lemon | 一个简单、轻量级的Android Socket框架。Android Socket Client Library | Socket library

I want the label to come to the center of the screen. label mean circle. I've found many ways that verticle-align : middle , text-align: center ... but i can't find solution...

I am new to Python, and I am trying to use Python to query a Microsoft SQL Server database. The data is returned in this format:

(('orange,apple,coconut',), ('lettuce,carrot,celery',), ('orange,lemon,strawberry',))

What I am trying to do is check to find a match, to see if some data from another data table exists in that data from SQL Server.

When I try to use the "in" to check, it does not work for me. I thought if I could convert the data (a tuple of tuples) into a list, then I could more easily search and match. But that doesn't work because there are some brackets around each list element. At least, that is the what I think because, if I manually recreate the list without the extra brackets, then I can search successfully.

I am wondering if there is a way to remove that extra bracket. Or, maybe there is a better approach. I have read several posts here and other articles, and so far, I have not found an approach.

Here is what I have tried. As you can see, the final one works, but that is what i have created manually.

I have a set of legacy data that has aimed to match companies together (based on a number of different factors). However, I would like to do a bit of QA on the matches just based on the names that came from the different profiles (and may have small differences).

Assuming a dataset as follows:

Is their an algorithmic or pythonic way to know for example that 1 and 2 are probably well matched and 3 badly matched? This, without any ML etc.

I would imagine I need to create a score somehow and knock out on this. However, would love some input if their is best practice.

Some ideas I have had is to look through patterns, compare letters in sets etc. However, at a lost to execute them.

I have a table with x num of rows, I have a second table with the same number of rows but different columns and metadata, they have different table models. but each row represents the same object (a song).

I want to synchronize row sorting between the two tables so for example if I sort on column 2 of table 1 then rows of the table will be sorted in the same order. But currently, I just have sorted by matching sort keys so sort on the same column (but because different data get different results)

e.g

Starting point

I'm trying to Use reactive bindings to bind the value of alcoholPercentageField to the progress property of alcoholBar. The progress bar will "full" when alcoholic content is set to 20 % and empty when the alcoholic content is 0

My Code-

So, I have the following XML file example:

I am trying to show only the first two rows of a CSS GRID.
The width of the container is unknown therefore it should be responsive.
Also the content of each box is unknown.

My current hacky solution is to define the following two rules:

• use an automatic height for the first two rows
• set the height of the next 277 rows to 0 height

grid-auto-rows: auto auto 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0;

I tried repeat() like this: grid-auto-rows: auto auto repeat(277, 0px) but unfortunately it didn't set the height to 0.

Is there any clean way to repeat height 0?

I have a table as indicated below where the Category column could have multiple categories each with its own scale which is shown in the Value column. I would like to create a new column that multiplies all the values where the item column does not equal 'scale' by the corresponding scale value that matches its category. In the example below: if Category = A then multiply the value by 10

I've been stuck with this for a while and would truly appreciate any help.

Note - there are hundreds of categories and each one could have a different value. In the actual data, the category is a date and for each of those dates, there is a corresponding scale value that the remainder of the data that matches that date will need to be multiplied by.

Original Table

New Column added