wharf | quickly transfer software builds

by itchio Go Version: Current License: MIT

X-Ray Key Features Code Snippets Community Discussions(10)Vulnerabilities Install Support

kandi X-RAY | wharf Summary

wharf is a Go library typically used in Networking applications. wharf has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

wharf is a protocol for incrementally transferring software builds over the network using minimal time/bandwidth. It is used in production at to allow creators to quickly iterate & players to keep their library always up-to-date. This repository contains the reference golang implementation of the wharf protocol, along with the reference protobuf definition files.

Support

Quality

Security

License

Reuse

Support

wharf has a low active ecosystem.

It has 143 star(s) with 11 fork(s). There are 8 watchers for this library.

It had no major release in the last 6 months.

There are 4 open issues and 8 have been closed. On average issues are closed in 7 days. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of wharf is current.

Quality

wharf has no bugs reported.

Security

wharf has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

License

wharf is licensed under the MIT License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

wharf releases are not available. You will need to build from source code and install.

Installation instructions are not available. Examples and code snippets are available.

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wharf Key Features

No Key Features are available at this moment for wharf.

wharf Examples and Code Snippets

No Code Snippets are available at this moment for wharf.

Community Discussions

Trending Discussions on wharf

Can re ignore a lazy quantifier?

Sticky navbar won't show up properly

React.js + axios: How do I avoid hard coding data on my datatable?

If and Loop function to extract data

img.height problem (returning 0 everytime)

When running my Kafka consumer in local, it is only consuming half of the message

how to use boundary with str_detect (tidyr package)

NameError instance of WindowManager is not defined kivy

How do I write a Mongoose Schema for an object containing an array of arrays?

Issue during installation of RubyEncoder CLI mode

QUESTION

Can re ignore a lazy quantifier?

Asked 2020-Oct-11 at 18:50

Given this code (Python 3.6):

...

ANSWER

Answered 2020-Oct-11 at 18:50

The lazy flag isn't being ignored.

You get a match on the entire string because .+? means match anything one or more times until you find a match, expanding as needed. If the regex was $[^)]+?$$ it would have matched only the last (wharf) because we excluded the +? from matching )

Or if the regex was $.+?$, it would have matched the (canary) and the (wharf), which shows that it's being lazy.

$.+?$$ matches everything because you make it match everything until the end of the line.

If you want to ensure that there is only one group in parentheses in the entire string, we can do that with our "no-parentheses-regex" from above and force the start of the string to match the start of your regex.

^$[^)]+?$$
Try it: https://regex101.com/r/Ts9JeF/1

Explanation:

^\(: Match a literal ( at the start of the string
[^)]+?: Match anything but ), as many times as needed
\)$: Match a literal )$ at the end of the line.

Or, if you want to allow other words before and after the one in parentheses, but nothing in parentheses, do this:

^[^()]*?$[^)]+?$[^()]*$
Try it: https://regex101.com/r/Ts9JeF/3

Explanation:

^[^()]*?: At the start of the string, match anything but parentheses zero or more times.
$[^)]+?$: Very similar to our previous regex
[^()]*$: Match zero or more non-parentheses characters until the end of the string.

Source https://stackoverflow.com/questions/64307384

QUESTION

Sticky navbar won't show up properly

Asked 2020-Jun-15 at 12:26

I'm building a navigation bar, but I'm having trouble displaying the sticky part properly.

As you can see, it shows up, but the menu items are moved to the left, and the background isn't full-width. Basically what I'd like to do is when I scroll, the full navigation part of the header Where the menu items are) should appear.

https://codepen.io/dtommy79/pen/yLeayMW

...

ANSWER

Answered 2020-Jun-15 at 12:24

Add left: 0; and right: 0; to .sticky-header will solve your problem? I hope I understand your problem.

Source https://stackoverflow.com/questions/62388032

QUESTION

React.js + axios: How do I avoid hard coding data on my datatable?

Asked 2020-Mar-20 at 08:35

I'm still new to React and I'm using this library called axios to do API calls.

I had success on fetching login data for my web app. However, I'm having a hard time applying it onto a datatable.

Here is the code:

ClientMaintancePage.js

...

ANSWER

Answered 2020-Mar-20 at 08:32

You need useEffect to setData upon load of page

Source https://stackoverflow.com/questions/60769774

QUESTION

If and Loop function to extract data

Asked 2020-Mar-17 at 11:52

In the sample dataset above, I am trying to use the VBA's If function to look for a specific keyword, and if there's a match, I would want to extract the Name itself, alongside its Serial Number and Product, and add to the last row of another worksheet, within the same workbook.

For instance, If in column C, we detect, say, cana (note that this is not an exact match, but good enough), then I would want VBA to help me to extract Canary Wharf, its Serial Number and Product next to it, which are 8273615 and Canned Food, to the end of another worksheet, and the loop goes on until the end of Canary Wharf and moves on to Riverdale, which I would type, say, riverd, and repeat the same process. The x's are there to signify that I have a rather large dataset, nothing else.

I have gotten some clues with the top answer found in Using "If cell contains" in VBA excel , it is of great help, but I could not quite get the exact thing to do. Any help would be very much appreciated!

Below should be the intuition:

...

ANSWER

Answered 2020-Mar-17 at 06:31

You can do something like this:

Source https://stackoverflow.com/questions/60716410

QUESTION

img.height problem (returning 0 everytime)

Asked 2020-Mar-14 at 15:20

i have the following html code:

...

ANSWER

Answered 2020-Mar-14 at 13:41

Onload is called after the height is printed before the image is actually loaded hence the reason for zero height.

Source https://stackoverflow.com/questions/60683296

QUESTION

When running my Kafka consumer in local, it is only consuming half of the message

Asked 2020-Mar-05 at 10:09

This is the topic created -

...

ANSWER

Answered 2020-Mar-05 at 07:27

The default size of a message produced in Kafka is 1 MB. If the message is greater than the size you can incur data loss.

To increase the size of your message, set the following configuration: message.max.bytes and allocate the size of message you want to produce and consume.

Also, set the following configuration max.partition.fetch.bytes in your consumer to fetch the size of messages you want to receive.

You can also read more about these configurations in this link: https://kafka.apache.org/documentation/#brokerconfigs

Source https://stackoverflow.com/questions/60539908

QUESTION

how to use boundary with str_detect (tidyr package)

Asked 2020-Feb-11 at 16:24

Here is some data.

...

ANSWER

Answered 2020-Feb-11 at 16:24

We can specify the word boundary (\\b) at the start and end to avoid any partial matches

Source https://stackoverflow.com/questions/60173214

QUESTION

NameError instance of WindowManager is not defined kivy

Asked 2020-Feb-08 at 12:57

I'm getting a NameError saying the instance of my WindowManager isn't defined but I am defining it in the build class sm = WindowManager(). This used to work but now throws this error and I can't see what's been changed.

When the user logs in it should transfer them to the information page but instead the app is crashing.

Error

...

ANSWER

Answered 2020-Feb-08 at 12:57

First, you have to keep a reference to your ScreenManager in the MyApp class with self.sm = WindowManager(), and use the self.sm instead of the sm.

You can then access it from the py using App.get_running_app().sm, and from the kv using app.sm

Source https://stackoverflow.com/questions/60126786

QUESTION

How do I write a Mongoose Schema for an object containing an array of arrays?

Asked 2019-Dec-13 at 14:36

I'm trying to build a Mongoose schema for a relatively simple type. An example object coming out of mongo looks like this:

...

ANSWER

Answered 2019-Dec-13 at 14:36

why didn't you try this

Source https://stackoverflow.com/questions/59324551

QUESTION

Issue during installation of RubyEncoder CLI mode

Asked 2019-Aug-13 at 02:08

I am using RubyEncoder to encrypt my ruby application code and its working fine. But now we are providing on premise solution for our application. So we are creating image using packer. So we need to install RubyEncoder in that image so we can encrypt our code. But facing issue in installation of RubyEncoder.

Below is my ansible playbook:

...

ANSWER

Answered 2019-Aug-13 at 02:08

As Vladimir mentioned you can use the expect module. I have a working example below, but there are a few things to keep in mind:

You need to have the pexpect library installed
For some reason the return code from rubyencode after successfully accepting the license is 9, so this needs to be handled properly (anything other than a 0 is considering a failure
I have also included return code 8 in the checks, as this is the code when the command is successfully run but license acceptance is not required.

Example:

Source https://stackoverflow.com/questions/57456319

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install wharf

You can download it from GitHub.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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