tr | Easy drop-in i18n solution for Go applications | Text Editor library

 by   tucnak Go Version: Current License: MIT

kandi X-RAY | tr Summary

kandi X-RAY | tr Summary

tr is a Go library typically used in Editor, Text Editor applications. tr has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

Easy drop-in i18n solution for Go applications.
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            kandi-support Support

              tr has a low active ecosystem.
              It has 183 star(s) with 7 fork(s). There are 4 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              tr has no issues reported. There are 1 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of tr is current.

            kandi-Quality Quality

              tr has no bugs reported.

            kandi-Security Security

              tr has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              tr is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              tr releases are not available. You will need to build from source code and install.
              Installation instructions are not available. Examples and code snippets are available.

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            tr Key Features

            No Key Features are available at this moment for tr.

            tr Examples and Code Snippets

            A class used to construct a TR object
            javascriptdot img1Lines of Code : 1dot img1License : Permissive (MIT License)
            copy iconCopy
            function tr(t,n){this.xf=n,this.f=t,this.found=!1}  

            Community Discussions

            QUESTION

            How to produce a point graph in R like this?
            Asked 2021-Jun-16 at 04:05

            I have basically this very odd type of data frame:

            The first column is the name of the States (say I have 3 states), the second to the last column (say I have 5 columns) contains some values recorded at different dates (not continuous). I want to create a graph that plots the values for each State on the range of the dates that starts from the earliest and end in the latest dates (continuous).

            The table looks like this:

            state 2020-01-01 2020-01-05 2020-01-06 2020-01-10 AZ NA 0.078 -0.06 NA AK 0.09 NA NA 0.10 MS 0.19 0.21 NA 0.38

            "NA" means there is not data.

            How do I produce this graph in which the x axis is from 2020-01-01 to 2020-01-10 (continuous), the y axis contains the changing values (as points) of the three States, each state occupies its separate (segmented) y-axis?

            Thank you.

            ...

            ANSWER

            Answered 2021-Jun-16 at 03:41

            You can get the data into a long format, which makes it easier to plot. R will make it difficult to read column names that start with a number. While reading the data, ensure that you have check.names = FALSE so that column names are read as is.

            Source https://stackoverflow.com/questions/67995623

            QUESTION

            append or join value from one dataframe to every row in another dataframe in Pandas
            Asked 2021-Jun-15 at 23:59

            I'm normally OK on the joining and appending front, but this one has got me stumped.

            I've got one dataframe with only one row in it. I have another with multiple rows. I want to append the value from one of the columns of my first dataframe to every row of my second.

            df1:

            id Value 1 word

            df2:

            id data 1 a 2 b 3 c

            Output I'm seeking:

            df2

            id data Value 1 a word 2 b word 3 c word

            I figured that this was along the right lines, but it listed out NaN for all rows:

            ...

            ANSWER

            Answered 2021-Jun-15 at 23:59

            Just get the first element in the value column of df1 and assign it to value column of df2

            Source https://stackoverflow.com/questions/67994592

            QUESTION

            A prolog predicate to split a list into sperate lists ever n elements
            Asked 2021-Jun-15 at 23:50

            The title is the required predicate and here are few sample queries

            ...

            ANSWER

            Answered 2021-Jun-08 at 09:46

            This compact fragment satisfies the queries you listed

            Source https://stackoverflow.com/questions/67880231

            QUESTION

            pandas returning column name as value if column name matches value of another data frame
            Asked 2021-Jun-15 at 23:15

            I've been stuck on this for a few weeks now....

            df1:

            2 1/1/2021 1/2/2021 1/3/2021 Name a door nan house b nan key door c nan house key d house key nan

            df2:

            2 key door house Name a nan nan nan b nan nan nan c nan nan nan d nan nan nan

            desired output=

            df2:

            2 key door house Name a nan 1/1/2021 1/3/2021 b 1/2/2021 1/3/2021 nan c 1/3/2021 nan 1/2/2021 d 1/2/2021 nan 1/1/2021 ...

            ANSWER

            Answered 2021-Jun-15 at 23:03

            Try with stack + pivot_table with aggfunc='first' to get the first match

            Source https://stackoverflow.com/questions/67993713

            QUESTION

            Aggregating all values not in the same group
            Asked 2021-Jun-15 at 22:57

            Is there a way in PostgreSQL to take this table:

            ID country name values 1 USA John Smith {1,2,3} 2 USA Jane Smith {0,1,3} 3 USA Jane Doe {1,1,1} 4 USA John Doe {0,2,4}

            and generate this table from it with the column agg_values:

            ID country name values agg_values 1 USA John Smith {1,2,3} {0,1,3,1,1,1,0,2,4} 2 USA Jane Smith {0,1,3} {1,2,3,1,1,1,0,2,4} 3 USA Jane Doe {1,1,1} {1,2,3,0,1,3,0,2,4} 4 USA John Doe {0,2,4} {1,2,3,0,1,3,1,1,1}

            Where each row aggregates all values except from the current row and its peers.
            So if name = John Smith then agg_values = aggregate of all values where name not = John Smith. Is that possible?

            ...

            ANSWER

            Answered 2021-Jun-14 at 20:16

            You can use a lateral join to a derived table that unnests all rows where the name is not equal and then aggregates that back into an array:

            Source https://stackoverflow.com/questions/67975901

            QUESTION

            link element inside table td won't expand to fill whole line
            Asked 2021-Jun-15 at 22:49

            In the following example the gray "td" bar will fill the entire window width, but I can't get the encapsulated link to. I want the entire bar to be an active link, not just the text:

            ...

            ANSWER

            Answered 2021-Jun-15 at 22:49

            Simply add display: flex; to a in the CSS:

            Source https://stackoverflow.com/questions/67994038

            QUESTION

            Multiple table joins in Oracle SQL with same column names
            Asked 2021-Jun-15 at 22:43

            Currently I have 3 tables like below

            Master

            ID_NUMBER ZIPCODE 1 12341 2 12342 3 12343 4 12344

            Table1

            ID_NUMBER CITYNAME COUNTYNAME 1 NEW YORK QUEENS 3 DETROIT SUFFOLK

            Table2

            ID_NUMBER CITYNAME COUNTYNAME 2 ATLANTA ROCKLAND 4 BOSTON WINCHESTER

            My desired output is like below. I want to filter based on the zipcode from master table

            ID_NUMBER ZIPCODE CITYNAME COUNTYNAME 2 12342 ATLANTA ROCKLAND

            How would i go about writing a query for this? Below is what i have tried but it's giving me null values if the ID_NUMBER is not found on that particular table.

            ...

            ANSWER

            Answered 2021-Jun-15 at 22:37

            QUESTION

            Class "App\Http\Controllers\User" not found
            Asked 2021-Jun-15 at 22:42

            So I was fetching data from my database to print in a table however, it says that Class "App\Http\Controllers\User" not found. Here is the controller and here is how I will print the data

            ...

            ANSWER

            Answered 2021-Jun-15 at 22:42

            At the top off your controller add

            Laravel 8+

            Source https://stackoverflow.com/questions/67994274

            QUESTION

            How do I initiate each different type of input and select elements since I submit it?
            Asked 2021-Jun-15 at 20:35

            ANSWER

            Answered 2021-Jun-15 at 20:35

            You could reset the form by writing this:

            Source https://stackoverflow.com/questions/67993147

            QUESTION

            Coalescing multiple chunks of columns with the same suffix in names (R)
            Asked 2021-Jun-15 at 20:10

            I have a dataset with various "chunks" of columns with different prefixes, but the same suffix:

            ID A034 B034 C034 D034 A099 B099 A123 B123 ... 1 NA 1 NA NA NA 3 1 NA ... 2 2 NA NA NA 2 NA NA 2 ... 3 NA NA 2 NA NA 2 1 NA ...

            The number of columns within each "chunk" also varies. Is there any way (other than manually, which is what I have been painstakingly doing with coalesce(!!! select(., contains("XXX")))) to automatically coalesce by chunk based on the shared suffix? That is, the result should resemble

            ID 034 099 123 ... 1 1 3 1 ... 2 2 2 2 ... 3 2 2 1 ...

            I'm not sure how to begin doing something like this, so any suggestions would be very helpful.

            ...

            ANSWER

            Answered 2021-Jun-15 at 20:10

            We reshape the data into 'long' format with pivot_longer, then we group by 'ID' and loop across the other columns, apply the na.omit to remove the NA elements (we assume that there is only one non-NA per each column by group)

            Source https://stackoverflow.com/questions/67992781

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install tr

            You can download it from GitHub.

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