go library typically used in Video, Video Utils applications. vdk has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

Base Pack thx nareix created JOY4. A set of libraries for building streaming services.
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              vdk has a low active ecosystem.
              It has 326 star(s) with 134 fork(s). There are 16 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              There are 21 open issues and 18 have been closed. On average issues are closed in 74 days. There are 12 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of vdk is v0.0.20

            kandi-Quality Quality

              vdk has no bugs reported.

            kandi-Security Security

              vdk has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              vdk is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              vdk releases are available to install and integrate.

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            vdk Key Features

            No Key Features are available at this moment for vdk.

            vdk Examples and Code Snippets

            No Code Snippets are available at this moment for vdk.

            Community Discussions

            QUESTION

            Recursive value in Dataframe
            Asked 2020-Feb-17 at 20:34

            I have something that has been bugging me for a while.

            I have a Dataframe, looking like this:

            ...

            ANSWER

            Answered 2020-Feb-17 at 20:34

            Let's use cumsum on 'Amount' column:

            Try:

            Source https://stackoverflow.com/questions/60269887

            QUESTION

            How to Change Select Query Value to Text using MySQL?
            Asked 2019-Aug-29 at 01:18

            Take a look at the following query. How do you display Column 'Action' as text. If the result of 'Action' is LEQ 0 then dipslay the text "Crash" and if 'Action' is GRT 0 display the text "Hold"?

            ...

            ANSWER

            Answered 2018-Aug-22 at 21:53

            QUESTION

            MySQL + Adjusting current query to get additional data from another table (per column)
            Asked 2018-Aug-17 at 08:04

            This a new question/update from a previous thread. MySQL + Query to return all rows that have cols that are 'active' in another table

            I am using PHP and MySQL to return some data with a query thank to the help of member @Nick

            I currently need help in tweaking the current query to somehow return substitute data from another table in the rows/data it is currently returning.

            Here are some current examples of what the table set-up is like, and the current query state:

            REXTESTER: http://rextester.com/RZXI72814

            SQL FIDDLE: http://www.sqlfiddle.com/#!9/296b5/3

            It currently works as I outlined in the previous request, but once I put it to use, I realized I missed a requirement, which in hindsight I feel is fairly significant...LOL (sorry)

            Current State: (working as expected) Query that returns all rows from the 'barbot_drinks' table [that has (1-15) ingredients made up of (3 cols each) _dispenser# _code# & _dosage#].. that are EACH found in the barbot_ingredients table AND are active.

            If any of the _dispenser# _code# & _dosage# cols are empty, the whole 'ingredient' is invalid...and empty fields dont count...usually signify the end of the drink recipe (a drink can only have a max of 15 ingredients)

            example: if a drink recipe/entry only has 2 'ingredients' (ingredient_1_dispenser, ingredient_1_code, and ingredient_1_dosage & ingredient_2_dispenser, ingredient_2_code, and ingredient_2_dosage)

            VODKA & OJ

            it checks the ingredients table to see if both VODKA and OJ entries exist in the barbot_ingredients table AND are active.

            So thats where we are now.

            What I need to try and do is get the 'dispenser_order' value from the barbot_ingredients for -EACH- ingredient_x_code column (which could be 1-15 per drink)..for each drink that gets returned. (ie: all ingredients for that paticular drink are found in the ingredients table and are active)

            I am parsing each row and creating a string using PHP from the result set from this query.

            what I am currently creating:

            Example (Screw Drive Drink): (after being parsed by php script)

            bottle=vdk:1,valve=oj:2000

            or (col names)

            [ingredient_1_dispenser]=[ingredient_1_code]:[ingredient_1_dosage],[ingredient_2_dispenser]=[ingredient_2_code]:[ingredient_2_dosage]

            what I need to build is this:

            bottle=1:1,valve=1:2000

            or

            [ingredient_1_dispenser]=[###dispenser_order - FROM_INGREDIENT TABLE THAT MATCHES THIS SETS - = ingredient_1_code###]:[ingredient_1_dosage],[ingredient_2_dispenser]=[###dispenser_order - FROM_INGREDIENT TABLE THAT MATCHES THIS SETS - = ingredient_2_code###]:[ingredient_2_dosage]

            ie: (after being parsed by php script)

            bottle=[###dispenser_order - FROM_INGREDIENT TABLE THAT MATCHES THIS SETS - = ingredient_1_code###]:1,

            valve=[###dispenser_order - FROM_INGREDIENT TABLE THAT MATCHES THIS SETS - = ingredient_2_code###]:2000

            The current is long because of the 1-15 possible column combination, but I also asked for something was easily readable so I can also understand and learn from it.. (like I have so far!)..

            Let me know if there is any other information I can provide, or if I made anything unclear. I wanted to give full background, links to working code, and examples of what I am getting/doing, and what what I -want- get/do.

            ...

            ANSWER

            Answered 2018-Aug-17 at 08:04

            Things are starting to get really messy because the database isn't normalised. This query will give you the results you want. Unfortunately it got too big for SQLFiddle... But rextester seems to handle it - here is the new one.

            Here is the output:

            Source https://stackoverflow.com/questions/51870190

            QUESTION

            How to: MYSQL average from multiple columns excluding Null Values and Changing Number Divided By
            Asked 2018-Aug-02 at 00:44

            Using the following MySQL 5.6 query SELECT sum(col1 + col2 + col3) / 3 AS Result FROM table1

            How can I do the same thing only ignoring NULL values? Also, adjusting the divide by number subtracting the NULL values?

            Our lab uses a sensory panel to asses certain quality points of our product. Each panel member scores -1, 0, or 1 for each sample. For any given sample we can have 1 to 15 scores that they want averaged as 'Result'.

            Reference to Question #24398431

            Below is the Query I just tested. I received no Errors but did not get any data at all returned. I will take all the help I can get.

            ...

            ANSWER

            Answered 2018-Aug-01 at 20:44

            One simple method that is often used in SQL is case statements. You can use a case statement to evaluate col1, col2, and col3 to see if they are null, and then output either the col1/2/3 value (for the numerator), or 1 or 0 for the denominator.

            MySQL may have specific functions to help with this (for example, the case statements could be rewritten with the if function), but case is understood by most RDBMSes.

            Here is an example of how you could do it - I've expanded out the numerator and denominator to make it a little bit clearer what is happening.

            Source https://stackoverflow.com/questions/51639890

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install vdk

            You can download it from GitHub.

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