brouter | configurable OSM offline router with elevation awareness, Java + Android | Map library

by abrensch Java Version: v1.7.0 License: MIT

X-Ray Key Features Code Snippets Community Discussions(1)Vulnerabilities Install Support

kandi X-RAY | brouter Summary

brouter is a Java library typically used in Geo, Map applications. brouter has no vulnerabilities, it has build file available, it has a Permissive License and it has low support. However brouter has 111 bugs. You can download it from GitHub.

You can install the BRouter app on your Android device from [F-Droid] or [Google Play Store] You can also [build BRouter] #build-and-install) yourself. You can find detailed documentation of the BRouter Android app in [misc/readmes/readme.txt] misc/readmes/readme.txt). .

Support

Quality

Security

License

Reuse

Support

brouter has a low active ecosystem.

It has 367 star(s) with 92 fork(s). There are 33 watchers for this library.

It had no major release in the last 12 months.

There are 148 open issues and 179 have been closed. On average issues are closed in 282 days. There are 6 open pull requests and 0 closed requests.

It has a neutral sentiment in the developer community.

The latest version of brouter is v1.7.0

Quality

brouter has 111 bugs (30 blocker, 9 critical, 21 major, 51 minor) and 1560 code smells.

Security

brouter has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

brouter code analysis shows 0 unresolved vulnerabilities.

There are 16 security hotspots that need review.

License

brouter is licensed under the MIT License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

brouter releases are available to install and integrate.

Build file is available. You can build the component from source.

Installation instructions, examples and code snippets are available.

brouter saves you 12460 person hours of effort in developing the same functionality from scratch.

It has 25108 lines of code, 1223 functions and 189 files.

It has high code complexity. Code complexity directly impacts maintainability of the code.

Top functions reviewed by kandi - BETA

kandi has reviewed brouter and discovered the below as its top functions. This is intended to give you an instant insight into brouter implemented functionality, and help decide if they suit your requirements.

Find the track .
Add aional penalty to the given link .
Process all available voice hints .
Finalize the wayfile .
Recovers from two files .
Called when a touch event occurs .
Formats GeoJSON representation as a GeoJSON string .
Downloads the file and returns the response .
Parse the params from the params
Write node data .

Get all kandi verified functions for this library.

brouter Key Features

No Key Features are available at this moment for brouter.

brouter Examples and Code Snippets

No Code Snippets are available at this moment for brouter.

Community Discussions

Trending Discussions on brouter

I have to iterate some if-else conditions for each row in data-frame in python

QUESTION

I have to iterate some if-else conditions for each row in data-frame in python

Asked 2018-Jun-28 at 11:23

I have to iterate some if-else conditions for each row in dataframe in python.

If the first condition is satisfied for row1, it will answer 'yes' or 'no' by adding one more column for that row and exit.

But if for the row 2, with another other condition satisfied, it shouldn’t overwrite the first row’s ‘yes’ or ‘no’.

I want it to be preserved or we can say in second iteration it should check all if else conditions for only row2 and then row3 and so on.

To be precise, only one row will be check against all the condition and which ever condition satisfy, it will give the output by adding one more column for that row and exit.

I am new to python and the code I wrote is not working.

I have written the below code. Kindly help me.

...

ANSWER

Answered 2018-Jun-27 at 22:21

You shouldn't need to iterate rows explicitly. In fact, you shouldn't need to calculate the same Boolean values multiple times.

If you wish to prioritise a particular assignment given a condition, you can do so explicitly. Here's one way using numpy.where; we use ~ to indicate "negative".

Source https://stackoverflow.com/questions/51072138

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