blog2 | 个人博客2.0源码 - 个人博客2 | Blog library

For example, when I open a topic, it would open in the same html page, not redirect to another address: http://web.archive.org/web/20090409012115/http://www.europeangoldfinch.net/home.htm#

I want to make it exactly like this (clicking on a topic). I downloaded the source files from web archive, but when I click on topic nothing opens up even though the topic text is in that html code.

This is exactly what I want to do: https://errorsea.com/how-to-change-text-onclick-event-javascript/#Syntax

EDIT: Thanks everyone for the help, I figured it out, I downloaded a website from web.archive.org, and it didn't work well, but I managed to get it working with the javascript included with the website.

Code:

I am new in Python Flask and I am trying to design my personal blog. Since it is only for private use, I would like to put the "add" page for post as protected area with a username and a password just for to add and manage my posts. In order not to show the login credentials in the source code, I decided to store in a .yaml file and retrieve them ({"Franz":{"pw":"Biberkopf"}}) through the function login.

But when I put "Franz" as username and "Biberkopf" as password, I get this error:

werkzeug.exceptions.BadRequestKeyError

werkzeug.exceptions.BadRequestKeyError: 400 Bad Request: The browser (or proxy) sent a request that this server could not understand.
KeyError: 'pw'

Traceback (most recent call last)

File "C:\Users\franc\AppData\Local\Programs\Python\Python38-32\Lib\site-packages\flask\app.py", line 2464, in call

return self.wsgi_app(environ, start_response)

File "C:\Users\franc\AppData\Local\Programs\Python\Python38-32\Lib\site-packages\flask\app.py", line 2450, in wsgi_app

response = self.handle_exception(e)

File "C:\Users\franc\AppData\Local\Programs\Python\Python38-32\Lib\site-packages\flask\app.py", line 1867, in handle_exception

reraise(exc_type, exc_value, tb)

File "C:\Users\franc\AppData\Local\Programs\Python\Python38-32\Lib\site-packages\flask_compat.py", line 39, in reraise

raise value

File "C:\Users\franc\AppData\Local\Programs\Python\Python38-32\Lib\site-packages\flask\app.py", line 2447, in wsgi_app

response = self.full_dispatch_request()

File "C:\Users\franc\AppData\Local\Programs\Python\Python38-32\Lib\site-packages\flask\app.py", line 1952, in full_dispatch_request

rv = self.handle_user_exception(e)

File "C:\Users\franc\AppData\Local\Programs\Python\Python38-32\Lib\site-packages\flask\app.py", line 1821, in handle_user_exception

reraise(exc_type, exc_value, tb)

File "C:\Users\franc\AppData\Local\Programs\Python\Python38-32\Lib\site-packages\flask_compat.py", line 39, in reraise

raise value

File "C:\Users\franc\AppData\Local\Programs\Python\Python38-32\Lib\site-packages\flask\app.py", line 1950, in full_dispatch_request

rv = self.dispatch_request()

File "C:\Users\franc\AppData\Local\Programs\Python\Python38-32\Lib\site-packages\flask\app.py", line 1936, in dispatch_request

return self.view_functionsrule.endpoint

File "C:\Users\franc\OneDrive\Desktop\Blog_Project\blog_prova.py", line 102, in login

user.id = username
flask_login.login_user(user)
return redirect(url_for("add"))
else:
error = "Leider haben Sie die falschen Zugangsdaten."
return render_template("login.html", error=error)
return render_template("login.html")

Code:

I need help in coming up with a creative idea/way to transform the carousel indicators into a menu or any other possible way of making the whole section mobile responsive with all the indicators present within the mobile width. I have tried multiple ways that haven't worked. I am kinda new to programming where I wanted to challenge myself but making it responsive became difficult for me. As you can see when running the code, day one is not visible and also day 8 is overlapping. I'll be happy to get a solution for a project I am doing.

• Node.js project with Mongoose and Pug as the templating engine

Example JSON content (fetched with Mongoose)

I am having a navbar and a side bar for my page.

Navbar consists of home and blogs

Blogs will render BlogHome Component which will fetch links from db and on click of any link will render BlogContent component.

Lets say the side bar has Blog1,Blog2 and Blog3 listed. If I click Blog1 it renders Blog1's content properly to its side, but if I click Blog2 again it just changes URL but not the Blog2's content.

Please take a look at my code:

Navbar.js

I want to change the delimiter of the QualifiedName from '.' to '#'. Below is my try. The following example from the online documentation.

I have a Jekyll site that uses the jekyll-paginate plugin and is hosted by GitHub Pages, pretty standard.

Does anybody know of other solutions to handle pagination such that I could build two blogs from the same site at domain/blog1 and domain/blog2 using this solution, but also retain pagination?

Retaining the current pagination design is not a priority. Creative ideas that require redesign are welcome.

I know jekyll-paginate-multiple exists, but GitHub Pages does not support it natively, and I would have to maintain two repos to maintain the site code and build artifacts separately, which is not ideal.

I have checked other questions covering the topic such as this, this, this, this and this as well as some great blog posts, blog1, blog2 and blog3 (kudos to respective author) but without success.

What I want to do is to transform rows whose values are under a certain threshold in X, but only those that correspond to some specific classes in the target y (y != 9). The threshold is calculated based on the other class (y == 9). However, I have problems understanding how to implement this properly.

As I want to do parameter tuning and cross-validation on this I will have to do the transformation using a pipeline. My custom transformer class looks like below. Note that I haven't included TransformerMixin as I believe I need to take into account for y in the fit_transform() function.

Puppet: 5.3.3
OS: Ubuntu Xenial (virtual box) Inbuilt RAM: 4GB

I am new to Puppet. After installing Puppet v5.3.3, I wanted to start the server:

systemctl start puppetserver (or service puppetserver start)

This gave me following error:
Job for puppetserver.service failed because the control process exited with error code. See "systemctl status puppetserver.service" and "journalctl -xe" for details.

systemctl status puppetserver.service