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QUESTION
I have below dict inside list, dictlist
have g1
to g4
key and inside many key,pair. I want to print a
and 23
with group title with sum of value for each group, desire output as below:
ANSWER
Answered 2021-May-12 at 03:33You do not have a dict inside a list. You have lists inside a dict. Once you fix the spelling errors (append
is a function and should use parens, not brackets, and you don't have b
and b1
, you have b1
and b2
), your code produces exactly the structure you describe. It doesn't PRINT that way, because that's not how Python prints lists, but the data is all there:
QUESTION
I have a regex problem that combines the ideas of optional characters and conditional regex statements that I'm unsure how to solve.
I want to find a pattern that, in addition to matching an initial number, will also match the following uppercase letter if and only if that character is not followed by a lowercase letter. The string will only ever have one number. For example:
...ANSWER
Answered 2021-Apr-14 at 11:51It seems you can try to use:
QUESTION
Given a non-empty string and an int N, return the string made starting with char 0, and then every Nth char of the string. So if N is 3, use char 0, 3, 6, ... and so on. N is 1 or more.
...ANSWER
Answered 2021-Mar-30 at 12:54Your code does not compile. First of all, replace String stringPosition = str.charAt(pos)
with String stringPosition = String.valueOf(str.charAt(0))
as str.charAt(pos)
returns a char
value which you can not assign to a String
variable.
Also, it is as simple as starting the loop counter with 0
and stepping with a value n
. In each iteration, append the character at the loop counter to a StringBuilder
.
QUESTION
I have a table in the shape of a symmetric matrix that tells me which components are compatible. Here is an example;
...ANSWER
Answered 2021-Mar-25 at 22:00import numpy as np
import pandas as pd
import networkx as nx
import matplotlib.pyplot as plt
df = pd.read_excel(r"/path/to/file.xlsx", sheet_name="Sheet4",index_col=0,usecols = "A:H")
df.edge=nx.from_pandas_adjacency(df)
print(list(nx.enumerate_all_cliques(nx.Graph(df.edge))))
QUESTION
I am testing a Linux-PAM installation with this test program. When the pam_ldap.so module is called, the test program application fails with a segmentation error. Looking at the /var/log/messages, I can red the following error message:
...ANSWER
Answered 2021-Feb-16 at 16:05Can anyone help me understand the source of the problem?
You linked libldap-2.4.so.2
against GLIBC-2.28 (or later).
But at runtime, the version of GLIBC is 2.27 (or earlier).
GLIBC supports backward compatibility (binaries built against earlier version of GLIBC continue to run on systems with newer GLIBC versions).
But it doesn't support "build on newer, run on older" compatibility.
QUESTION
I hope someone could help me solving this python scripting. I'd like to do something similar to index-match function in excel using Python.
I have two data sets shown below: -
a) The dataframe 1 (df):
Index Node 1 Node 2 Value 0 ABBDD DSGHSH 164.35 1 ABNEQY ASFCZC 125.40 2 ABNERR ZDCDBB 150.40 3 BANDER DSVBDG 0.00 4 GDCHR CVXSVG 94.05 5 GFRSA ZFGDHJD 94.05 6 SRHNAI SDWRWW 119.70 7 ZDCDBB BANDERR 148.20 8 VBZ3VG EWEWWE 148.20 9 SDZXZC ADGSGSG 125.40b) The dataframe 2 (df2):
Index Node Value 0 SDZX 1 VBZ3 2 AAAF 3 ADGS 4 DSVB 5 ZDCD 6 GFRSA 7 ABNE 8 ABBD 9 EWEW 10 SRHNA 11 BANDERThe first data frame comprises of two longer node names and a value column which I'd like to copy to the second data frame if its shorter node name contains in either one of the node names in the first data frame. If more than one value is available, only the maximum value will be selected.
My desired output:
Index Node Value 0 SDZX 125.40 1 VBZ3 148.20 2 AAAF NaN 3 ADGS 125.40 4 DSVB 0.00 5 ZDCD 150.40 6 GFRSA 94.05 7 ABNE 150.40 8 ABBD 164.35 9 EWEW 148.20 10 SRHNA 119.70 11 BANDER 148.20I have tried several ways. First step, I reduce the Node 1 and Node 2 name to 5 characters. I understand this is not the right way as this implies that I'll miss out those Nodes with more than 5 characters. I can't figure out how to use str.contains in join/merge function in Pandas to solve this problem.
...ANSWER
Answered 2020-Dec-21 at 19:46I think this should work, now:
I started from scratch because you're only providing a tables not coded data simple.
Creating DataFrames
QUESTION
I wanted to produce a permutation of multiple strings based on a given integer in the first line. For example,
...ANSWER
Answered 2020-Nov-20 at 18:00One approach to developing a recursive solution is to assume you already have one that works for smaller versions of the problem. (The idea is that if it can handle the smallest case (the base case) directly, and any recursive call is on a smaller problem, you always eventually get to that base case.)
To wit:
QUESTION
I have setup a lambda@edge function that dynamically decides what bucket (origin) to use to get the s3 object from (uri..).
I want to make sure that what I am doing does not defeat the whole purpose of using CloudFront in the first place, meaning, allowing origins contents (s3 buckets) to be cached at edges so that users can get what they request fast from the closest edge location to them.
I am following this flow:
...ANSWER
Answered 2020-Oct-16 at 14:01I want to make sure that what I am doing does not defeat the whole purpose of using CloudFront
It doesn't defeat the purpose. This works as intended and the response would still be cached using the same rules that would be used if this bucket were a statically configured origin and no trigger was in place.
Origin Request triggers only fire when there's a cache miss -- after the cache is checked and the requested resource is not there, and CloudFront concludes that the request needs to be forwarded to an origin server. The Origin Request trigger causes CloudFront to briefly suspend its processing while your trigger code evaluates and possibly modifies the request before returning control to CloudFront. Changing/setting the origin server in the trigger modifies the destination where CloudFront will then send the request, but it doesn't have any impact on whether the response can/will be cached or otherwise change what CloudFront would do when the response arrives from the origin server. And, if a suitable response is already available in the cache when a new request arrives, the trigger won't fire at all, since there's nothing for it to do.
as long as that bucket is setup in CloudFront as one of the origin already
This isn't actually required. Any S3 bucket with publicly-accessible content can be specified as the origin server in an Origin Request trigger, even if it isn't one of the origins configured on the distribution.
There are other rules and complexities that come into play if a trigger like this is desired and your buckets require authentication and are using KMS-based object encryption, but in those cases, there would still be no impact of this design on caching -- just some extra things you need to do to actually make authentication work between CloudFront and the bucket, since an Origin Access Identity (normally used to allow CloudFront to authenticate itself to S3) isn't sufficient for this use case.
It's not directly related to the Origin Request trigger and the gist of this question, but noteworthy since you are using request.querystring
: be sure you understand the concept of the cache key, which is the combination of request attributes that CloudFront will use when determining whether a future request can be served using a given cached object. If two similar requests result in different cache keys, then CloudFront won't treat them as identical requests and the response for one cannot be used as a cached response for the other, even though your expectation might have been otherwise, since the two request are for the same object. An Origin Request trigger can't change the cache key for a request, either accidentally or deliberately, since it's already been calculated by CloudFront by the time the trigger fires.
meaning, allowing origins contents (s3 buckets) to be cached at edges so that users can get what they request fast from the closest edge location to them
Ah. Having written all the above, it occurs to me now that perhaps your question might actually stem from an assumption I've seen people occasionally make about how CloudFront and S3 interact. It's an assumption that is understandable, but turns out to be inaccurate. When a bucket is configured as a CloudFront origin, there is no mechanism that pushes the bucket's content out to the CloudFront edges proactively. If you were working from a belief that this is something that happens when a bucket is configured as a CloudFront S3 origin, then this question takes on a different significance, since you're essentially asking whether the content from those various buckets would still arrive at CloudFront as expected... but CloudFront is what I call a "pull-through CDN." Objects are stored in the cache at a given edge only when someone requests them through that edge -- they're cached as they are fetched as a result of that initial request, not before. So your setup simply changes where CloudFront goes to fetch a given object. The rest of the system works the same as always, with CloudFront pulling and caching the content on demand.
QUESTION
Most of the Atlaskit editor is licensed with MIT or Apache 2.0 License. I'm trying to figure out how Atlaskit is supposed to be used without accepting non-free (as in freedom) Atlassian Design Guidelines License (ADG License) which is used for packages @atlaskit/icon
, @atlaskit/icon-file-type
and @atlaskit/icon-object
which are part of deeply nested dependencies for the Atlaskit editor.
I'm fully aware that I need to re-create alternative icons and themes and I'm fine with that. However, when I create package.json
and run npm install
I get the above mentioned ADG licensed packages when I include following dependencies:
ANSWER
Answered 2020-Oct-06 at 19:14NPM natively supports package aliases since version 6.9.0
So in your case you could take the following approach:
QUESTION
I have data as below:
...ANSWER
Answered 2020-Aug-21 at 19:32For two vectors vec
and test
, this returns a vector which is TRUE
if either the corresponding element of test
is the start of one of the elements of vec
, or one of the elements of vec
is the start of the corresponding element of test
.
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