PasswordGenerator | Password Generator HW3 JS

 by   Lusio7 JavaScript Version: Current License: No License

kandi X-RAY | PasswordGenerator Summary

kandi X-RAY | PasswordGenerator Summary

PasswordGenerator is a JavaScript library. PasswordGenerator has no bugs, it has no vulnerabilities and it has low support. You can download it from GitHub.

Password Generator HW3 JS. Problem: HTML and CSS build to match design and layouit of example Solution: Follow guidelines and build as indicated. Problem: get elements by id's created in the HTML Solution: retrieve elements with get element functions. Problem: generate random loop through symbols, uppercase, lowercase and numerals Solution: create random fuction to loop through array. Problem: clipboard needs to know when clicked Solution: add event listener to clipboard button. Problem: generate password also needs to know when clicked Solution: add event listener to generate password button. Problem: how to generate the password Solution: create function to generate password by running through array. Problem: creating a loop Solution: for accessing typescount and the funcName also creating functions to get all the random variables: symbol, number, uppercase and lowercase.
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            kandi-support Support

              PasswordGenerator has a low active ecosystem.
              It has 6 star(s) with 0 fork(s). There are 1 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              PasswordGenerator has no issues reported. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of PasswordGenerator is current.

            kandi-Quality Quality

              PasswordGenerator has no bugs reported.

            kandi-Security Security

              PasswordGenerator has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              PasswordGenerator does not have a standard license declared.
              Check the repository for any license declaration and review the terms closely.
              OutlinedDot
              Without a license, all rights are reserved, and you cannot use the library in your applications.

            kandi-Reuse Reuse

              PasswordGenerator releases are not available. You will need to build from source code and install.

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            PasswordGenerator Key Features

            No Key Features are available at this moment for PasswordGenerator.

            PasswordGenerator Examples and Code Snippets

            No Code Snippets are available at this moment for PasswordGenerator.

            Community Discussions

            QUESTION

            how can i fix: UnboundLocalError: local variable 'generate' referenced before assignment
            Asked 2021-Feb-01 at 00:16
            Error:  UnboundLocalError: local variable 'generate' referenced before assignment
            
            ...

            ANSWER

            Answered 2021-Feb-01 at 00:16

            Do you know what is local variable ?

            caratteri = "" creates local variable which exists only inside passwordGenerator() but you try to use it in generate() when you use list(caratteri).

            In generate() you create also local variable when you use caratteri = list(...) but you do this after trying to get value from caratteri - and this gives error local variable 'caratteri' referenced before assignment.

            Better use variables explicitly - send them as arguments

            Source https://stackoverflow.com/questions/65984051

            QUESTION

            How to save variable in for loop?
            Asked 2020-Nov-14 at 08:06

            I have made a random password generator.In function void passwordGenerator(int sizeOfPassword) The problem here is this I am trying to save the password generated by the program in sum but I don't know how to do it properly.

            How do I save random digits password in sum.

            ...

            ANSWER

            Answered 2020-Nov-14 at 08:06

            You might display letter by letter:

            Source https://stackoverflow.com/questions/64831699

            QUESTION

            Express Router .delete returns 404 Not Found?
            Asked 2020-Oct-22 at 17:36

            Encountered a strange issue while using delete method in Express app.

            Here is my app.js document. I am using elevatorRouter for "/elevators" routes.

            app.js

            ...

            ANSWER

            Answered 2020-Oct-22 at 17:36

            You cannot get response from a DELETE route with a POST HTTP request. It is a well-known issue of browsers, but HTML forms can only send FormData via POST and DELETE is not compatible. Therefore, Express routing does not match and says POST:“/:id” route does not exist. Try changing .delete to .post and it will work.

            Edit: There is a method-overwrite module to convert POST requests to DELETE via a query param _method (or any other name you choose).

            Source https://stackoverflow.com/questions/64453111

            QUESTION

            I have this crash while testing my app. I am a complete beginner and cant understand how to fix this, any solution?
            Asked 2020-Jun-30 at 12:54

            This is what the logcat is showing Me while Running the app, i cant understand what to do, please help me by telling me what to do. when i run my app the activity just pops up and closes in an instant. i dont get a 'app not responding' message too

            ...

            ANSWER

            Answered 2020-Jun-30 at 12:54

            You're getting NullPointerException because you're initializing the CheckBox views outside the onCreate() method.

            Source https://stackoverflow.com/questions/62632371

            QUESTION

            How to build this program without using global variables?
            Asked 2020-Apr-19 at 20:44

            I just created my first Python project. I'm sure there's a lot of improvements that could be made, but I have one specific question about how to alter my code.

            I've been reading that it's unwise to use global variables (due to security concerns). But I'm not sure how to make multiple functions work together (i.e. use the same variables) unless they are global.

            The program below does three things:

            1. Generate a password.
            2. Encrypt that password.
            3. Decrypt the password.

            However, I only declared global variables in part 2 to encrypt the password.

            My question is: how do alter the code to avoid using globals? I've pasted all the code below for reference, but the globals are declared in def listToString() and def passEncryptor():.

            ...

            ANSWER

            Answered 2020-Apr-19 at 20:33

            In this case it really just comes down to lack of knowledge - you aren't taking advantage of function parameters - I'm assuming you don't know what those are, because if you did, you would prefer them over global variables.

            I don't know that "security" is exactly what you're sacrificing when using global variables. Sure, I can think of hypothetical examples, and I'm sure someone can cite some real example(s) where use of global variables was a major security issue... What I mean is, using global variables doesn't make your program intrinsically insecure - it's just that it's very easy to use them incorrectly (is there a correct way?). There are better solutions available to solve the problems you think you can only solve with global variables.

            The code you posted actually demonstrates the crux of global variables perfectly - If I, a user of your program, want to generate multiple passwords, the result I get is unexpected:

            Source https://stackoverflow.com/questions/61310599

            QUESTION

            Python trying to randomly select the value from list within a list results in the TypeError: list expected at most 1 argument, got 4
            Asked 2020-Apr-17 at 16:07

            I tried to search a lot but could not find proper resolution hence posting here. I am new to Python and I am trying to create a simple password generator application which is of 8 characters and should consist of 1 uppercase, 1 lowercase, 1 special character, and 1 numeric values. I am able to get these things and create a 4 letter password with Uppercase, lowercase, special character, and numeric values. For the remaining 4 characters, I want to choose the options randomly from the list which is made up of all these options but for some reason, I am unable to obtain the values randomly for it. I am getting the following error when I try to access the random choice from the list within a list:

            TypeError: list expected at most 1 argument, got 4

            I wanted to know how can I select a random value which can be either lowercase, uppercase, numeric or special characters for the remaining 4 values in my final password. I know I can use the for loop to accomplish the same but I would like to do it randomly so I am trying this approach.

            Following is the code I have so far and some of the things I have tried to obtain the random values located list within a list:

            ...

            ANSWER

            Answered 2020-Apr-17 at 16:07

            The list() method only takes one argument. You can do

            Source https://stackoverflow.com/questions/61275826

            QUESTION

            How can i mock i base method when test derived class
            Asked 2020-Mar-30 at 03:55

            I have the problem that i want to write a unit test of a custom function in my user service. But this user service derives from asp.net core identity user manager. I want to extend the functionality of the user manager therefore i derived from it. So I want to test the method CreateCRohMUserAsync

            ...

            ANSWER

            Answered 2020-Mar-29 at 08:06

            As per your example code, I'd recommend you change the inheritance to composition as you only use methods from the base class, not override any.

            Source https://stackoverflow.com/questions/60911473

            QUESTION

            vuetify vee-validate scroll to the first validation error
            Asked 2020-Mar-26 at 15:32

            If the submit button is clicked in a form, it should automatically scroll to the first validation error if an error exists. I've read that I can use "scrolltoview" for this, but I don't know exactly how.

            I have already tried it with a simple ScrollTo (0.0) to simply scroll up in the event of errors and it works perfectly. However, this is not the solution I would like to have.

            ...

            ANSWER

            Answered 2020-Mar-26 at 15:32

            Try using document.querySelector to locate the first error message like below.

            Source https://stackoverflow.com/questions/60870424

            QUESTION

            How do I use TabbedView in SwiftUI?
            Asked 2019-Dec-29 at 23:04
            struct ContentView : View {
                var body: some View {
                    NavigationView {
                        TabbedView {
                            PasswordGenerator()
                                .tabItemLabel {
                                    Image("KeyGlyph")
                                    Text("Generator")
                            }
            
                            PasswordGeneratorSettings()
                                .tabItemLabel {
                                        Image("SettingsGlyph")
                                        Text("Settings")
                            }
                        }
                    }
                }
            }
            
            ...

            ANSWER

            Answered 2019-Jun-25 at 15:09

            The 'TabbedView' can be used in a way similar to the following:

            Source https://stackoverflow.com/questions/56748132

            QUESTION

            Problem with making random string in python
            Asked 2019-Oct-27 at 17:59

            I'm semi-new to python, and i'm trying to make a random username and password generator, but nothing that I've been having trouble setting up a random username

            I've tried just generating a random string of ten characters, but it ends up being way too long, and quite repetitive. Here's the code I tried

            ...

            ANSWER

            Answered 2019-Oct-27 at 17:59

            username.join(nameExtra) means "take each of the characters in nameExtra, and put the full value of username between each of them". This is why it's appearing several times. To fix this problem, do username + nameExtra instead of username.join(nameExtra).

            Also, you're not building a string correctly, so it's using . at 0x0000020B09A5DE48> as the string, instead of the text you wanted it to use. To fix this problem, do ''.join(str(random.randint(0, 9)) for i in range(2)) instead of ''.join(str(random.randint(0, 9) for i in range(2))). Note the subtle difference in the closing parentheses.

            Source https://stackoverflow.com/questions/58581867

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

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            You can download it from GitHub.

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