radicals | RADKFILE/KRADFILE parsers | Parser library
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QUESTION
I'm trying to write a simple program that extracts the numbers and operands outside the last pair of parenthesis, i'm trying to achieve this by employing a simple recursive function, however, my code is printing nothing. What's wrong with the code?
...ANSWER
Answered 2021-Jun-14 at 20:52The problem is with the wrong stopping condition which is leading to an infinite recursion in this line if(x[y] != '('){
. You just need to put that condition in the end or you can ignore it all.
QUESTION
I have been searching for an answer to this specific kind of format, but was not able to find any to solve this specific issue.
The situation is, I have a kind of JSON format that I can't work with in combination with mongoDB. I wish to alter the format of the JSON data to a normal JavaScript object. Now the data is over 2,000 entries long, so I can't handle it manually. And I couldn't make the JSON.parse(data) work for this kind of special format.
Here an example of the current JSON format:
...ANSWER
Answered 2020-Nov-22 at 11:50Both are actually valid JSON objects, although you are looking for a simple manipulation:
QUESTION
I am not able to take (let say) top 10 categories of my feature in hue
as well as col
parameter using catplot
graph in seaborn.
ANSWER
Answered 2020-Sep-15 at 18:37- As per
seaborn.catplot
col_feature
andhue_feature
are strings, and a string can't be used for.
notation when accessing a dataframe column.data.col_feature
is equivalent todata.'nationality'
and won't work- Use
data[col_feature]
which is equivalent todata['nationality']
- The
col
parameter expects a column name,col='nationality'
, not an array of values from inside the column.data[col_feature].value_counts()[:10].index
can't be used
- The
hue
parameter also expects a column name,'hue='group'
, not an array.data[hue_feature].value_counts()[:10].index
can't be used
- Any type of feature selection should happen to the dataframe before it is sent to
catplot
.
QUESTION
I have a small issue where I use a query function in Google sheets to display a score of drivers that are mostly also in a team. I use a separate Data sheet for it to enter the scores and all details.
The query function in my case should select certain columns to display in a different tab. It does that perfectly, but one of the names in there changed teams. This means I had to add the person a second time in the data table with a different team name so the team scores don't get mixed up.
Now I would like the query function to display this person only once in combination with his latest team name (I put that above the old team name in the data table) and add the scores of both to make a driver points score and a legit team score.
Long story short, this is what the function looks like and it should not display this extra rule without messing up the other points in there.
...ANSWER
Answered 2020-Jul-02 at 10:57According to your request of solving this using preferrably Google Sheet formulas rather than Apps Script, I have developed a possible solution/workaround in the fewer amount of steps I could.
To achieve what you aimed here (only display unique members according to their names), I was not able to use query but rather a series of formulas that led me to a similar solution as if you would have used query.
- Filter the names to only display a list of the unique members (no duplicate names) so that we don't have twice the same person (in the image showing the solution, this formula is implemented in
B2
):
=unique(filter('Championship Data'!B4:B952;NOT(ISBLANK('Championship Data'!O4:O952))))
- Get the row index of the names obtained (i.e the row numbers they are in) to then get the rest of the column information we are interested in (implemented in
A2
and then dragged all the way down until we cover all the names):
=MATCH(B2;'Championship Data'!$B$4:$B$952;0)+3
- In the columns
C
,D
andE
we will use this row index along with the column we want to get the information from in the sheetChampionship Data
to get the right values from the other sheet (and then just drag all the way down until we cover all the names):
Car number : =INDEX('Championship Data'!$A$1:$O$952;A2;3)
Team : =INDEX('Championship Data'!$A$1:$O$952;A2;4)
Total : =INDEX('Championship Data'!$A$1:$O$952;A2;15)
- Finally, using the table we just created, we apply two
sort
functions for the columns of names and total to order them accordingly:
=SORT(SORT(B2:E34;1;TRUE);4;FALSE)
NOTE : To place the right total value to Manuel, I have had to add these points in the first table created as otherwise it would be practically impossible to change his score (unless we change it manually or with a script). To do so I changed the cell
E3
to this:=INDEX('Championship Data'!$A$1:$O$952;A3;15)+20
I hope this has helped you. Let me know if you need anything else or if you did not understood something. :)
QUESTION
Is it possible to query a specific string from a list of string in an Entity in RoomDB?
here is my Entity
...ANSWER
Answered 2020-Apr-28 at 21:13You can use LIKE
(same like contains() method) instead of ==
for example
QUESTION
Working on an assignment in MATLAB and I can't seem to figure this problem out due to the arithmetic, I've been trying it for about 6 hours now
I need to create a loop that accepts user input > 1 (done) and loops through the following (m is input)
...ANSWER
Answered 2018-Jan-30 at 14:24I'm not sure what you're trying to do with the sqrts
variable, you should be calculating each step on the fly in your loop, since you can't possibly know how deep you need to go
QUESTION
I am new to sympy but want to solve the following problem:
I have multiple inequality constraints of the form
...ANSWER
Answered 2018-Jan-19 at 13:15I just messed up rational functions with polynomials. What I was searching for was solve_poly_inequalities
:
QUESTION
I made a double for loop that first takes a word from a list of radicals and then iterates through the same list looking for similar words (with a ratio of 70%). What I need is that each time the first loop takes a word from the list, it creates a new list containing the word + those that were chosen by the second loop that are similar.
I tried a lot with lists comprehensions but I can't figure out how to put the words from the second loop into the new list. I thought it could work if each list created had an index (x). Here's my code :
...ANSWER
Answered 2017-Oct-13 at 16:20I think you need something like this
QUESTION
I'm new in Python and working on a lexicon database. I have three lists : the first one contains several words from the database I want to test, the second one contains prefixes and the third one contains suffixes. I need to make another list (called "radicals") that would contain the words from the first list that matched with the two other lists but with their prefixes or suffixes removed.
I'm sure I'm not using the right method here but here's my code :
...ANSWER
Answered 2017-Oct-13 at 09:59What you want is to iterate over each word and remove any defined prefix or suffix. That's it. And since some radicals will be the same, e.g., for fleur and fleuriste, use a set
.
QUESTION
I am solving a system of linear equations. I want to output the variables with their respective solutions, displaying decimals (a double).
...ANSWER
Answered 2017-Oct-12 at 12:58Using vpa
before concatenation:
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