permission | permission management system based on SpringBoot2+Shiro

 by   TyCoding JavaScript Version: Current License: No License

kandi X-RAY | permission Summary

kandi X-RAY | permission Summary

permission is a JavaScript library. permission has no bugs, it has no vulnerabilities and it has low support. You can download it from GitHub.

:rocket: A permission management system based on SpringBoot2+Shiro, using Vue+ElementUI front-end framework, supporting dynamic routing, Redis monitoring, log monitoring, Qiniu cloud storage, etc. Welcome to star, fork
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              permission has a low active ecosystem.
              It has 315 star(s) with 134 fork(s). There are 4 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 3 open issues and 0 have been closed. There are 3 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of permission is current.

            kandi-Quality Quality

              permission has no bugs reported.

            kandi-Security Security

              permission has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              permission does not have a standard license declared.
              Check the repository for any license declaration and review the terms closely.
              OutlinedDot
              Without a license, all rights are reserved, and you cannot use the library in your applications.

            kandi-Reuse Reuse

              permission releases are not available. You will need to build from source code and install.
              Installation instructions are not available. Examples and code snippets are available.

            Top functions reviewed by kandi - BETA

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            Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of permission
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            permission Key Features

            No Key Features are available at this moment for permission.

            permission Examples and Code Snippets

            Permission middleware .
            pythondot img1Lines of Code : 47dot img1License : Non-SPDX (Apache License 2.0)
            copy iconCopy
            def _preemption_handler(self):
                """A loop that handles preemption.
            
                This loop waits for signal of worker preemption and upon worker preemption,
                it waits until all workers are back and updates the cluster about the
                restarted workers.
                
            Create a Permission from a list of tensors .
            pythondot img2Lines of Code : 2dot img2License : Non-SPDX (Apache License 2.0)
            copy iconCopy
            def _from_components(self, tensor_list):
                return PerReplica(tensor_list)  

            Community Discussions

            QUESTION

            How to publish two messages of the same type to different worker instances based on the message content without using Send and RequestAddress?
            Asked 2021-Jun-16 at 03:47

            How to publish two messages of the same type to different worker instances based on the message content without using Send and RequestAddress?

            My scenario is:

            I am using Azure ServiceBus and Azure StorageTables.

            I am running two different instances of the same worker service workera and workerb. I need workera and workerb to both consume messages of type Command based on the value of Command.WorkerPrefix.

            the Command type looks like:

            ...

            ANSWER

            Answered 2021-Jun-15 at 23:37

            Using MassTransit with Azure Service Bus, I would suggest taking the message routing burden away from the publisher, and moving it to the consumer. By configuring the receive endpoint and using a subscription filter each instance would add its own subscription and use a message header to filter published messages.

            On the publisher, a message header would be added:

            Source https://stackoverflow.com/questions/67993639

            QUESTION

            There was a problem saving the text in EditText to a file
            Asked 2021-Jun-16 at 01:47

            This code receives information from an acquaintance you want to register in editText, and then clicks finButton to save the information you receive as a file called friendlist.txt. However, the Toast message is outputted from the try-catch statement that is currently performed when finButton is pressed. Also, the checkpermission does not work, which is wrapped in a try~catch statement, but does not have output on the logcat.

            And manifest.

            uses-permission android:name="android.permission.READ_EXTERNAL_STORAGE"

            uses-permission android:name="android.permission.WRITE_EXTERNAL_STORAGE"

            is written.

            Please let me know the solution. And this content is written with a translator, so the sentence can be strange.

            when you press finButton, the logcat is shown below.

            The code corresponding to the 116th line is this.

            FileOutputStream outstream = openFileOutput("friendList.txt", Activity.MODE_WORLD_WRITEABLE);

            logcat

            ...

            ANSWER

            Answered 2021-Jun-16 at 01:47

            Try with Context.MODE_APPEND or Context.MODE_PRIVATE instead of Activity.MODE_WORLD_WRITEABLE

            Source https://stackoverflow.com/questions/67995297

            QUESTION

            Does opening a file in a child process create a separate entry in the system open file table in the kernel?
            Asked 2021-Jun-15 at 23:17

            I understand that after calling fork() the child process inherits the per-process file descriptor table of its parent (pointing to the same system-wide open file tables). Hence, when opening a file in a parent process and then calling fork(), both the child and parent can write to that file without overwriting one another's output (due to a shared offset in the open-file table entry).

            However, suppose that, we call open() on some file after a fork (in both the parent and the child). Will this create a separate entries in the system-wide open file table, with a separate set of offsets and read-write permission flags for the child (despite the fact that it's technically the same file)? I've tried looking this up and I don't seem to be able to find a clear answer.

            I'm asking this mainly since I was playing around with writing to files, and it seems like only one the outputs of the parent and child ends up in the file in the aforementioned situation. This seemed to imply that there are separate entries in the open file table for the two separate open calls, and hence separate offsets, so the slower process overwrites the output of the other process.

            To illustrate this, consider the following code:

            ...

            ANSWER

            Answered 2021-May-03 at 20:22

            There is a difference between a file and a file descriptor (FD).

            All processes share the same files. They don't necessarily have access to the same files, and a file is not its name, either; two different processes which open the same name might not actually open the same file, for example if the first file were renamed or unlinked and a new file were associated with the name. But if they do open the same file, it's necessarily shared, and changes will be mutually visible.

            But a file descriptor is not a file. It refers to a file (not a filename, see above), but it also contains other information, including a file position used for and updated by calls to read and write. (You can use "positioned" read and write, pread and pwrite, if you don't want to use the position in the FD.) File descriptors are shared between parent and child processes, and so the file position in the FD is also shared.

            Another thing stored in the file descriptor (in the kernel, where user processes can't get at it) is the list of permitted actions (on Unix, read, write, and/or execute, and possibly others). Permissions are stored in the file directory, not in the file itself, and the requested permissions are copied into the file descriptor when the file is opened (if the permissions are available.) It's possible for a child process to have a different user or group than the parent, particularly if the parent is started with augmented permissions but drops them before spawning the child. A file descriptor for a file opened in this manner still has the same permissions uf it is shared with a child, even if the child would itself be able to open the file.

            Source https://stackoverflow.com/questions/67375028

            QUESTION

            Service account with org viewer role not able to perform any actions
            Asked 2021-Jun-15 at 20:53

            I have created a GCP service account with org viewer permissions (I assume therefore having read rights in all projects)

            ...

            ANSWER

            Answered 2021-Jun-15 at 20:49

            The error messages states that the service account does not have the permission compute.disks.list.

            What permissions does the role roles/resourcemanager.organizationViewer have?

            Source https://stackoverflow.com/questions/67992475

            QUESTION

            How to add multiple IDs to a discord.js check?
            Asked 2021-Jun-15 at 19:17

            I am trying to make a simple script that checks if the users ID is the one in the script.

            But I can't seem to figure it out.

            I hope you guys can help me.

            ...

            ANSWER

            Answered 2021-Jun-15 at 19:17

            Just add them to an array and check if the current author's ID is in that array:

            Source https://stackoverflow.com/questions/67989098

            QUESTION

            Collate setting on a column in SQL Server table not working
            Asked 2021-Jun-15 at 14:47

            I have a table in SQL Server 2008 database hosted on a shared web hosting. I cannot change the collation of the database because I don't have permissions. When I created the table, I set the collation for the columns that I want but it doesn't do anything and I still see ???? when I query the table. I tried nvarchar as well and it didn't work.

            The table:

            ...

            ANSWER

            Answered 2021-Mar-25 at 20:05

            The problem is your INSERT/UPDATE statements. Unless you define those values as an nvarchar then the characters outside the databases collation will be lost. This means you need to declare your parameters as an nvarchar. As a result I would suggest, instead, not changing the collation of the columns and changing them as an nvarchar and using an nvarchars throughout your code.

            Source https://stackoverflow.com/questions/66806705

            QUESTION

            Is it possible to restrict the Application API permissions of an Azure AD web application to one account?
            Asked 2021-Jun-15 at 12:38

            I'm developing an AWS Lambda function which will need to access an Outlook 365 inbox at a regular interval. I'm using Graph API for accessing the inbox.

            I created a new Azure AD web application registration using the Azure Active Directory admin center.(https://aad.portal.azure.com/) When assigning API Permissions to my app, I have an option to choose between Delegated permissions and Application permissions. I can't use delegated permissions since my code will run without any user interaction.

            When choosing application permissions, I can't find a way to restrict the permission to one user account. For example, if I try to give the app Mail.Read application permission, it'll get access to all mailboxes in the enterprise. Or maybe I'm interpreting the permission description incorrectly.

            How do I give my app API permissions to one user's mailbox?

            ...

            ANSWER

            Answered 2021-Mar-25 at 08:20

            This issue was solved by Shiva's comment, add it as the answer to close the question:

            Some apps call Microsoft Graph using their own identity and not on behalf of a user. For example, the Mail.Read application permission allows apps to read mail in all mailboxes without a signed-in user.

            Configuring ApplicationAccessPolicy is used to limit the app access to a specific set of mailboxes.

            1.Connect to Exchange Online PowerShell

            Source https://stackoverflow.com/questions/66707488

            QUESTION

            Configuring github to use local username and email for one project?
            Asked 2021-Jun-15 at 12:33

            In my github I set up my github username as follows (name and email changed for privacy)

            ...

            ANSWER

            Answered 2021-Jun-15 at 12:33

            The Git configuration of user.name and user.email has nothing to do with the permission error. You can specify any email and username. Those two values goes only into the commit author information.

            The real issue that you are facing is that you need two different github accounts. Your machine caches the first github account and uses that one to authenticate against the repository where the cached credentials does not have access permissions.

            There are two possible solutions to face this issue:

            • Use SSH keys and clone the repositories using ssh
            • Grant the other account access to the non working repository

            I would prefer the first one.

            Source https://stackoverflow.com/questions/67980572

            QUESTION

            Give read/write access to an S3 bucket to a specific Cognito user group
            Asked 2021-Jun-15 at 12:03

            I have users in a Cognito user pool, some of whom are in an Administrators group. These administrators need to be allowed to read/write to a specific S3 bucket, and other users must not.

            To achieve this, I assigned a role to the Administrators group which looked like this:

            ...

            ANSWER

            Answered 2021-Jun-15 at 12:03

            The solution lies in the federated identity pool's settings.

            By default the identity pool will provide the IAM role that it's configured with. In other words, one of either the "unauthenticated role" or the "authenticated role" that it's set up with.

            But it can be told instead to provide a role specified by the authentication provider. That's what will solve the problem here.

            1. In the AWS console, in Cognito, open the relevant identity pool.
            2. Click "Edit identity pool" (top right)
            3. Expand "Authentication Providers"
            4. Under Authenticated Role Selection, choose "Choose role from token".

            That will allow Cognito to specify its own roles, and you will find that the users get the privileges of their group.

            Source https://stackoverflow.com/questions/67713772

            QUESTION

            run on all object's parameters java
            Asked 2021-Jun-15 at 11:36

            I've an model:

            User(id, firstName, lastName);

            I get the user from POST request in Java Spring boot framework using @ModelAttribute Annotation in the prototype.

            ...

            ANSWER

            Answered 2021-Jun-15 at 11:36

            When you use the Spring Framework, there is a serialization/deserialization happening "behind the scenes" which involves your POJOs.

            For example, into this endpoint:

            Source https://stackoverflow.com/questions/67983156

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install permission

            You can download it from GitHub.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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