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QUESTION
i recently made a site, following this tutorial https://pythonprogramming.net/django-web-development-python-tutorial . I have uploaded it, however now in the meta-description shows me this:
"For full functionality of this site it is necessary to enable JavaScript. Here are the instructions how to enable JavaScript in your web browser"
The site is made from django.Do you know where the mistake might be? The site is http://birminghamcleaner.co.uk/ .
...ANSWER
Answered 2021-Feb-26 at 18:07The culprit is this part. Remove it and you're golden:
QUESTION
I am training on how to scrape some data in python and here's my try:
...ANSWER
Answered 2021-Feb-14 at 07:47You can actually do it with a single list comprehension.
Basically, what you have is the right approach, you just need to create a list of lists using your list comprehension.
For each match returned by soup.select
, you can extract both the text
and href
together.
Then, using the csv
module, you can pass this list of lists to csv.writerows
to create the CSV file for viewing in Excel or other tools, data processing, etc.
You can also optionally prepend a header to the list of lists, if you want, e.g. ['Title', 'URL']
.
Here is a full working example:
QUESTION
Working on an exercise from MIT's OpenCourseWare 6.01SC. Problem 3.1.5:
Define a function
clip(lo, x, hi)
that returnslo
ifx
is less thanlo
, returnshi
ifx
is greater thanhi
, and returnsx
otherwise. You can assume thatlo < hi
. ...don't useif
, but usemin
andmax
.
Reformulated in English, if x
is the least of the arguments, return lo
; if x
is the greatest of the arguments, return hi
; otherwise, return x
. Thus:
ANSWER
Answered 2020-Oct-22 at 23:51You can return this formula:
QUESTION
I have a dict
that was saved as JSON
in Python
, which is as shown in the code below.
ANSWER
Answered 2020-Sep-02 at 05:03You are converting dictionary to JSON and then again to JSON using JSON.dump
twice.
Just use it once while writing the file.
QUESTION
I am writing a project from the Automate The Boring Stuff book. The task is the following:
Image Site Downloader
Write a program that goes to a photo-sharing site like Flickr or Imgur, searches for a category of photos, and then downloads all the resulting images. You could write a program that works with any photo site that has a search feature.
Here is my code:
...ANSWER
Answered 2020-Jul-26 at 11:34First off - scraping 4 million results from a website like Flicker is likely to be unethical. Web scrapers should do their best to respect the website from which they are scraping by minimizing their load on servers. 4 million requests in a short amount of time is likely to get your IP banned. If you used proxies you could get around this but again - highly unethical. You also run into the risk of copyright issues since a lot of the images on flicker are subject to copyright.
If you were to go about doing this you would have to use Scrapy and possibly a Scrapy-Selenium combo. Scrapy is great for running concurrent requests meaning you can request a large number of images at the same time. You can learn more about Scrapy here:https://docs.scrapy.org/en/latest/
The workflow would look something like this:
- Scrapy makes a request to the website for the html - parse through it to find all tags with class='overlay no-outline'
- Scrapy makes a request to each url concurrently. This means that the urls won't be followed one by one but instead side by side.
- As the images are returned they get added to your database/storage space
- Scrapy (maybe Selenium) scrolls the infinitely scrolling page and repeats without iterating over already checked images (keep index of last scanned item).
This is what Scrapy would entail but I strongly recommend not attempting to scrape 4 million elements. You would probably find that the performance issues you run into would not be worth your time especially since this is supposed to be a learning experience and you will likely never have to scrape that many elements.
QUESTION
I am getting a bit confused here, the latest Anaconda Distribution, 2018.12 at time of writing comes with an option to install Microsoft Visual Studio Code, which is great.
When launching VSC and after Python: Select Interpreter
and with a fresh install of Anaconda, I can see ~Anaconda3\python.exe
which I assume is the Anaconda Python Environment, however, when I try to run some commands, I am getting:
ANSWER
Answered 2019-Feb-26 at 00:35Activating a conda environment does not place conda
on your PATH
. You need to launch the Anaconda Prompt
app from your Start menu to get a command-line with conda
on your PATH
if you didn't check the box to include conda
during installation.
Also realize that conda
only supports PowerShell as of conda
4.6 which was released in January 2019.
And the Python extension for VS Code works with conda
fine. Create a conda
environment and the extension will allow you to select it as your environment/interpreter.
QUESTION
I'm new to OpenCV, I am getting Assertion failed error when I run a template matching code. The error message is given below
...ANSWER
Answered 2017-Oct-17 at 21:53Make sure the images are on the same folder as the code.
I know, it's stupid and probably you had already checked that. I had the same exact problem. The answer seems stupid but it worked for me. I assume you have already figured it out. But for the sake of no one repeating it I will leave this here.
From what I have found, if the problem persists you should probably search for "imread not loading images properly" because that's the root of this error.
P.S. I too am following the same tutorial! Keep learning! And for those uninitiated: https://pythonprogramming.net/template-matching-python-opencv-tutorial/
QUESTION
i'm using API to load my data and make prediction. I have seen documentation to train model using code (https://docs.microsoft.com/en-us/azure/cognitive-services/Custom-Vision-Service/python-tutorial) but I can't figure how to chose training time of my model using the API?
edit: curently i'm importing data using code, training model using azure portal, and making prediction with code
edit2: more info about global process i'm using Azure congitive service to do an image classification task, multiclass (images can belong to only 1 label).
...ANSWER
Answered 2020-Jan-07 at 09:12Basically to queue project for training, you have to use below API :
QUESTION
I have installed Visual Studio Code (VSC) and Code Runner. When I use the terminal to execute my code it works fine and I get the results in the terminal window:
However, when I try to use Code Runner's keyboard shortcut Ctrl+Alt+N
I keep getting this error message:
Which baffles me because VSC shows this:
I've tried rebooting (solution on another related SO question), creating a new conda environment inside VSC along with what seemed to be relevant from the VSC documentation here and here.
If anyone can help me understand what I need to be doing differently I would appreciate it.
...ANSWER
Answered 2019-Dec-06 at 16:53You need to set a symbolic link between calling Python3 and Python since they're effectively the same thing. If you go into a normal command prompt / terminal and type Python3, you may get the same error. Whereas, if you type Python, it will launch the Python interpreter.
Close VSCode
If you're a Windows user you can use mklink to sort it out — open a Command Prompt as an Administrator, then navigate to your Python installation. e.g.:
QUESTION
I am trying to debug a custom management command using Visual Studio Code.
For this I have gone through the official VS Code tutorials for working with Python and Django, and I have managed to get debugging to work while following these tutorials.
VS Code Python tutorial / VS Code Django tutorial
The problem is that for a Python script (no Django), the debugger works because I run a specific file (by pressing f5) while the file's tab is open. Django debugging works because VS Code knows when a browser request causes my Django app to hit a break-point I entered in VS Code.
But a custom management command is run differently. For this I type the following in the console:
python manage.py name_of_management_command
How do I debug this in VS Code?
...ANSWER
Answered 2019-May-06 at 16:02While writing this question I came up with a solution myself.
In the VS Code launch.json
file (which contains the settings for the VS Code Django debugger) contains the following entry, by default:
"args": ["runserver", "--noreload", "--nothreading"]
I changed this to:
"args": ["name_of_management_command"]
Then start the debugger (press f5), and I am debugging my custom management command
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