hendrix | Real-time correlation and alerting system for streaming data | Monitoring library

I think that's because there is a page literally. The exception may arise when there is no page to show on the browser. But when you make a request for this one:

You can ascertain this a number of ways, one way would be using exists

You're already pulling one line into a string at a time. Just check if that string starts with your comment characters and if so, continue:

• Change your property to List (List(Of String) in VB.NET).
  • While String[] (String() in VB.NET) should work, I personally have fewer issues when deserializing JSON to List - sometimes computers are spooky.
• You can also greatly simplify your VB.NET class definition to use Auto-Implemented Properties: there's no need for explicit fields and boilerplate getter/setter logic.
• Also, in .NET: public members (properties, methods) should be PascalCase, as should type-names.
  • You can use the JsonProperty attribute to specify explicit JSON property names if they don't exactly match the .NET class member names (Newtonsoft.Json is case-sensitive by default).
    • Another approach is to configure CamelCasePropertyNamesContractResolver but I personally prefer explicit [JsonProperty] attributes.

You can use diff/lag to calculate difference :

You were almost there. In fact, your database was empty. Why? Because of this line in your DBConfig class. prop.put("hibernate.hbm2ddl.auto", "create-drop"); (link to the documentation for this property). You can safely delete it or set the property to a value that makes sense for you.

You will also need to set the photo attribute (and the getters&setters for it) in your Singer class to Byte (This kind of type is also called a Wrapper Class) instead of byte since byte is a primitive value that cannot be set to null. In your DB script however, you allow photo to be null so, if you dont change this code, it will cause an exception when trying to map the DB columns into Java objects.Once youve down these two things, the list of singers will be shown in the browser.

Now, some final tips since you are somewhat new to programming and stackoverflow:

1. Read https://stackoverflow.com/help/how-to-ask carefully if you haven't already. It will help you write questions that people will want to answer and helps you avoid downvotes and being burried in stackoverflow.

2. I've checked out your repo and you're doing a lot of work and configuration that you do not have to do since you are using Spring Boot and Spring Boot Data Jpa and not simply Spring. I would encourage you to start using Spring Boot to its full extent first and then learn Spring and how to customize it to your needs, if you ever need solely Spring at all for your needs.Use this link as a gateway to learn more about Spring Boot and Spring Boot Data Jpa.

The easiest way to do this would be to get a list of all the keys in both the dictionaries and retrieve these values. In this case I have assumed the resultant dictionary such that each name is a key in a dictionary and each values is a dict of two keys info and error with their respective values (or 0 if it doesnt exist).

Anyways, the code for the same:

If key of object is variable you should use [] instead of dot.

One way