dogs | blog - 博客 | Blog library

 by   Dongss JavaScript Version: Current License: No License

kandi X-RAY | dogs Summary

kandi X-RAY | dogs Summary

dogs is a JavaScript library typically used in Web Site, Blog applications. dogs has no bugs, it has no vulnerabilities and it has low support. You can download it from GitHub.

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            kandi-support Support

              dogs has a low active ecosystem.
              It has 16 star(s) with 10 fork(s). There are 4 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 0 open issues and 7 have been closed. On average issues are closed in 223 days. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of dogs is current.

            kandi-Quality Quality

              dogs has 0 bugs and 0 code smells.

            kandi-Security Security

              dogs has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              dogs code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              dogs does not have a standard license declared.
              Check the repository for any license declaration and review the terms closely.
              OutlinedDot
              Without a license, all rights are reserved, and you cannot use the library in your applications.

            kandi-Reuse Reuse

              dogs releases are not available. You will need to build from source code and install.

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            dogs Key Features

            No Key Features are available at this moment for dogs.

            dogs Examples and Code Snippets

            No Code Snippets are available at this moment for dogs.

            Community Discussions

            QUESTION

            Aggregate multiple columns of qualitative data using pandas?
            Asked 2021-Jun-15 at 05:42

            I want to go from this:

            name pet 1 Rashida dog 2 Rashida cat 3 Jim dog 4 JIm dog

            to this:

            name num_dogs num_cats 1 Jim 2 0 2 Rashida 1 1

            In R I would do

            ...

            ANSWER

            Answered 2021-Jan-22 at 20:50

            There are lots of different ways to do this.

            If you are filtering the value of a single column, then you can use the .agg with a custom lambda function.

            Source https://stackoverflow.com/questions/65837805

            QUESTION

            problem with printing my sorted struct list
            Asked 2021-Jun-14 at 16:07

            I'm making a program where I'm entering an activity hours for dogs and then sums the hour for each activity and after that the program print each dog one after another from the dog with higher sum of hours of activites to the lowest now I did sort the list and made a print function , but still doesn't work , it prints either 2 of them if the first dog I entered has the highest sum of hours and the seconde is the lowers in the right order, but if there first dog was the one with the lowest and the seconde one was the one with the highest it just prints the first dog ( the loswet one) and doesn't even print the seconde dog.

            input:

            ...

            ANSWER

            Answered 2021-Jun-14 at 16:07

            When you find the new place where to insert the new dog, you walk the list if there is a next dog and if the new dog's grade is below the current dog's grade. (I've renamed the two iterators curr and prev for clarity.)

            When you insert the new dog, p, the next dog is the current dog, p->next = curr. If the current dog's grade is the smallest of if the list was empty, curr is NULL, which is fine. You don't need to treat an empty list as special case.

            Now, if prev == NULL, your new dog ist the current best. There is no previous node, so update the head pointer via *fitBarkList. Otherwise, update the next field of the previous node:

            Source https://stackoverflow.com/questions/67972230

            QUESTION

            Linq query that returns obj results after comparing an input List against a List that is a property of an object
            Asked 2021-Jun-14 at 03:14

            I'm very new to C# and Linq so please forgive if I misuse terminology. As I tried to phrase in my title I would like to supply a Linq query with a List and have it return a List of objects who have a property that is also a List. The query should look at the property of the objects and return the objects whose lists contain all the values of the query list. Here's a simplified example I'm trying to set up in a command line app.

            ...

            ANSWER

            Answered 2021-Jun-14 at 03:14

            It seems what you want this:

            Source https://stackoverflow.com/questions/67964114

            QUESTION

            Understanding LinkingObjects in Realm Xcode 12, Also when to use it
            Asked 2021-Jun-13 at 15:23

            In Realm, I had problem understanding ( Im new in Realm T,T ) the implementations of LinkingObjects , let's say a Person could have more than one Dog ( List of Dog ) so I would write the code such as below:

            ...

            ANSWER

            Answered 2021-Jun-13 at 15:23

            You can think of LinkingObjects almost as a computed property - it automagically creates an inverse link to the parent object when the child object is added to the parent objects List.

            So when a Dog is added to a person's dogs list, a person reference is added to the Dog's walkers list. Keeping in mind that it's a many to many relationship so technically if Person A adds Doggo, and Person B adds Doggo, the Doggo's inverse relationship 'walkers' will contain Person A and Person B

            the app still can run normally without any diff

            Which is true, it doesn't affect he operation of the app. HOWEVER the difference is that by removing the walkers LinkingObjects, there's no way to query Dogs for their Person and get Dog Results (i.e. you can't traverse the graph of the relationship back to the person)

            In other words we can query Person for kinds of dog stuff

            Source https://stackoverflow.com/questions/67950349

            QUESTION

            I want to solve the javascript OOP problems, but my code isn't complete
            Asked 2021-Jun-13 at 13:15

            In this challenge, using javaScript you will create 3 classes

            1. Super class called Animal.
            2. Dog and Cat class which both extends Animal class (a dog is an animal and a cat is an animal)
            3. Dog and Cat class should only have 1 function, which is their own implementation of the sound() function. This is polymorphism
            4. a Home class. But we’ll talk about that later
            ...

            ANSWER

            Answered 2021-Jun-05 at 13:48

            Since 2015 there should be no more need to go through the pain of assigning prototype properties like that, and establish inheritance between two classes with such assignments.

            I would suggest rewriting your code completely, and using the class syntax, where you don't need to explicitly do this inheritance fiddling with the prototype property:

            Source https://stackoverflow.com/questions/67850125

            QUESTION

            How to make a Kotlin class with method to append argument
            Asked 2021-Jun-12 at 19:58

            How do I make a kotlin class that takes an input arg (string) and appends it to the growing list within itself? For example, a person can buy a dog. Person is a class, and a dog name is an arg. Then the person buys a 2nd dog which gets appended within the Person class. SO you query person.dogs and now there are two dogs.

            Thanks for helping.

            ...

            ANSWER

            Answered 2021-Jun-12 at 19:58

            There are two ways to append elements to a growing list:

            1. List approach: On addition of a new element, return a new List, using List.plus method, with both the existing elements and the newer one
            2. MutableList approach: Simply add the new element to a MutableList, using the MutableList.add method

            Hope the following code snippet explains how both approaches work:

            Source https://stackoverflow.com/questions/67948437

            QUESTION

            In my class thats container-fluid, I can do padding for top and bottom, but it doesn't work for right and left?
            Asked 2021-Jun-12 at 18:39

            I am using bootstrap-5. I couldn't find it a solution. How can this work for top and bottom, but not for right and left? Can you please help me? Okay as a default, there may be a value for bootstrap, but i am changing it on css. So what I wrote there must have worked I think. How can I get it worked?

            ...

            ANSWER

            Answered 2021-Jan-04 at 17:28

            try bootstrap classes such as m-1, px-1, m-2, etc...

            Source https://stackoverflow.com/questions/65566967

            QUESTION

            Is there a way to make a single query in MongoDB for different types of documents and limit each type to a specific number in one collection?
            Asked 2021-Jun-12 at 01:33

            Let's say I have a collection called "pets"

            The collection contains three different types of pets: cat, dog, and bird

            Now let's say there are 10 cats, 10 dogs, and 10 birds in the collection (30 documents in total).

            Is there a way to make a single query to pets that gets me 3 cats, 2 dogs, and 1 bird?

            Basically I want to specify each type of pet I want, and limit each type of pet to a specific number, all in one query. The reason for this is because I want to be efficient and not make many queries.

            This is what I have currently:

            ...

            ANSWER

            Answered 2021-Jun-12 at 01:33

            Thanks to prasad_, here is the solution that solves my case:

            Source https://stackoverflow.com/questions/67930240

            QUESTION

            Get all possible combinations of quiz answers
            Asked 2021-Jun-11 at 18:52

            I have a dictionary with questions as keys and answer option lists as values.

            ...

            ANSWER

            Answered 2021-Jun-11 at 18:29

            There is in fact 8 possiblities 2**3 that you can get with itertools.product

            Source https://stackoverflow.com/questions/67941921

            QUESTION

            Filter dictionary values by strings in python
            Asked 2021-Jun-10 at 10:07

            Lets say I have a csv file which looks like this:

            ...

            ANSWER

            Answered 2021-Jun-10 at 10:07

            Sure there is. Hope this helps, I've tried to be liberal with comments.

            Source https://stackoverflow.com/questions/67918902

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install dogs

            You can download it from GitHub.

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          • CLI

            gh repo clone Dongss/dogs

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            git@github.com:Dongss/dogs.git

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