letype | Type checker for any data structures | Validation library

by Marcisbee JavaScript Version: 1.1.0 License: MIT

X-Ray Key Features Code Snippets Community Discussions(3)Vulnerabilities Install Support

kandi X-RAY | letype Summary

letype is a JavaScript library typically used in Utilities, Validation applications. letype has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can install using 'npm i letype' or download it from GitHub, npm.

Type checker that uses native data types. Letype is simple and small (1kB minified + gzipped) type checker library that can validate any JS data types and structures as well as any custom ones.

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Quality

Security

License

Reuse

Support

letype has a low active ecosystem.

It has 15 star(s) with 0 fork(s). There are 1 watchers for this library.

It had no major release in the last 12 months.

letype has no issues reported. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of letype is 1.1.0

Quality

letype has 0 bugs and 0 code smells.

Security

letype has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

letype code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

letype is licensed under the MIT License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

letype releases are available to install and integrate.

Deployable package is available in npm.

Installation instructions, examples and code snippets are available.

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letype Key Features

No Key Features are available at this moment for letype.

letype Examples and Code Snippets

No Code Snippets are available at this moment for letype.

Community Discussions

Trending Discussions on letype

How cast parent into child to call right function in C#

Symfony 3.4 - Passing variables in my modals?

Symfony - How to remove a specific element from my array from an entity

QUESTION

How cast parent into child to call right function in C#

Asked 2020-Mar-11 at 16:13

I Work on c#/Code first I've a Parent Class abstract public class form_base {} and severals differents childs class. Here one of them

...

ANSWER

Answered 2020-Mar-03 at 17:11

Instead of:

GetMethod("Cast")

...try this overload:

GetMethod("Cast", new Type[] { typeof(Object) })

More observations...

The Cast method of class form_base is not static. (See above to get this one.)

The class form_base doesn't define any public static methods.

(Side note, I'm not sure why the class extensions is defined as partial.)

The Cast method in class extensions is static, but is not an extension method.

To get this one, you can use this overload, on type extensions:

Source https://stackoverflow.com/questions/60492898

QUESTION

Symfony 3.4 - Passing variables in my modals?

Asked 2019-Apr-08 at 10:21

I would like to know if it is possible to pass variables in a modal using Symfony?

Before integrating a modal, my line looked like

...

ANSWER

Answered 2019-Apr-08 at 10:21

I would recomment you to use a macro for your modal. This one you can reuse everytime you want. This would look something like this:

Source https://stackoverflow.com/questions/55569861

QUESTION

Symfony - How to remove a specific element from my array from an entity

Asked 2019-Mar-25 at 15:10

I have a Packages entity (manyToMany with the entityTypeUser that creates me in the DB the package_des_users entity). My Packages entity therefore contains an array of TypeUser (because a package can be assigned to several types of users).

I want to be able to delete one of the elements that are part of the TypeUser array of one of my packages.

My plan of action was:

Retrieve the package to process
Retrieve the name of the TypeUser to remove from the TypeUser array of the package.
Do a check: If the package contains only one typeUser, the package is deleted directly. If it contains more than one, just delete the chosen TypeUser.

For now, I was able to recover the package to be processed as well as the name of the TypeUser to delete, and the number of TypeUser that contained my package. If it contains only one, it suppresses it well. The problem remains for the other case.

Being a beginner in Symfony 3.4, I have a hard time understanding how to do it right.

My controller.php function :

...

ANSWER

Answered 2019-Mar-25 at 14:56

You have to change it on the class, you are calling the $unPaquet property of the entity manager, and then calling to a function that does not exist. Also you forgot to check if there is more than one or you would be deleting from an empty array.

Source https://stackoverflow.com/questions/55340334

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install letype

To install the stable version:. This assumes you are using npm as your package manager. If you're not, you can access these files on unpkg (letype.min.js is the file you're probalby after), download them, or point your package manager to them.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

Find more information at: