coordtransform | 坐标转换工具,提供WGS84,GCJ02,百度坐标系的相互转换。 | Map library

 by   qichengzx Go Version: Current License: MIT

kandi X-RAY | coordtransform Summary

kandi X-RAY | coordtransform Summary

coordtransform is a Go library typically used in Geo, Map applications. coordtransform has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

坐标转换工具,提供WGS84,GCJ02,百度坐标系的相互转换。
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              coordtransform has a low active ecosystem.
              It has 116 star(s) with 21 fork(s). There are 5 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 0 open issues and 2 have been closed. On average issues are closed in 116 days. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of coordtransform is current.

            kandi-Quality Quality

              coordtransform has no bugs reported.

            kandi-Security Security

              coordtransform has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              coordtransform is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              coordtransform releases are not available. You will need to build from source code and install.
              Installation instructions are not available. Examples and code snippets are available.

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            coordtransform Key Features

            No Key Features are available at this moment for coordtransform.

            coordtransform Examples and Code Snippets

            No Code Snippets are available at this moment for coordtransform.

            Community Discussions

            QUESTION

            Java : How to do image manipulation (pan, zoom, flip and rotate)?
            Asked 2019-Sep-24 at 00:05

            I am making an Image viewer application for my own interest. I am using JPanel to display a bufferedImage.

            Objective - I want to manipulate the image and give user the options to zoom, pan, flip or rotate images.

            I am now able to zoom, pan and rotate. But the problem is that it is not the same as what you see when you open a .pdf file in Microsoft Edge.

            I have added the code below:

            ...

            ANSWER

            Answered 2019-Sep-23 at 18:09

            Here is a simple program that demonstrates what I suggested, namely a large image set as the icon of a JLabel and the JLabel is the scrollable client for a JScrollPane. Note that I set the preferred size of the JScrollPane to 800 x 600 pixels because the default behavior is to make the JScrollPane the same size as its scrollable client. The image dimensions are 2312 x 1536 pixels which means it is larger than my computer screen. So if I don't set the preferred size, when you run the program the JFrame overflows the screen. You don't see all of the JFrame. This is on purpose so you can see how the image scrolls. The URL for the image is https://unsplash.com/photos/l68Z6eF2peA. And here is the code, which is a MCVE

            By the way, I downloaded and saved the image in a file that I named worldmap.jpg

            Source https://stackoverflow.com/questions/58021358

            QUESTION

            Rotate an image in C++ without using OpenCV functions
            Asked 2019-Aug-02 at 04:13

            Description :- I am trying to rotate an image without using OpenCV functions in C++. The rotation center need not be the center of the image. It could be a different point (offset from the image center). So far I followed a variety of sources to do image interpolation and I am aware of a source which does the job perfectly in MATLAB. I tried to mimic the same in C++ without OpenCV functions. But I am not getting the expected rotated image. Instead my output appears like a small horizontal line on the screen.

            ...

            ANSWER

            Answered 2019-Jul-11 at 15:14

            First, I have to admit I agree with generic_opto_guy:

            The approach with the loop looks good, so we would need to check the math. On thing I noticed: if (oldRow > 0 && oldCol > 0 && oldRow <= oldHeight && oldCol <= oldWidth) implies you start indexing with 1. I belife that opencv starts indexing with 0.

            For all that, I couldn't resist to answer. (May be, it's just an image phase of mine.)

            Instead of fiddling with sin() and cos(), I would recommend to use matrix transformation. At the first glance, this might appear over-engineered but later you will recognize that it bears much more flexibility. With a transformation matrix, you can express a lot of transformations (translation, rotation, scaling, shearing, projection) as well as combining multiple transformations into one matrix.

            (A teaser for what is possible: SO: How to paint / deform a QImage in 2D?)

            In an image, the pixels may be addressed by 2d coordinates. Hence a 2×2 matrix comes into mind but a 2×2 matrix cannot express translations. For this, homogeneous coordinates has been introduced – a math trick to handle positions and directions in the same space by extending the dimension by one.

            To make it short, a 2d position (x, y) has the homogeneous coordinates (x, y, 1).

            A position transformed with a transformation matrix:

            = M · v.

            This may or may not change the value of third component. To convert the homogeneous coordinate to 2D position again, x and y has to be divided by 3rd component.

            Source https://stackoverflow.com/questions/56981096

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install coordtransform

            You can download it from GitHub.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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