kandi X-RAY | RegexToDFA Summary
kandi X-RAY | RegexToDFA Summary
converting regex (regular expression) to DFA directly by creating syntax tree in java
Top functions reviewed by kandi - BETA
- Generates the tree using the regular expression
- Adds the given regular expression to the regular expression
- Perform the concatenation operation
- Performs the operation
- The main entry point
- Get symbols for a regular expression
- Initializes the DFA using the given regular expression
- Create a DFA
- Add a follow position
- Show the follow position
- Add a number to the name
RegexToDFA Key Features
RegexToDFA Examples and Code Snippets
Trending Discussions on Regex
I have the following regex:
/\.([s]?[ac]ss)$/. The problem is, it matches
.ass. How would I make it not match
ANSWERAnswered 2022-Mar-02 at 08:35
You can use
I have an array of 5 numbers, I'd like to match as long as there are three of the same number and two of the same different number in the array, placement does not matter. Number sequences can be any random string of 5 numbers between 1 - 5.
Examples of matches would be:
*basically any grouping of 2 and 3 of the same numbers needs to match.
Best I've come up with so far:
I am not so good with regex, any help would be greatly appreciated....
ANSWERAnswered 2022-Jan-16 at 23:38
You can use
Currently, this is my code....
ANSWERAnswered 2022-Jan-06 at 04:57
A simple solution would be to convert all characters to lowercase, replace any character that isn't a-z, 0-9, or a space with a space character, and then replace multiple space characters with a single space character.
Expected output: "TenancyAccountAccountPublicIdWorkspaceWorkspacePublicIdRemove-userUserPublicId"
- replace any character with zero or more underscore to the non-underscored uppercase
x | __*x => X
- If exists remove last _
This is what is tried so far, looking for better alternatives, if any:...
ANSWERAnswered 2021-Dec-17 at 14:21
Split and slice
ANSWERAnswered 2021-Nov-16 at 14:57
Pattern.asPredicatewill return true if any part of the input string matches the Regular expression. You should use this method if you're testing some larger body of text for a certain pattern. For example, to test whether a comment from a user contains a hyperlink.
Pattern.asMatchPredicatewill return true if the entire input string matches the Regular expression. You should use this method if you're testing the entire input for a certain pattern. For example, to validate the phone number of a user in their profile.
Pattern.asPredicate internally uses
Pattern.asMatchPrediate internally uses
Matcher.matches(). So the difference between the two boils down to the difference between these two methods from the
Below are some examples to showcase the difference. You can copy & paste below code in an online Java sandbox like https://www.compilejava.net/ to play around with it yourself.
I am trying to replace a single occurrence of a character '1' in a String with a different character.
This same character can occur multiple times in the String which I am not interested in.
For example, in the below string I want to replace the single occurrence of 1 with 2....
ANSWERAnswered 2021-Nov-13 at 09:22
Use a negative lookahead in the regexp to match a
1 that isn't followed by another
I'm attempting to solve a very simple problem - find strings in an array which only contain certain letters. However, I've run up against something in the behavior of regular expressions and/or
grep that I don't get.
ANSWERAnswered 2021-Nov-02 at 13:15
fails are fixed with the addition of anchors
$ and quantifier
These both work:
I'm looking for a regexp that matches any line that contains 'B', 'R', 'A' and 'S' (in any order) at the start. It would match all the following lines, except the last two....
ANSWERAnswered 2021-Oct-30 at 21:05
There are only 24 permutations :)
I have a Json file having multiple comments and I want to replace a value in it.
I tried the below and it gives me a json file without comments. But I don't understand how to change the value and save it back with comments. Is this even possible because we are replacing all the comments with empty lines?...
ANSWERAnswered 2021-Oct-22 at 22:32
The header question may not be easy to understand. Hope you can understand my detailed info below.
I have sentence data below, that has some tags, represented by
ANSWERAnswered 2021-Oct-04 at 08:47
Here is a solution that assumes that there are no nested tags, that all tags open and close in the part. Also, this assumes that all characters from the sentence are in
parts. For this last assumption, I had to add the
. after it has to be in the second expected part. I also had to remove newline characters from the sentence but I think it was because of the copy/paste.
This solution will loop through all characters and store two parallel buffers : one with the tags, one without. We will use the second one to compare with the parts, and use the first one to generate the output.
No vulnerabilities reported
DStates is a Set of States which is used for creating the final dfa.
input is also a Set which holding the characters of the input regular expression taken from user. pay attention to this issue that, some characters like '*' can be used as an operator (closure, union, concatination, ...) so if you want to enter these characters just as a normal character, you could bring a backslash '\' following up the intended character for example "\*" meaning a normal '*' character. and "*" meaning star opeartor (closure) this is why we use a set of String for declaring input variable.
String regex = getRegex(); is for getting the intended regular expression from stdin.
getSymbols(regex); this line of code sets the input Set.
SyntaxTree st = new SyntaxTree(regex); and this line creates the corresponding syntax tree of the inputted regex.
root = st.getRoot(); gets the root of the syntax tree.
followPos = st.getFollowPos(); make a new refference to the Set of followpos variable.
State q0 = createDFA(); creates the DFA through using the syntax tree and assigns q0 the start state of resulted DFA.
DfaTraversal dfat = new DfaTraversal(q0, input); makes a new DFA Traversal object for traversing the resulted DFA and recognizing whether the DFA can accept a particular string or not.
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