ditto | A tool for IDN homograph attacks and detection | Computer Vision library
kandi X-RAY | ditto Summary
kandi X-RAY | ditto Summary
Ditto is a small tool that accepts a domain name as input and generates all its variants for an homograph attack as output, checking which ones are available and which are already registered.
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QUESTION
I understand that the middlewares are injected in-between and surrounded by the preceding ditto. At the course of each, we can invoke a call to next() and pass the baton to the succeeding, inwards ware. By that logic, the order might affect the behavior of the application. However, I can't see how the order might cause the chain to be broken (unless an exception occurs or a developer fails to invoke next()).
I noticed that the following order (vanilla weather project) does execute both middlewares.
...ANSWER
Answered 2022-Apr-09 at 09:02The reason is mentioned in your question: "a developer fails to invoke next()", although in this case it’s not a failure as such, as that middleware is essentially the end of the pipeline, if it finds an action to execute.
See the source.
QUESTION
I am trying to create a table (150 rows, 165 columns) in which :
- Each row is the name of a Pokemon (original Pokemon, 150)
- Each column is the name of an "attack" that any of these Pokemon can learn (first generation)
- Each element is either "1" or "0", indicating if that Pokemon can learn that "attack" (e.g. 1 = yes, 0 = no)
I was able to manually create this table in R:
Here are all the names:
...ANSWER
Answered 2022-Apr-04 at 22:59Here is the a solution taking the list of url to webpages of interest, collecting the moves from each table and creating a dataframe with the "1s".
Then combining the individual tables into the final answer
QUESTION
When I run npm start react goes into infinite loop and keeps showing me the same Pokemons again and again. I want to see each pokemon only one time on the screen.
I also got the following error in the console:
...Encountered two children with the same key,
6. Keys should be unique so that components maintain their identity across updates. Non-unique keys may cause children to be duplicated and/or omitted — the behavior is unsupported and could change in a future version
ANSWER
Answered 2022-Apr-04 at 05:18You are doing setState on each iteration of props.pokemonList, React won't batch the state updates in async operations which leads to inifinite re-render.
Try to set the state after resolving all the values using Promise.all
QUESTION
I am trying to find out the number of moves each Pokemon (first generation) could learn.
I found the following website that contains this information: https://pokemondb.net/pokedex/game/red-blue-yellow
There are 151 Pokemon listed here - and for each of them, their move set is listed on a template page like this: https://pokemondb.net/pokedex/bulbasaur/moves/1
Since I am using R, I tried to get the website addresses for each of these 150 Pokemon (https://docs.google.com/document/d/1fH_n_BPbIk1bZCrK1hLAJrYPH2d5RTy9IgdR5Ck_lNw/edit#):
...ANSWER
Answered 2022-Apr-03 at 18:32You can scrape all the tables for each of the pokemen using something like this:
QUESTION
I have an idea for a tensor operation that would not be difficult to implement via iteration, with batch size one. However I would like to parallelize it as much as possible.
I have two tensors with shape (n, 5) called X and Y. X is actually supposed to represent 5 one-dimensional tensors with shape (n, 1): (x_1, ..., x_n). Ditto for Y.
I would like to compute a tensor with shape (n, 25) where each column represents the output of the tensor operation f(x_i, y_j), where f is fixed for all 1 <= i, j <= 5. The operation f has output shape (n, 1), just like x_i and y_i.
I feel it is important to clarify that f is essentially a fully-connected layer from the concatenated [...x_i, ...y_i] tensor with shape (1, 10), to an output layer with shape (1,5).
Again, it is easy to see how to do this manually with iteration and slicing. However this is probably very slow. Performing this operation in batches, where the tensors X, Y now have shape (n, 5, batch_size) is also desirable, particularly for mini-batch gradient descent.
It is difficult to really articulate here why I desire to create this network; I feel it is suited for my domain of 'itemized tabular data' and cuts down significantly on the number of weights per operation, compared to a fully connected network.
Is this possible using tensorflow? Certainly not using just keras. Below is an example in numpy per AloneTogether's request
...ANSWER
Answered 2022-Mar-30 at 07:49All operations you need (concatenation and matrix multiplication) can be batched.
Difficult part here is, that you want to concatenate features of all items in X with features of all items in Y (all combinations).
My recommended solution is to expand the dimensions of X to [batch, features, 5, 1], expand dimensions of Y to [batch, features, 1, 5]
Than tf.repeat() both tensors so their shapes become [batch, features, 5, 5].
Now you can concatenate X and Y. You will have a tensor of shape [batch, 2*features, 5, 5]. Observe that this way all combinations are built.
Next step is matrix multiplication. tf.matmul() can also do batch matrix multiplication, but I use here tf.einsum() because I want more control over which dimensions are considered as batch.
Full code:
QUESTION
private async void btnClickThis_Click(object sender, EventArgs e)
{
//using example code from: https://docs.microsoft.com/en-us/dotnet/api/system.windows.forms.filedialog?view=windowsdesktop-6.0
//to open a file dialog box and allow selection
//variable declaration by section
//file processing
var fileContent = string.Empty;
var filePath = string.Empty;
//counting vowels and storing the word
int vowelMax = 0;
int vowelCount = 0;
String maxVowels = "";
//finding length and storing longest word
int length = 0;
int lengthMax = 0;
String maxLength = "";
//for storing first and last words alphabetically
String first = "";
String last = "";
using (OpenFileDialog openFileDialog = new OpenFileDialog())
{
openFileDialog.InitialDirectory = "c:\\";
openFileDialog.Filter = "txt files (*.txt)|*.txt|All files (*.*)|*.*";
openFileDialog.FilterIndex = 2;
openFileDialog.RestoreDirectory = true;
if (openFileDialog.ShowDialog() == DialogResult.OK)
{
//Get the path of specified file
filePath = openFileDialog.FileName;
//Read the contents of the file into a stream
var fileStream = openFileDialog.OpenFile();
using StreamWriter file = new("Stats.txt", append: true);
using (StreamReader reader = new StreamReader(fileStream))
{
do
{
//try catch in case file is null to begin with
try
{
//read one line at a time, converting it to lower case to start
fileContent = reader?.ReadLine()?.ToLower();
//split line into words, removing empty entries and separating by spaces
var words = fileContent?.Split(' ', StringSplitOptions.RemoveEmptyEntries);
if (words != null)
{
foreach (var word in words)
{
//if the string is null, immediately store word
//if word < first, store word as first
if (first == null || String.Compare(word, first) < 0)
{
first = word;
}
//if the string is null, immediately store word
//if word > last, store word as last
else if (last == null || String.Compare(word, last) > 0)
{
last = word;
}
//find length of current word
length = word.Length;
//if len is greater than current max len, store new max len word
if (length > lengthMax)
{
maxLength = word;
}
//iterate over each letter to check for vowels and total them up
for (int i = 0; i < length; i++)
{
if (word[i] == 'a' || word[i] == 'e' || word[i] == 'i' || word[i] == 'o' || word[i] == 'u')
{
vowelCount++;
}
}
//if vowelCount is greater than max, store word as new max
if (vowelCount > vowelMax)
{
maxVowels = word;
}
await file.WriteLineAsync(word);
}
}
} catch (IOException error)
{
Console.WriteLine("IOException source: {0}", error.Source);
}
} while (fileContent != "");
//append file stats after processing is complete
await file.WriteLineAsync("First word(Alphabetically): " + first);
await file.WriteLineAsync("Last word(Alphabetically): " + last);
await file.WriteLineAsync("Longest word: " + maxLength);
await file.WriteLineAsync("Word with the most vowels: " + maxVowels);
}
}
}
MessageBox.Show(fileContent, "File Content at path: " + filePath, MessageBoxButtons.OK);
}
ANSWER
Answered 2022-Mar-27 at 18:43here you try to find first (min ) word.
QUESTION
This is using Dropwizard's logging with Yaml file and some java.
I wanted to add an instance field in the Dropwizard filename, so that the logs can go handle multiple instances. This was not too difficult. I build a FileAppenderFactory and on buildAppender I just getCurrentLogFilename(), modify it for the instance number, and then setIt. Ditto for the archived name. All well and good.
The problem was when I wanted to add a second file appender (for metrics).
So before I had
...ANSWER
Answered 2022-Mar-24 at 15:24The answer is complex.
For the additive appender (above) the ObjectMapper that is used to do it is created in DiscoverableSubtypeResolver and not in the base deserializer. So you cannot register your factory programatically, but must instead add it to the META-INF\services\io.dropwizard.logging.AppenderFactory file (which you will need to copy from the dropwizard jar and then add your factory).
That will at least get your factory hit (although there are other dropwizard problems that you may encounter, but they are beyond the scope of this question).
QUESTION
I have two lists (variable length) in Excel (1, 2 resp.) and wish to find the union of these:
My research yields numerous solutions / questions to this effect, however, they either focus on Office 365, VB, Lambdas, PowerQuery variations - they do not proivde a function fit for Excel 2010 etc.:
Requirements/research:
- No Office 365 requirement (so no FilterXML, let, choose, etc. etc. - per here, here, here)
- Am not interested in VB (trivial) / PowerQuery (ditto - i.e. simple 'insert/data/append 2 or more queries)
- Am not interested in Lambda variations (per here)
- Duplicates are fine
Progress
Have been contemplating an offset function that picks up values in the 2nd list once those in the first list are exhausted in an array function -- but am a litte lost otherwise (and don't want to restrict anyone in scope of functions that may be avail. in this regard).
Can someone assist me in finding a function per above pls?
...ANSWER
Answered 2022-Mar-01 at 22:32Using INDEX/MATCH:
QUESTION
My project was built long ago using Microsoft.Azure.Storage.Blob and I have many containers with many files. I am not sure how it happened but all of my folder structures have a leading slash in them. This has not been an issue until I try to upgrade my code to Azure.Blobs (v12).
When I look at my blobs in the Azure Portal, it shows a blank / in the root folder, and browsing down I see it looks like this
[container] / / [first folder] / [second folder] / [filename]
Azure portal has not problem showing a file and downloading it. When I look at properties, the URL looks like https://[account].blob.core.windows.net/[container]//folder1/folder2/file.ext
After updating my code, I find that container.GetBlobClient([folder+filename]) will not retrieve any files. It always gets a 404. When I look in debugger to see what URL it is trying to access, it is eliminating the double slash so it looks like https://[account].blob.core.windows.net/[container]/folder1/folder2/file.ext
I have tried prepending a slash to the [folder+filename] but it always strips it out. Ditto for prepending two slashes.
I have been googling all day and cannot find an answer here. Is there a workaround to this? I am thinking there has to be because both the Azure Portal and Cloudberry Explorer can access and download my blobs.
...ANSWER
Answered 2022-Mar-01 at 05:36One possible workaround is to create an instance of BlobClient using the full URL of the blob. That way the leading slashes are preserved.
Please take a look at the code below. It makes use of Azure.Storage.Blobs version 12.10.0.
QUESTION
If you want to see this project running you can see the codesandbox in here.
I have a Landing component calling a ReturnPokemon component passing a string as props.
The ReturnPokemon component receives two arrays and sends back the array accordingly with the props it's receiving.
Now the Landing component has a console.log for the information that it is receiving from ReturnPokemon.
The problem with the code is Landing is not receiving the same array that ReturnPokemon receives, why is that? I need that ReturnPokemon send to Landing the same array it is receiving. How can I fix the code?
Landing:
ANSWER
Answered 2022-Feb-27 at 17:23It looks like you are trying to use a React component as if it were a React hook.
My suggestion would be to re-write as a React hook and then you should be able to correctly log the chosen pokemon:
Landing Becomes:
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