sqld | sqld supports MySQL , Postgres | Database library

 by   mmaelzer Go Version: Current License: MIT

kandi X-RAY | sqld Summary

kandi X-RAY | sqld Summary

sqld is a Go library typically used in Database, PostgresSQL applications. sqld has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

sqld supports MySQL (-type mysql), Postgres (-type postgres), and SQLite (-type sqlite3) databases.
Support
    Quality
      Security
        License
          Reuse

            kandi-support Support

              sqld has a low active ecosystem.
              It has 11 star(s) with 3 fork(s). There are 1 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              sqld has no issues reported. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of sqld is current.

            kandi-Quality Quality

              sqld has 0 bugs and 0 code smells.

            kandi-Security Security

              sqld has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              sqld code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              sqld is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              sqld releases are not available. You will need to build from source code and install.
              Installation instructions are not available. Examples and code snippets are available.

            Top functions reviewed by kandi - BETA

            kandi has reviewed sqld and discovered the below as its top functions. This is intended to give you an instant insight into sqld implemented functionality, and help decide if they suit your requirements.
            • handle query
            • readQuery executes a sql query and returns a map of values .
            • helper function
            • buildDSN builds a DSN from the database
            • buildSelectQuery builds a SELECT query from the request .
            • createSingle inserts a single row into a single item .
            • buildUpdateQuery builds an UPDATE query from the request .
            • create a record from the request .
            • buildDeleteQuery builds the delete query for the given request .
            • execute query .
            Get all kandi verified functions for this library.

            sqld Key Features

            No Key Features are available at this moment for sqld.

            sqld Examples and Code Snippets

            No Code Snippets are available at this moment for sqld.

            Community Discussions

            QUESTION

            My UPDATE statement does not work, but DELETE and INSERT does
            Asked 2021-Mar-20 at 17:05

            I am using sql with Javascript to make a simple CRUD project, but when i need to update a user from de DB I get an error saying: "could not prepare statement (1 no such column: (new name))", so I ended up using a DELETE and INSERT instead, but the UPDATE statement is better in terms of time, so I'd like to use the UPDATE.

            ...

            ANSWER

            Answered 2021-Mar-20 at 17:05

            The error messsage is about that there's no name column in that table. It means that you are probably set the nombre's value as name, but not qouting it, so you're ending up with the query:

            Source https://stackoverflow.com/questions/66723687

            QUESTION

            SQL result not shown as the same in Servlet
            Asked 2021-Jan-26 at 15:36

            All.

            I got SQL query that sorts the given data inside query.xml file.
            As I test on SQLD(Oracle), it gives me back the sorted data as expected.

            ...

            ANSWER

            Answered 2021-Jan-26 at 15:36

            This is because ? designates a placeholder value, so you always sort by constant.

            Oracle distinguishes between constant int (that you pass via ?) and integer position of the column, that you put when you do select * from ... order by 1. For the latter 1 is a part of syntax and acts like an identifier. You can check this with below code.

            As you see, the first query treats 1 as column position and sorts by the first column, when the second actually sorts by the second column.

            Source https://stackoverflow.com/questions/65903759

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install sqld

            You can download it from GitHub.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
            Find more information at:

            Find, review, and download reusable Libraries, Code Snippets, Cloud APIs from over 650 million Knowledge Items

            Find more libraries
            CLONE
          • HTTPS

            https://github.com/mmaelzer/sqld.git

          • CLI

            gh repo clone mmaelzer/sqld

          • sshUrl

            git@github.com:mmaelzer/sqld.git

          • Stay Updated

            Subscribe to our newsletter for trending solutions and developer bootcamps

            Agree to Sign up and Terms & Conditions

            Share this Page

            share link