ANDI | test web content for accessibility and 508 compliance | Accessibility Testing library
kandi X-RAY | ANDI Summary
kandi X-RAY | ANDI Summary
ANDI is a web accessibility inspection tool.
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Top functions reviewed by kandi - BETA
- Analyze the table .
- This class is the basic checks for all elements that are part of an element .
- Display the active element
- The alerter class .
- Initializes the main UI .
- Initialize the plugin
- Analyze table information about a table .
- Find headers for element .
- Creates and initial settings .
- Creates HTMLUi Utility helper .
ANDI Key Features
ANDI Examples and Code Snippets
function camelizeStyleName(string) {
return camelize(string.replace(msPattern, 'ms-'));
}
Community Discussions
Trending Discussions on ANDI
QUESTION
I have some columns titles essay 0-9, I want to iterate over them count the words and then make a new column with the number of words. so essay0 will get a column essay0_num with 5 if that is how many words it has in it.
so far i got cupid <- cupid %>% mutate(essay9_num = sapply(strsplit(essay9, " "), length))
to count the words and add a column but i don't want to do it one by one for all 10.
i tried a for loop:
...ANSWER
Answered 2022-Apr-08 at 04:54Use across()
to apply the same function to multiple columns:
QUESTION
I am having trouble finding the syntax error in this code of a simple simulator of MIPS alu functions. The error appears in the else
of the case 6'b001000: // addi
:
ALU_.v:112: syntax error ALU_.v:113: Syntax in assignment statement l-value.
And here is my code:
...ANSWER
Answered 2022-Apr-02 at 00:52There are two coding errors:
Fix them this way
This was a bad nor expression
regC = ~(regA | regB) ;
Was missing begin/end pairs
Like this
QUESTION
I am creating a program for a user to enter an integer and then check each bit and count how many 1's is in it's binary value. So if I input 4673 I should get "4" as an output because there is 4 ones. This is the code I have below, for some reason I am only getting "0" as an output. My guess is I am not properly loading each bit with the "andi" and "srl". I check it step by step and when it comes to andi and srl $t0 never holds a value of 1, so I must not be shifting bit by bit?
...ANSWER
Answered 2022-Mar-14 at 06:59You've got this instruction andi $t0, $v0, 1
in your loop. But $v0
never changes within the loop, so you're always getting the same value. And regardless of whether that values was 0 or 1, it's going to be 0 after the srl
on the following line.
The whole bit-counting loop could be replaced by something like this:
QUESTION
I am working on a program that takes an integer from the user and then outputs how many 1's there are in it's binary equivalent. So first I believe I need to convert it to binary and then use a loop and check all 32 bits to find how many 1's there are.
I have been browsing around for hours and trying different things to first convert the integer to binary. What's the best way to do this? Is there a way to to read a register value in binary directly, or do I need to convert it first? This is all the code I have so far.
...ANSWER
Answered 2022-Mar-09 at 11:55As Michael commented, integers in registers are already in binary. A register is a group of 32 bits.
Crucially, operations on registers like andi $t1, $v0, 1
and srl $v0, $v0, 1
work in binary. i.e. the resulting 0 or 1 from and
is the value mod 2, and right-shift by 1 place divides by 2.
This is a consequence of MIPS being a binary computer, like every over real-world ISA you might learn assembly for. Higher-level languages including C, Java, and Python that have &
and >>
operations also always guarantee that they work in binary. (On a non-binary computer, e.g. ternary, implementing those semantics for x & y
would involve converting to an array of base-2 digits and doing the logic manually, then converting back.)
If you want to work with other number bases, like base 10, you'd need to do actual division (MIPS divu
) or remainder to remove or isolate the lowest base-10 digit. Or if the base is a power of 2, like base 16, then shift by 4 bits, or AND with 0x0f
(take the low 4 bits, i.e. 0b1111).
Input / output in other bases involves converting (binary) integers from / to strings of ASCII digits representing digits in another base. The MARS/SPIM read_int call (syscall
with $v0 = 5) does that for you, like C library functions scanf or printf. To do it manually, you do stuff like total = total * 10 + digit
, where digit
is something like ascii_char - '0'
. Or for output, repeated division / modulo by 10 to get the base-10 digits, starting with the lowest.
There are some MIPS Q&As about manually converting to/from strings, but not many because most students using MIPS are using MARS or SPIM with their toy system calls that do things normally done by a C library, or by hand. But IIRC there are some if you search.
ASCII decimal or hex strings are a serialization format for numbers, not how they exist inside computers (except as strings, not integers).
PopcountLooping over the bits one at a time, extracting and adding the low bit, is a simple but often inefficient way to count the number of set bits. Still, simple is good for a first attempt; the choice of andi
and srl
as examples earlier is a hint.
Some faster bithacks are shown on How to count the number of set bits in a 32-bit integer? although for MIPS that means generating lots of separate 32-bit constants which cost 2 instructions each. You could do two SWAR widening steps and then loop over groups of 4-bit sums, as a middle ground.
Count bits 1 on an integer as fast as GCC __builtin__popcount(int) shows a way where you count iterations of n &= n-1
to clear the lowest set bit, which is faster if there are only a few bits set, even if they're not near the bottom of the register.
QUESTION
Was trying to test my program with SPIM and have this message
spim: (parser) immediate value (-16) out of range (0 .. 65535) on line 56 of file code1.a
...ANSWER
Answered 2022-Feb-19 at 22:31The MIPS processor cannot do that operation in one instruction. The andi
instruction is an I-Type instruction, which holds a 16-bit immediate — further the andi
instruction zero extends the 16-bit immediate to 32-bit, so it cannot hold a negative number (ori
& xori
also zero extend, whereas addi
and all the others sign extend the immediate).
Whenever we cannot do something in one instruction, use a sequence of instructions. In this case, load the immediate into a register, then use the and
R-Type instruction.
FYI, the MARS simulator's assembler will take the andi $t1, $t0, 0xfffffff0
, though it treats that as a pseudo instruction and will expand that one line of assembly into a 3-instruction machine code sequence that loads the constant into a register (using two instructions: one more than needed to do the job), then uses that and
.
Apparently, Spim doesn't offer that particular pseudo instruction.
QUESTION
I'm developing a Java application using owl-api. For testing I want to use a TestDataProvider to provide test data for unit-testing.
I'm using version 5.0.0 because the tutorial I read is using this version too. I plan to update later.
...ANSWER
Answered 2022-Feb-19 at 15:13By default, an ontology is saved in the same place it was loaded from - in this case it was loaded from a remote IRI, and there's currently no support for saving an ontology directly to a remote URL.
You can work around this by specifying a target for your saveOntology()
call, e.g.,
QUESTION
My data frame is:
...ANSWER
Answered 2022-Feb-15 at 18:59Using dplyr
for the pipe and mutate
, we can gsub
everything after /
.
QUESTION
I have tabular data-set representing curves, each curve is represented by 42 values(data points), the goal is to filter out curves that do not follow Sigmoid function.
Technique applied
- Sigmoid Curve Fitting
- Calculate goodness of curve
Curve fitting source
...ANSWER
Answered 2021-Nov-16 at 12:36The problem is that you are using unbounded parameters. For example, if you allow L to be negative, you can fit a monotonically decreasing dataset with your function.
If I add simple non-negativity bounds to your fit, I get:
QUESTION
I have a nested dictionary like this:
...ANSWER
Answered 2021-Oct-17 at 11:01If I understand you correctly, you can use a nested dictionary comprehension:
QUESTION
ANSWER
Answered 2021-Jun-28 at 15:39I am not 100% sure I understand your question. But, you can enter an array formula once and it will automatically fill in formulas below. So change this:
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