lcm | Lightweight Communications | Networking library
kandi X-RAY | lcm Summary
kandi X-RAY | lcm Summary
Lightweight Communications and Marshalling (LCM). LCM is a set of libraries and tools for message passing and data marshalling, targeted at real-time systems where high-bandwidth and low latency are critical. It provides a publish/subscribe message passing model and automatic marshalling/unmarshalling code generation with bindings for applications in a variety of programming languages.
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Top functions reviewed by kandi - BETA
- Get the custom error bars
- Sets the absolute error
- Sets the absolute error value
- Customize the custom error bars
- Set the relative x error value
- Set the Y error value
- Entry point for testing purposes
- Creates a deep clone of this color
- Paint the bar
- Draws a Bookmark
- Creates an arrow image
- Called when the mouse is pressed
- Paint the title of axis
- Finds a filename based on the given name
- Creates a zoomable chart
- Main entry point
- Main method for testing
- Paint the panel
- Called when the menu item is pressed
- Paint the error bar
- Compares this object to another
- Removes all redundant line breaks from a file
- Returns the maximum amount of characters in this currency
- Creates a hashCode of this object
- Main entry point
- Listener for the background of the chart
lcm Key Features
lcm Examples and Code Snippets
public static OptionalInt lcm(int[] numbers) {
IntBinaryOperator lcm = (x, y) -> (x * y) / gcd(x, y);
return Arrays.stream(numbers)
.reduce((a, b) -> lcm.applyAsInt(a, b));
}
private static int gcd(int a, int b) {
if (b
def test_lcm_function(self):
for i, (first_num, second_num) in enumerate(self.test_inputs):
slow_result = least_common_multiple_slow(first_num, second_num)
fast_result = least_common_multiple_fast(first_num, second_num
public static OptionalInt lcm(int[] numbers) {
IntBinaryOperator lcm = (x, y) -> (x * y) / gcd(x, y);
return Arrays.stream(numbers)
.reduce((a, b) -> lcm.applyAsInt(a, b));
}
public static int lcmByLambda(int... numbers) {
return Arrays.stream(numbers).reduce(1, (lcmSoFar, currentNumber) -> Math.abs(lcmSoFar * currentNumber) / gcd(lcmSoFar, currentNumber));
}
Community Discussions
Trending Discussions on lcm
QUESTION
This is my source code, which I try to pass to the least common multiplier task:
...ANSWER
Answered 2021-May-24 at 09:32what about negative numbers? Try calculating the GCD(abs(x), abs(y)), it's the same as GCD(x, y)
QUESTION
I want to find out Least Common Multiple(LCM) of more than two numbers. I know the formula of lcm(a,b) = (a * b) / gcd(a,b). Let's say, I have an array of numbers: [2, 6, 8, 13] and the the lcm should be modulo M = 1000000007.
I have seen below code to calculate the LCM of multiple numbers but I am not understanding how the calculation is going on with both the loops.
...ANSWER
Answered 2021-May-16 at 19:46gcd(a, b)
represents the product of all the prime factors shared by a
and b
, what is the significance of a / gcd(a,b)
?
a / gcd(a, b)
is equal to the prime factors of a
that are not in b
.
Therefore, when you multiple that quantity by b
, you get a product of all the prime factors of b
and all the prime factors of a
that are not in b
. This is precisely lcm(a, b)
.
The lcm(a, b)
is a
times all the prime factors of b
not in a
or:
QUESTION
How do I visualize different coordinate frames in drake when using the LCM visualizer, such as the body frame attached to the end effector of the Kuka?
...ANSWER
Answered 2021-May-08 at 13:41Here's some simple code for drawing frames in Drake Visualizer, w/ simple video:
https://github.com/EricCousineau-TRI/repro/blob/ea2d7987/drake_stuff/drake_viz_draw_frames/README.md
Does this help at all? If so, yeah, I can help to PR against Drake.
Some notes / caveats:
- This doesn't draw
pydrake.geometry.FrameId
as doesmeshcat
; instead, it simply draws a frame (whatever you name it) usingRigidTransform
, w.r.t. world frame. - This is unlike things like
/tf
in ROS, where you can publish a frame w.r.t. another frame.
QUESTION
I hope you are doing well, I start using OpenNebula here, I deploy a basic setup one Opennebula fronend in centos 8 another server as OpenNebula Node, I download an image from marketplace it's centos image, Then I create a network Under Network >> Virual Network. Bridge it with ens33 (ens3 is the physical interface of my node) in order to give VM access to LAN, he is my Node net
...ANSWER
Answered 2021-May-04 at 09:02The problem here is that you are using a physical interface instead of using a bridge. If you would like to use bridge networking, you need to create a bridge or let OpenNebula create it for you.
Let me know if this answers your issue, if not, feel free to submit your query on OpenNebula Forum - https://forum.opennebula.io/. :)
QUESTION
I am trying to solve this kata on Codewars: https://www.codewars.com/kata/56e56756404bb1c950000992/train/javascript, and I have a method that I think should be correct, but it throws a RangeError. This is my code:
...ANSWER
Answered 2021-May-01 at 16:34I'm not sure I get any of the maths stuff here, but skipping zeros seems to stop it from trying to recurse forever.
Anything % 0 will give NaN
and probably anything % NaN will give NaN
and NaN == 0 is false, so if you start with a zero value entering GCD there's no way for the recursion to terminate.
QUESTION
My function for finding LCM does not work. Is there a problem with the while loop?
...ANSWER
Answered 2021-Mar-23 at 10:06Your lcm logic is wrong the condition you used in while loop is wrong. LCM logic should be like,
QUESTION
I am trying to understand how the pos_weight
argument is being used in BCEWithLogitsLoss
in order to be able to correctly define the pos_weight
Tensor. The documentation only mentions: "a weight of positive examples. Must be a vector with length equal to the number of classes.". As I was not able to get a sufficient understanding by looking at the code (the actual code is hidden behind multiple function loaders and I didn't even manage to reach a point where pos_weight
is used), I have several questions regarding the pos_weight
argument:
- Is the weight for negative samples always 1?
- If the weight for negative samples is always 1 and assuming I want every sample to contribute equally to the loss I would do something like the following. Let
l = [100, 10, 5, 15]
wherel[0]
is the amount of negative samples andl[1:]
is the amount of positive samples from each label. In pseudo code this looks like:
ANSWER
Answered 2021-Mar-19 at 10:03I didn't manage to find a definitive answer but from my experiments it seems I was right, i.e. negative sample weights are considered to be 1 and increasing the weights past 1 for positive samples makes them more important. Additionally, the LCM approach for figuring out the weights is actually both not good and not needed. First it is bad because if you have a lot of classes with different number of samples the LCM can be an incredibly large number so very often computing it exactly is not even feasible. Additionally, it is not needed because you achieve the same weights by simply dividing the amount of negative samples with the amount of positive samples for every label and obtain the weights in that manner. Here is a short code snippet on how you can obtain the weights if you have your data in pandas DataFrame. Obtaining the weights in this way results in a 'balanced' dataset where ideally you optimize for both precision and recall.
QUESTION
I have a column with a bunch of unformatted XML code. I am trying to really just query 1 value out of the column. The value inside of the column is listed below:
...ANSWER
Answered 2021-Mar-15 at 17:31Please try the following solution. It is for MS SQL Server.
Amazingly enough, the provided XML has no namespaces. Though it was an attempt to use a namespace.
SQL
QUESTION
For my learning testlab I have a simple DSC configuration. I am creating VMs and have them running the following ps1 on first startup to rename the system to the VM's name.
...ANSWER
Answered 2021-Mar-02 at 11:19Set-DscLocalConfigurationManager -Path ".\PrepareVM" -Force
QUESTION
I have a pyspark data frame as
...ANSWER
Answered 2021-Feb-22 at 08:05You can use replace
on dataframe to replace the values in colC
by passing a dict object for the mappings. And round
function to limit the number of decimals in colB
:
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install lcm
You can use lcm like any standard Java library. Please include the the jar files in your classpath. You can also use any IDE and you can run and debug the lcm component as you would do with any other Java program. Best practice is to use a build tool that supports dependency management such as Maven or Gradle. For Maven installation, please refer maven.apache.org. For Gradle installation, please refer gradle.org .
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