puppy | golang library that can be used to create proxies | Proxy library
kandi X-RAY | puppy Summary
kandi X-RAY | puppy Summary
Puppy is a golang library that can be used to create proxies to intercept and modify HTTP and websocket messages that pass through it. Puppy itself does not provide any interactive interface, it provides an API to do proxy things in go. If you want a useful tool that uses Puppy, try [Pappy] Puppy was originally aimed to be a starting point to write a tool similar to [Burp Suite] and to provide a base for writing other HTTP proxy software.
Support
Quality
Security
License
Reuse
Top functions reviewed by kandi - BETA
- InterceptHandler handles incoming requests
- schema9 updates the requests table .
- CreateWebUIHandler creates proxy web UI handler
- NewRequestChecker creates a new RequestChecker .
- CheckArgsGoToStr cast args to strings
- create a string field getter
- CheckArgsStrToGo takes a slice of strings and returns a slice of strings .
- schema8 creates a new schema version .
- Runs the main process .
- genStrChecker creates a checker for a given argument .
puppy Key Features
puppy Examples and Code Snippets
Community Discussions
Trending Discussions on puppy
QUESTION
I'm completely stuck here. Here's the problem I'm solving:
A shift cipher takes a plain text message and shifts each letter forward in the alphabet by a given number. For example, a shift cipher with a shift of 1 would turn the string 'hello' to 'ifmmp'.
Example:
...ANSWER
Answered 2022-Apr-03 at 12:50The problem seems to be this line:
QUESTION
Does anyone know how to create an alphabetical fast scroller, displaying all the letters in Jetpack Compose?
Similar to this one: Recyclerview Alphabetical Scrollbar
I have made a list which is scrollable, but I have no clue in how to make the letters on the side and make it "jump" to the right letter.
here is my coding so far:
...ANSWER
Answered 2022-Mar-29 at 07:35To display letters all you need is a Column with needed items. To scroll a lazy column to a needed item, you can use lazy column state.
Here's a basic example:
QUESTION
I am trying to use a navlink in my app.jsx file to create links in my navbar but when I try to npm start, I dont see the nav links and I get a message that says No routes matched location "/". I'm not sure why. I saw somewhere that I needed to start using element but I'm not sure how. I'll show app.jsx file with the element statements that didn't seem to work still and the file without using element at all which also didn't help but is what I'm used to. Can someone point me in the right direction?
index.js :
...ANSWER
Answered 2022-Mar-28 at 19:02Links use a to prop for the target route they are linking to, and the UI needs to be rendered on Route components on the element prop. I suggest unconditionally rendering the App component and move the routes into it.
Example:
index.js
QUESTION
I am practicing with API's and building out controller functions to create, index, show, update and delete puppies from the database. In order to check that all my routes are working correctly I am using Postman and so far so good, except for my show function. The show controller function is supposed to find a single puppy by the id.
I am trying to send a GET request with a specific id and I am supposed to receive the object I CREATEd earlier but instead I get{"err": "Cannot read property 'id' of undefined"}
can anyone help me? why is it not accepting the id?
Server.js
...ANSWER
Answered 2022-Mar-24 at 00:58It is because of misspelling the argument to Puppy.findById(), you entered req.parmas.id and it should be req.params.id.
QUESTION
I have a list like this:
...ANSWER
Answered 2022-Mar-23 at 12:50There are a few adjustment you need to make:
- don't increase
imanually in the loop but use step value inrange(start, end, step). The step value here would need to be 5. - You need to append the results to the list, otherwise you are just replacing the value over and over again and only the last value will be stored in the variables at the end of the
for loop. - you probably want to strip the newlines
\n(but this is optional) usingrstrip("\n"). - you probably also want to have all the possibilities for an answer in an array (but this is also optional). You can do that by using
split("#")on the relevant string.
QUESTION
I need help with my project. I am new to coding but am learning very quick. I have a random image generator but every time I click the button I want the images previously generated to be replaced with the new ones. right now the generator just adds two more images every time I click the button. My goal is that every time I click the button two new random images appear taking the place of the two before. Thanks for the help! here is my code below but i have redacted the images because i wish to keep them private for now.i put the original puppies in place of the real images.
...ANSWER
Answered 2022-Mar-18 at 07:00In order to clear the images before generating a new set, you have to clear the result span element. Also, I adjusted the code below to declare the images in the array and created a reference to the element outside of the function to minimize the tasks being done in the function.
QUESTION
Consider the following array of emojis:
...ANSWER
Answered 2022-Mar-17 at 08:25Your code resets display at each iteration, so the final value is merely the last match on the array.
QUESTION
I am trying to see how spoken-word and read-word frequency correlate with performance on a word game. here is my reproducible sample:
...ANSWER
Answered 2022-Mar-09 at 22:28Perhaps something like this?
QUESTION
I am trying to see how word frequency correlates with phonotactic probability using R, but there are a few issues. First, and most generally, I don't know merge these two graphs together (i want them to appear on the same axis).
This leads to a second problem because the first graph's y values are in probabilities, and the second is a count, so the scales are not the same. Should I combine data frames first, or is there a simpler way to merge two graphs?
Here is the reproducible sample, and the code for my graphs:
...ANSWER
Answered 2022-Mar-09 at 20:44One way could be to use a second y axis. Although this method is to be used critically, in this situation I think it is appropriate:
QUESTION
I'm curious about this line and have never seen this format with an array right after the variable:
pics[coinToss() === 'heads' ? 'kitty' : 'doggy'] to render pics.doggy or pics.kitty
Is there specific documentation about this format I can read more about?
...ANSWER
Answered 2022-Feb-17 at 15:52It's not an array, it's a property access - like when you access some array's elements with myArray[5] to get the 6th element (which is property 5 of the array), but it works the same for string properties of objects:
pics['kitty'] is the same as pics.kitty.
The name of the property accessed is whatever coinToss() == 'heads' ? 'kitty' : 'doggy' evaluates to (which uses ?: to yield either 'kitty' or 'doggy' depending on the result of coinToss()).
Here it's functionally the same as coinToss() === 'heads' ? pics.kitty : pics.doggy.
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install puppy
Support
Reuse Trending Solutions
Find, review, and download reusable Libraries, Code Snippets, Cloud APIs from over 650 million Knowledge Items
Find more librariesStay Updated
Subscribe to our newsletter for trending solutions and developer bootcamps
Share this Page
