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QUESTION
I want to go from this:
name pet 1 Rashida dog 2 Rashida cat 3 Jim dog 4 JIm dogto this:
name num_dogs num_cats 1 Jim 2 0 2 Rashida 1 1In R I would do
...ANSWER
Answered 2021-Jan-22 at 20:50There are lots of different ways to do this.
If you are filtering the value of a single column, then you can use the .agg with a custom lambda function.
QUESTION
I'm making a program where I'm entering an activity hours for dogs and then sums the hour for each activity and after that the program print each dog one after another from the dog with higher sum of hours of activites to the lowest now I did sort the list and made a print function , but still doesn't work , it prints either 2 of them if the first dog I entered has the highest sum of hours and the seconde is the lowers in the right order, but if there first dog was the one with the lowest and the seconde one was the one with the highest it just prints the first dog ( the loswet one) and doesn't even print the seconde dog.
input:
...ANSWER
Answered 2021-Jun-14 at 16:07When you find the new place where to insert the new dog, you walk the list if there is a next dog and if the new dog's grade is below the current dog's grade. (I've renamed the two iterators curr
and prev
for clarity.)
When you insert the new dog, p
, the next dog is the current dog, p->next = curr
. If the current dog's grade is the smallest of if the list was empty, curr
is NULL
, which is fine. You don't need to treat an empty list as special case.
Now, if prev == NULL
, your new dog ist the current best. There is no previous node, so update the head pointer via *fitBarkList
. Otherwise, update the next
field of the previous node:
QUESTION
I'm very new to C# and Linq so please forgive if I misuse terminology. As I tried to phrase in my title I would like to supply a Linq query with a List and have it return a List of objects who have a property that is also a List. The query should look at the property of the objects and return the objects whose lists contain all the values of the query list. Here's a simplified example I'm trying to set up in a command line app.
...ANSWER
Answered 2021-Jun-14 at 03:14It seems what you want this:
QUESTION
In Realm, I had problem understanding ( Im new in Realm T,T ) the implementations of LinkingObjects , let's say a Person could have more than one Dog ( List of Dog ) so I would write the code such as below:
...ANSWER
Answered 2021-Jun-13 at 15:23You can think of LinkingObjects almost as a computed property - it automagically creates an inverse link to the parent object when the child object is added to the parent objects List.
So when a Dog is added to a person's dogs list, a person reference is added to the Dog's walkers list. Keeping in mind that it's a many to many relationship so technically if Person A adds Doggo, and Person B adds Doggo, the Doggo's inverse relationship 'walkers' will contain Person A and Person B
the app still can run normally without any diff
Which is true, it doesn't affect he operation of the app. HOWEVER the difference is that by removing the walkers LinkingObjects, there's no way to query Dogs for their Person and get Dog Results (i.e. you can't traverse the graph of the relationship back to the person)
In other words we can query Person for kinds of dog stuff
QUESTION
In this challenge, using javaScript you will create 3 classes
- Super class called
Animal
. Dog
andCat
class which both extendsAnimal
class (a dog is an animal and a cat is an animal)Dog
andCat
class should only have 1 function, which is their own implementation of thesound()
function. This is polymorphism- a
Home
class. But we’ll talk about that later
ANSWER
Answered 2021-Jun-05 at 13:48Since 2015 there should be no more need to go through the pain of assigning prototype
properties like that, and establish inheritance between two classes with such assignments.
I would suggest rewriting your code completely, and using the class
syntax, where you don't need to explicitly do this inheritance fiddling with the prototype
property:
QUESTION
How do I make a kotlin class that takes an input arg (string) and appends it to the growing list within itself? For example, a person can buy a dog. Person is a class, and a dog name is an arg. Then the person buys a 2nd dog which gets appended within the Person class. SO you query person.dogs and now there are two dogs.
Thanks for helping.
...ANSWER
Answered 2021-Jun-12 at 19:58There are two ways to append elements to a growing list:
- List approach: On addition of a new element, return a new
List
, usingList.plus
method, with both the existing elements and the newer one - MutableList approach: Simply add the new element to a
MutableList
, using theMutableList.add
method
Hope the following code snippet explains how both approaches work:
QUESTION
I am using bootstrap-5. I couldn't find it a solution. How can this work for top and bottom, but not for right and left? Can you please help me? Okay as a default, there may be a value for bootstrap, but i am changing it on css. So what I wrote there must have worked I think. How can I get it worked?
...ANSWER
Answered 2021-Jan-04 at 17:28try bootstrap classes such as m-1, px-1, m-2, etc...
QUESTION
Let's say I have a collection called "pets"
The collection contains three different types of pets: cat, dog, and bird
Now let's say there are 10 cats, 10 dogs, and 10 birds in the collection (30 documents in total).
Is there a way to make a single query to pets that gets me 3 cats, 2 dogs, and 1 bird?
Basically I want to specify each type of pet I want, and limit each type of pet to a specific number, all in one query. The reason for this is because I want to be efficient and not make many queries.
This is what I have currently:
...ANSWER
Answered 2021-Jun-12 at 01:33Thanks to prasad_, here is the solution that solves my case:
QUESTION
I have a dictionary with questions as keys and answer option lists as values.
...ANSWER
Answered 2021-Jun-11 at 18:29There is in fact 8 possiblities 2**3
that you can get with itertools.product
QUESTION
Lets say I have a csv file which looks like this:
...ANSWER
Answered 2021-Jun-10 at 10:07Sure there is. Hope this helps, I've tried to be liberal with comments.
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