kandi X-RAY | simple-web-app Summary
kandi X-RAY | simple-web-app Summary
A simple Java web application that is built to learn the basics of JavaServer Pages (JSP).
Top functions reviewed by kandi - BETA
- Opens the connection
- Determines if the request should be done
- Gets a database connection
- Get a connection
- Closes a Connection
- Rolls back all exceptions
- Store connection in request attribute
- Check user account
- Retrieves the user name from the cookie
- Handles GET calls
- Gets the product view
- Sets the request encoding
simple-web-app Key Features
simple-web-app Examples and Code Snippets
Trending Discussions on simple-web-app
I'm creating a Chrome extension with React which uses an Airtable database, copying code verbatim from a tutorial. In my app.js, I am following directions for adding a method called 'componentDidMount' underneath a constructor method, which calls the Airtable API to get the data values from it.
I'm receiving an error on the opening curly brace in the first line:...
ANSWERAnswered 2019-May-29 at 06:12
componentDidMount() should go inside the
class App (where the constructor is):
I am converting a Spring MVC app to Spring Boot. The Spring app has a Home controller:...
ANSWERAnswered 2019-Jan-29 at 08:11
In Spring framework, if you want to write a String to the response body then you'll use the keyword
@ResponseBody. From the documentation
@ResponseBody annotation and, therefore, writes directly to the response body versus view resolution and rendering with an HTML template.
Or, in your case, the
@RestController annotation that is
A convenience annotation that is itself annotated with @Controller and @ResponseBody.
If you don't use this keyword then Spring will search for a file with the given path. For this it uses a
viewResolver. See 16.5 Views and resolving them
Here is an exemple where you can see the property that allow Spring to resolve the real path of your file :
I am trying to access it using simple-web-app. Simple-web-app now can see the OIDC app. It still asks for user/pwd even though I am logged in in the OIDC app. When I enter these I now get the following error. I can't find any help. Anyone have any idea?...
ANSWERAnswered 2018-Dec-19 at 14:59
I think you have an incompatibility between the latest mitreid sample app (which is bleeding edge as far as mitreid goes) and the spring boot fork of mitreid server from 2 years ago. E.g. the model for SystemScope changed here on the main mitreid project https://github.com/mitreid-connect/OpenID-Connect-Java-Spring-Server/commit/b17a7f43ae9a94592132a0336248631fe5914508
You'll probably hit a number of these as the spring-boot fork is not being kept up-to-date
I am using the Spring Boot MitreID OIDC application from here. This runs OK and I can login but there are no other options available to me:
I am trying to access it using simple-web-app. In simple-web-app I try to login using URI: http://localhost:8080/openid-connect-server-webapp/. This gives:...
ANSWERAnswered 2018-Dec-19 at 12:48
MitreID is serving on root but sample app is calling on /openid-connect-server-webapp/ You'll want to change your sample app to point to the proper issuer....http://localhost:8080/ (maybe in the application.properties of your sample app?) Or your MitreID server is not configured properly (possibly for issuer property)
See http://localhost:8080/.well-known/openid-configuration for all the endpoints your sample app would hit
I am trying to get OIDC working with Java Spring Boot. Specifically the example app here.
I am a newbie to this stuff, so can anyone give me brief instructions on how to run that app?
I have it in Eclipse (with STS4) as existing maven project (as per these instructions). When I run it I pick 'Java application' which gives me some examples including version, Licence, roller etc etc. I do not know which, if any, of these is correct, nor how do I pass parameters etc. Any pointers are gratefully received....
ANSWERAnswered 2018-Dec-18 at 12:28
From the project overview list, pick the Application class. Right-click on it to open the context menu and choose "Run as -> Spring Boot App". Have fun.
Only ultimate has web application support so that's out of the way.
I am trying to start ope up my web app via tomcat something wich i do succesfully on the same machine on netbeans with next to no configuration.
all possible combinations with EE and non EE remote and local.
none of which work.
I've done this : Cannot run/debug jsp page from within IntelliJ using Tomcat server
but nothing gives way.
Running tomcat local (first thing I tried and what I would have bet on. Chrome actually opens but the page cannot be found.)
Which is more promissing because tomcat if acually found if I manually navigate to index.jsp :
but no other url works. not the project path not its path plus index.jsp :
Running tomcat remote :
same for TomEE local runs but fails to find webpage. remote fails to run with same error message. though unless the terminology is seriously *** up (I've seen app makers go this far before) what I want is local.
ANSWERAnswered 2017-Aug-19 at 23:04
Have you selected an artifact in the Deployment tab? If not add an artifact. After that, you should be able to request your site.
So you need to do: Open the configuration -> go to the Deployment tab -> add the artifact you want to deploy on the tomcat.
Restart tomcat and done you should be able to request your side :)
No vulnerabilities reported
You can use simple-web-app like any standard Java library. Please include the the jar files in your classpath. You can also use any IDE and you can run and debug the simple-web-app component as you would do with any other Java program. Best practice is to use a build tool that supports dependency management such as Maven or Gradle. For Maven installation, please refer maven.apache.org. For Gradle installation, please refer gradle.org .
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