pinkerton | Archived -- see https : //github.com/flynn/flynn | Telnet library

by flynn-archive Go Version: Current License: Non-SPDX

X-Ray Key Features Code Snippets Community Discussions(4)Vulnerabilities Install Support

kandi X-RAY | pinkerton Summary

pinkerton is a Go library typically used in Networking, Telnet applications. pinkerton has no bugs, it has no vulnerabilities and it has low support. However pinkerton has a Non-SPDX License. You can download it from GitHub.

Archived -- see

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Reuse

Support

pinkerton has a low active ecosystem.

It has 28 star(s) with 3 fork(s). There are 5 watchers for this library.

It had no major release in the last 6 months.

pinkerton has no issues reported. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of pinkerton is current.

Quality

pinkerton has no bugs reported.

Security

pinkerton has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

License

pinkerton has a Non-SPDX License.

Non-SPDX licenses can be open source with a non SPDX compliant license, or non open source licenses, and you need to review them closely before use.

Reuse

pinkerton releases are not available. You will need to build from source code and install.

Top functions reviewed by kandi - BETA

kandi has reviewed pinkerton and discovered the below as its top functions. This is intended to give you an instant insight into pinkerton implemented functionality, and help decide if they suit your requirements.

Add adds a new image to the store
main is the main function .
NewRef creates a new reference
New creates a new Store
parseEndpoints parses a comma separated list of endpoints .
log file

Get all kandi verified functions for this library.

pinkerton Key Features

No Key Features are available at this moment for pinkerton.

pinkerton Examples and Code Snippets

No Code Snippets are available at this moment for pinkerton.

Community Discussions

Trending Discussions on pinkerton

SQL recursive level 1 supervisee staff

How to get the respective JSON object based on id

JSLINQ - Distinct from multiple columns

SQL AVG Salary recursive Query

QUESTION

SQL recursive level 1 supervisee staff

Asked 2018-Sep-09 at 20:35

I am stack again. I want to get all the supervisors who supervise staff less than 1.

In my result I miss one supervisor so I think my Query is wrong.

...

ANSWER

Answered 2017-Jan-06 at 16:57

This is pretty simple actually. In your source data, there are no employees with a supervisorFk value of 48, so Supervisor #48 (Carol Moore) has no employees. Since you're doing an INNER JOIN based on that foreign key, that record is never in the initial set. You don't even make it to the HAVING clause of COUNT(*)=1 - the user isn't there to be counted.

Change that to a LEFT JOIN and make your COUNT(*)<=1, or add a record that has a supervisorFk of 48 and then you'll see the user.

Source https://stackoverflow.com/questions/41509625

QUESTION

How to get the respective JSON object based on id

Asked 2018-Mar-07 at 18:43

how to get the respective nested JSON object based on Id. For example below is my complete JSON.

...

ANSWER

Answered 2018-Mar-07 at 18:43

You can use a recursive algorithm to look for an object in the current array as well as the nested ones.

Source https://stackoverflow.com/questions/49158513

QUESTION

JSLINQ - Distinct from multiple columns

Asked 2017-Mar-24 at 17:51

I have a working JSFiddle demo https://jsfiddle.net/u1fohjxw/

The idea is to create a unique list of items, based on multiple fields. I know the way I've implemented it could be improved, but need advice on doing it in JSLINQ.

This filtered unique list I then manually loop and add again - this could be done in JSLINQ.

Please indicate how this should be done :

...

ANSWER

Answered 2017-Mar-24 at 17:51

how you doing? :)

Maybe something like this helps you out:

Source https://stackoverflow.com/questions/42244026

QUESTION

SQL AVG Salary recursive Query

Asked 2017-Jan-07 at 20:47

in the first Query I get the staffs who leads other staff and in the second I wanne get the avg salary of staffs who earns more than the avarage. But I wanne combine both to get the managers who earns more than twice of the salary than the avg salary of the staffs who works for them.

...

ANSWER

Answered 2017-Jan-07 at 20:47

You are selecting the managers that earn more than half of the average.

Source https://stackoverflow.com/questions/41525576

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install pinkerton

You can download it from GitHub.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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