asorted | Fast and efficient sorted arrays in JavaScript
kandi X-RAY | asorted Summary
kandi X-RAY | asorted Summary
Fast sorted array in Javascript. Uses binary search for addition and deletion.
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QUESTION
I have a vector a
of known size N, so that np.sum(a)
is 1, and np.all(a>=0)
is true. I want to determine the minimum number of entries that sum a threshold t
. For instance, I would do something like:
ANSWER
Answered 2020-Mar-12 at 20:18Depending on the length of the arrays, maybe sort, and then you could use a cumulative sum? It would at least be faster than that while loop.
QUESTION
I want to return a sorted list but it gives me this error. What should I do?
...ANSWER
Answered 2018-Feb-20 at 07:11Returning A.Sort
does not return the sorted array, it returns the Sort
command's return value. Since Sort
is a void
method, it actually returns nothing, hence the error message.
So to return the sorted array, you need to return it after you sort it:
QUESTION
My aim is to write a subroutine which takes in
- An array of hashes
- A list containing the sort order
Just to be clear - the keys may be anything. My example is just for reference.
Given an array containing a list of keys in their required sort order
...ANSWER
Answered 2018-Jan-03 at 16:04Well, you're quite right - using eval
like that is a road to future pain.
The joy of 'sort' is that you can define a sort subroutine, that implicitly defines $a
and $b
and you can use whatever logic you desire to decide if it's a positive, negative or 'zero' comparison (equal). (e.g. like <=>
or cmp
do).
The trick here is - 'true' is anything non zero, so <=>
you can test for 'true' to see if there's a comparison to be made ( 4 <=> 4
is 'false')
So if you're just working numerically (you'd need to test for 'alphanumeric' and use cmp
in some cases there, but doesn't seem to apply to your data):
QUESTION
I want to select 2 minimum elements from every column of matrix. How to can display number of row? input:
...ANSWER
Answered 2017-Feb-01 at 20:41Let me guess, is this what you want to do?
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