MyBook | Simple and beautiful e-book reader | Media library
kandi X-RAY | MyBook Summary
kandi X-RAY | MyBook Summary
Simple and beautiful e-book reader (supports all platforms)
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of MyBook
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Trending Discussions on MyBook
QUESTION
I have json object whose property values are unique and can be anything;
...ANSWER
Answered 2021-Jun-09 at 05:40You can try this
QUESTION
I have a jqgrid with a subgrid. I made a few columns in the parent grid and subgrid as frozen. Frozen columns on subgrid works fine, but it does not work on the parent grid.
When I disable the subgrid by setting subGrid as false, frozen rows works perfectly on the parent.
Is there anything that I am missing which stops the frozen columns on the parent grid from working?
Here is my jqgrid:
...ANSWER
Answered 2021-Jun-07 at 07:42In Guriddo jqGrid subgrid can not be used when frozen columns are on.
Here you can read all the limitation of Guriddo jqGrid. We do not know how this is in free-jqgrid.
QUESTION
I want to be able to change an iframe src with the help of react but i don't know were to start as i am new to coding in general.
I manage to build what i want with html and js but it is not working when i dump the code in a react project.
edit: I tried converting html and js to jsx with an online convertor but it did not work.
Please see how code below works and point me to the right direction please.
...ANSWER
Answered 2021-May-27 at 04:26You need to start with create-react-app.
After you get the basic react application template, Go to App.js and write this code:
QUESTION
const myBooks = [
{
title: 'Why We Sleep',
author: 'Matthew Walker',
},
{
title: 'All freinds',
author: 'Christian'
}
];
function createBookList(books) {
let list = document.createElement('ul');
books.forEach((sam) => {
let li = document.createElement('li');
let p = document.createElement('p');
let image = document.createElement('img');
image.src = 'https://media-amazon.com/7ov383lj3Rr';
p.textContent = `${sam.title} - ${sam.author}`;
li.style.listStyleType = 'none';
list.appendChild(li);
list.appendChild(p);
list.appendChild(image);
});
return list;
}
...ANSWER
Answered 2021-May-21 at 14:43The callback function in Array.prototype.forEach()
exposes three values; the current item in the array, the current index of the array, and the array that is being looped over.
With the second parameter, the index, you can assess where in the loop you are and create logic for a specific index, like the first item in the array 0
.
Oh, and I think you meant to append the paragraph and the image to the list item, not the list itself.
QUESTION
In the below I am trying to create new tabs in a worksheet based of a column 3 in MainSheet (if they dont exist already). I think the below should do that, but I can not figure out how to group lines in MainSheet based on a matching number prefix.... that is 210422-C is the cell and the 2104 once extracted matches the line below it. So those two lines would be copied to a new tab called 04-21 (reverse of the extracted prefix separated with a - after the second digit). 210505-C is the cell and the 2105 once extracted matches the line below it. So those two lines would be copied to a new tab called 05-21 (reverse of the extracted prefix separated with a - after the second digit). There wont always be two rows that match and there are multiple columns in each line. Thank you :).
MainSheet
...ANSWER
Answered 2021-May-19 at 06:25It is pretty simple actually once you understand the logic.
LOGIC:
- Identify your range.
- Get the range in an array.
- Loop through the array and extract left 4 characters and create a unique collection. This will also help us identify the number of sheets that needs to be created.
- Loop through the collection and create the sheets.
- Copy across the headers from main sheet to the newly created sheet.
- In the same loop, filter the data from main sheet based on the 4 charcters in the collection and copy across to the newly created sheet. More about this method is explained in How to copy a line in excel using a specific word and pasting to another excel sheet.
CODE:
I have commented the code but if you still face any issues, simply ask :)
QUESTION
I'm trying to use a for loop through iterate through a range of dates, and I was going to increment the start date using plusDays, but I get "cannot resolve method plusDays in Date". Here is my code:
...ANSWER
Answered 2021-Apr-27 at 14:29java.util.Date
is not java.time.LocalDate
java.util.Date
does not have a plusDays(1L)
function:
So if you work with Date you can increment using :
QUESTION
I have a workbook with many sheets. I'm trying to have a macro that copies two specific sheets together to a new workbook that does not yet exist. I'm terrible at VBA and the code I wrote below gets run-time error 13 for type mismatch. Can someone please help? Thanks!
...ANSWER
Answered 2021-Apr-24 at 01:35Your second
QUESTION
I have an app that uses a recyclerView to show results from Google Books API.
In every onBindViewHolder
, I ask the client to give me data which leads me eventually to exceeding the rate limit since every scroll calls data.
Let say I got data for position 1-5 and I scroll down to position 6-10 and then go back to 1-5. How can I make sure that it won't call the client again for positions 1-5 since it has already loaded them?
I just want whatever it already called to stay there.
My adapter looks like this ( I deleted some parts like more views so it wont confuse):
...ANSWER
Answered 2021-Apr-23 at 08:54Ok, I understood your problem. For every bookID, you fetch its data from Google Books, and now you want to not hit the api for already loaded items.
Simply, create a global variable for ArrayList
as
QUESTION
I'm working my university project and i have a 4 pages , I want to know how to disable scrolling option only specific page. I'm using following code part, but its apply overall pages. any one have a solution ?
...ANSWER
Answered 2021-Apr-23 at 08:41Yes, you can
QUESTION
I'm implementing a Google Script WebApp which will be able to filter a Google Sheet with a few parameters. What is happening is... I have a 30 columns approximately and each column would be a parameter. I thought this:
...ANSWER
Answered 2021-Mar-07 at 16:39Is this what you are trying to accomplish?
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