radicals | RADKFILE/KRADFILE parsers | Parser library

 by   gojp Go Version: Current License: Apache-2.0

kandi X-RAY | radicals Summary

kandi X-RAY | radicals Summary

radicals is a Go library typically used in Utilities, Parser applications. radicals has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

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            kandi-support Support

              radicals has a low active ecosystem.
              It has 6 star(s) with 0 fork(s). There are 5 watchers for this library.
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              It had no major release in the last 6 months.
              radicals has no issues reported. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of radicals is current.

            kandi-Quality Quality

              radicals has no bugs reported.

            kandi-Security Security

              radicals has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              radicals is licensed under the Apache-2.0 License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              radicals releases are not available. You will need to build from source code and install.

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            radicals Key Features

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            radicals Examples and Code Snippets

            No Code Snippets are available at this moment for radicals.

            Community Discussions

            QUESTION

            code for extracting numbers outside parenthesis doesn't work
            Asked 2021-Jun-14 at 20:52

            I'm trying to write a simple program that extracts the numbers and operands outside the last pair of parenthesis, i'm trying to achieve this by employing a simple recursive function, however, my code is printing nothing. What's wrong with the code?

            ...

            ANSWER

            Answered 2021-Jun-14 at 20:52

            The problem is with the wrong stopping condition which is leading to an infinite recursion in this line if(x[y] != '('){. You just need to put that condition in the end or you can ignore it all.

            Source https://stackoverflow.com/questions/67976927

            QUESTION

            How to parse a special JSON format to JavaScript object?
            Asked 2020-Nov-22 at 12:01

            I have been searching for an answer to this specific kind of format, but was not able to find any to solve this specific issue.

            The situation is, I have a kind of JSON format that I can't work with in combination with mongoDB. I wish to alter the format of the JSON data to a normal JavaScript object. Now the data is over 2,000 entries long, so I can't handle it manually. And I couldn't make the JSON.parse(data) work for this kind of special format.

            Here an example of the current JSON format:

            ...

            ANSWER

            Answered 2020-Nov-22 at 11:50

            Both are actually valid JSON objects, although you are looking for a simple manipulation:

            Source https://stackoverflow.com/questions/64953739

            QUESTION

            How to filter pandas dataframe based on hue and col categories in seaborn catplot?
            Asked 2020-Sep-15 at 18:37

            I am not able to take (let say) top 10 categories of my feature in hue as well as col parameter using catplot graph in seaborn.

            ...

            ANSWER

            Answered 2020-Sep-15 at 18:37
            1. col_feature and hue_feature are strings, and a string can't be used for . notation when accessing a dataframe column.
              • data.col_feature is equivalent to data.'nationality' and won't work
              • Use data[col_feature] which is equivalent to data['nationality']
            2. The col parameter expects a column name, col='nationality', not an array of values from inside the column.
              • data[col_feature].value_counts()[:10].index can't be used
            3. The hue parameter also expects a column name, 'hue='group', not an array.
              • data[hue_feature].value_counts()[:10].index can't be used
            • Any type of feature selection should happen to the dataframe before it is sent to catplot.

            Source https://stackoverflow.com/questions/63874346

            QUESTION

            Remove duplicate but add score in google sheets query and group with just 1 of 2 teamnames
            Asked 2020-Jul-02 at 10:57

            I have a small issue where I use a query function in Google sheets to display a score of drivers that are mostly also in a team. I use a separate Data sheet for it to enter the scores and all details.

            The query function in my case should select certain columns to display in a different tab. It does that perfectly, but one of the names in there changed teams. This means I had to add the person a second time in the data table with a different team name so the team scores don't get mixed up.

            Now I would like the query function to display this person only once in combination with his latest team name (I put that above the old team name in the data table) and add the scores of both to make a driver points score and a legit team score.

            Long story short, this is what the function looks like and it should not display this extra rule without messing up the other points in there.

            ...

            ANSWER

            Answered 2020-Jul-02 at 10:57
            Solution

            According to your request of solving this using preferrably Google Sheet formulas rather than Apps Script, I have developed a possible solution/workaround in the fewer amount of steps I could.

            To achieve what you aimed here (only display unique members according to their names), I was not able to use query but rather a series of formulas that led me to a similar solution as if you would have used query.

            1. Filter the names to only display a list of the unique members (no duplicate names) so that we don't have twice the same person (in the image showing the solution, this formula is implemented in B2):

            =unique(filter('Championship Data'!B4:B952;NOT(ISBLANK('Championship Data'!O4:O952))))

            1. Get the row index of the names obtained (i.e the row numbers they are in) to then get the rest of the column information we are interested in (implemented in A2 and then dragged all the way down until we cover all the names):

            =MATCH(B2;'Championship Data'!$B$4:$B$952;0)+3

            1. In the columns C, D and E we will use this row index along with the column we want to get the information from in the sheet Championship Data to get the right values from the other sheet (and then just drag all the way down until we cover all the names):

            Car number : =INDEX('Championship Data'!$A$1:$O$952;A2;3)

            Team : =INDEX('Championship Data'!$A$1:$O$952;A2;4)

            Total : =INDEX('Championship Data'!$A$1:$O$952;A2;15)

            1. Finally, using the table we just created, we apply two sort functions for the columns of names and total to order them accordingly:

            =SORT(SORT(B2:E34;1;TRUE);4;FALSE)

            NOTE : To place the right total value to Manuel, I have had to add these points in the first table created as otherwise it would be practically impossible to change his score (unless we change it manually or with a script). To do so I changed the cell E3 to this: =INDEX('Championship Data'!$A$1:$O$952;A3;15)+20

            I hope this has helped you. Let me know if you need anything else or if you did not understood something. :)

            Source https://stackoverflow.com/questions/62613615

            QUESTION

            how to query a specific string from a list of string in Android RoomDB
            Asked 2020-Apr-28 at 21:13

            Is it possible to query a specific string from a list of string in an Entity in RoomDB?

            here is my Entity

            ...

            ANSWER

            Answered 2020-Apr-28 at 21:13

            You can use LIKE (same like contains() method) instead of ==

            for example

            Source https://stackoverflow.com/questions/61489914

            QUESTION

            Matlab Nested Radicals
            Asked 2018-Jan-30 at 14:24

            Working on an assignment in MATLAB and I can't seem to figure this problem out due to the arithmetic, I've been trying it for about 6 hours now

            I need to create a loop that accepts user input > 1 (done) and loops through the following (m is input)

            ...

            ANSWER

            Answered 2018-Jan-30 at 14:24

            I'm not sure what you're trying to do with the sqrts variable, you should be calculating each step on the fly in your loop, since you can't possibly know how deep you need to go

            Source https://stackoverflow.com/questions/48522283

            QUESTION

            Solving rational inequalities in sympy
            Asked 2018-Jan-19 at 13:15

            I am new to sympy but want to solve the following problem:

            I have multiple inequality constraints of the form

            ...

            ANSWER

            Answered 2018-Jan-19 at 13:15

            I just messed up rational functions with polynomials. What I was searching for was solve_poly_inequalities:

            Source https://stackoverflow.com/questions/48266247

            QUESTION

            How can I create new lists in a loop and name them so I can fill them up with items from another list using Python?
            Asked 2017-Oct-13 at 16:20

            I made a double for loop that first takes a word from a list of radicals and then iterates through the same list looking for similar words (with a ratio of 70%). What I need is that each time the first loop takes a word from the list, it creates a new list containing the word + those that were chosen by the second loop that are similar.

            I tried a lot with lists comprehensions but I can't figure out how to put the words from the second loop into the new list. I thought it could work if each list created had an index (x). Here's my code :

            ...

            ANSWER

            Answered 2017-Oct-13 at 16:20

            I think you need something like this

            Source https://stackoverflow.com/questions/46732617

            QUESTION

            How can I remove unwanted characters from a words list and put them cleared in another list using Python?
            Asked 2017-Oct-13 at 10:02

            I'm new in Python and working on a lexicon database. I have three lists : the first one contains several words from the database I want to test, the second one contains prefixes and the third one contains suffixes. I need to make another list (called "radicals") that would contain the words from the first list that matched with the two other lists but with their prefixes or suffixes removed.

            I'm sure I'm not using the right method here but here's my code :

            ...

            ANSWER

            Answered 2017-Oct-13 at 09:59

            What you want is to iterate over each word and remove any defined prefix or suffix. That's it. And since some radicals will be the same, e.g., for fleur and fleuriste, use a set.

            Source https://stackoverflow.com/questions/46726862

            QUESTION

            MatLab not formating doubles as expected in matrix
            Asked 2017-Oct-12 at 12:58

            I am solving a system of linear equations. I want to output the variables with their respective solutions, displaying decimals (a double).

            ...

            ANSWER

            Answered 2017-Oct-12 at 12:58

            Using vpa before concatenation:

            Source https://stackoverflow.com/questions/46710064

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

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            Install radicals

            You can download it from GitHub.

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