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kandi X-RAY | beejs Summary
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QUESTION
I am learning about C, specifically the structs. The following exaple of a recursive (is it?) struct being used for creating a linked list. This is all from beejs guide to c.
...ANSWER
Answered 2021-Apr-22 at 16:13Part 0
The following exaple of a recursive (is it?) [...]
(No, it isn't.)
Part 1
head = malloc(sizeof(struct node));
head->data = 11;
head->next = malloc(sizeof(struct node));
on line 14 since Head is a pointer it saves the memory address from pointer. on line 16 next is the pointer but rather then using head.next to store the memory address it uses head->next. This confuses me as head -> next == (*head).next this means the content of next is assigned the memory address but next is not pointing to anything.
head->next
is equivalent to (*head).next
. Assuming all the malloc
calls are successful, head->next
is not pointing to anything valid before the assignment, but will point to the block allocated by malloc
after the assignment. For access to the member head->next
(equivalently (*head).next
), the important part is that the pointer value in head
is valid. The probably invalid initial pointer value in head->next
does not matter because it is being replaced by the assignment anyway.
Part 2
QUESTION
I am trying to write a server-client program. The idea is that server
- listens() on the given port
- When a user connects it accepts() the connection and stops listening
- On user disconnects, it goes back to listening state and this goes on forever.
Now, I have created the server and the communication is going fine, however, I am not sure how to stop listening when the user connects and start listening on disconnects. Can anyone help me with it?
Also, I am following beejs guide
Thanks
...ANSWER
Answered 2021-Jan-05 at 04:33The (only) way to stop listening is to close the listening socket. That will have no effect on the already accepted connection(s), so they can continue to be used. To start listening again, you will need to open a new listening socket and bind it. You'll probably need the SO_REUSEADDR option on the socket if you want to reopen the port before the TCP delay period has elapsed.
You could instead keep the listening socket around and simply not accept any more connections until you are finished with the first one, but that would not actually not listen -- any additional client that tried to connect would get a handshake from the kernel (so it would think it was connected) rather than a rejection.
A third possibility which is even more unlke what you are asking, but it probably a better design would be to keep the socket open and accept additional connections while you are processing the first connection, but then close these new connections right away with some kind of BUSY message. Then clients could know at least something about what is going on.
It all depends on what you want to have clients see when they try to connect to a busy server.
QUESTION
I've been working from Beejs Network examples, introducing a few customizations. In particular, I'm trying to use a single structure to store the necessary information related to communications/sockets. I think I'm having trouble populating an addrinfo
structure and using it with sendto
for a UDP socket. Bellow is my code, which compiles fine, but it fails with the message outlined below
ANSWER
Answered 2018-Jul-16 at 07:17This line
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