tr | Easy drop-in i18n solution for Go applications | Text Editor library
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kandi X-RAY | tr Summary
Easy drop-in i18n solution for Go applications.
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QUESTION
I have basically this very odd type of data frame:
The first column is the name of the States (say I have 3 states), the second to the last column (say I have 5 columns) contains some values recorded at different dates (not continuous). I want to create a graph that plots the values for each State on the range of the dates that starts from the earliest and end in the latest dates (continuous).
The table looks like this:
state 2020-01-01 2020-01-05 2020-01-06 2020-01-10 AZ NA 0.078 -0.06 NA AK 0.09 NA NA 0.10 MS 0.19 0.21 NA 0.38"NA" means there is not data.
How do I produce this graph in which the x axis is from 2020-01-01 to 2020-01-10 (continuous), the y axis contains the changing values (as points) of the three States, each state occupies its separate (segmented) y-axis?
Thank you.
...ANSWER
Answered 2021-Jun-16 at 03:41You can get the data into a long format, which makes it easier to plot. R will make it difficult to read column names that start with a number. While reading the data, ensure that you have check.names = FALSE
so that column names are read as is.
QUESTION
I'm normally OK on the joining and appending front, but this one has got me stumped.
I've got one dataframe with only one row in it. I have another with multiple rows. I want to append the value from one of the columns of my first dataframe to every row of my second.
df1:
id Value 1 worddf2:
id data 1 a 2 b 3 cOutput I'm seeking:
df2
id data Value 1 a word 2 b word 3 c wordI figured that this was along the right lines, but it listed out NaN for all rows:
...ANSWER
Answered 2021-Jun-15 at 23:59Just get the first element in the value column of df1 and assign it to value column of df2
QUESTION
The title is the required predicate and here are few sample queries
...ANSWER
Answered 2021-Jun-08 at 09:46This compact fragment satisfies the queries you listed
QUESTION
I've been stuck on this for a few weeks now....
df1:
2 1/1/2021 1/2/2021 1/3/2021 Name a door nan house b nan key door c nan house key d house key nandf2:
2 key door house Name a nan nan nan b nan nan nan c nan nan nan d nan nan nandesired output=
df2:
2 key door house Name a nan 1/1/2021 1/3/2021 b 1/2/2021 1/3/2021 nan c 1/3/2021 nan 1/2/2021 d 1/2/2021 nan 1/1/2021 ...ANSWER
Answered 2021-Jun-15 at 23:03Try with stack
+ pivot_table
with aggfunc='first'
to get the first match
QUESTION
Is there a way in PostgreSQL to take this table:
ID country name values 1 USA John Smith {1,2,3} 2 USA Jane Smith {0,1,3} 3 USA Jane Doe {1,1,1} 4 USA John Doe {0,2,4}and generate this table from it with the column agg_values
:
Where each row aggregates all values
except from the current row and its peers.
So if name = John Smith
then agg_values = aggregate of all values where name not = John Smith
. Is that possible?
ANSWER
Answered 2021-Jun-14 at 20:16You can use a lateral join to a derived table that unnests all rows where the name is not equal and then aggregates that back into an array:
QUESTION
In the following example the gray "td" bar will fill the entire window width, but I can't get the encapsulated link to. I want the entire bar to be an active link, not just the text:
...ANSWER
Answered 2021-Jun-15 at 22:49Simply add display: flex;
to a
in the CSS:
QUESTION
Currently I have 3 tables like below
Master
ID_NUMBER ZIPCODE 1 12341 2 12342 3 12343 4 12344Table1
ID_NUMBER CITYNAME COUNTYNAME 1 NEW YORK QUEENS 3 DETROIT SUFFOLKTable2
ID_NUMBER CITYNAME COUNTYNAME 2 ATLANTA ROCKLAND 4 BOSTON WINCHESTERMy desired output is like below. I want to filter based on the zipcode from master table
ID_NUMBER ZIPCODE CITYNAME COUNTYNAME 2 12342 ATLANTA ROCKLANDHow would i go about writing a query for this? Below is what i have tried but it's giving me null values if the ID_NUMBER is not found on that particular table.
...ANSWER
Answered 2021-Jun-15 at 22:37Use COALESCE()
:
QUESTION
So I was fetching data from my database to print in a table however, it says that Class "App\Http\Controllers\User" not found. Here is the controller and here is how I will print the data
...ANSWER
Answered 2021-Jun-15 at 22:42At the top off your controller add
Laravel 8+
QUESTION
ANSWER
Answered 2021-Jun-15 at 20:35You could reset the form by writing this:
QUESTION
I have a dataset with various "chunks" of columns with different prefixes, but the same suffix:
ID A034 B034 C034 D034 A099 B099 A123 B123 ... 1 NA 1 NA NA NA 3 1 NA ... 2 2 NA NA NA 2 NA NA 2 ... 3 NA NA 2 NA NA 2 1 NA ...The number of columns within each "chunk" also varies. Is there any way (other than manually, which is what I have been painstakingly doing with coalesce(!!! select(., contains("XXX")))
) to automatically coalesce by chunk based on the shared suffix? That is, the result should resemble
I'm not sure how to begin doing something like this, so any suggestions would be very helpful.
...ANSWER
Answered 2021-Jun-15 at 20:10We reshape the data into 'long' format with pivot_longer
, then we group by 'ID' and loop across
the other columns, apply the na.omit
to remove the NA elements (we assume that there is only one non-NA per each column by group)
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