borrowers | Example application of the Ember.js book ember-cli-101.com
kandi X-RAY | borrowers Summary
kandi X-RAY | borrowers Summary
This README outlines the details of collaborating on this Ember application. A short introduction of this app could easily go here.
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borrowers Key Features
borrowers Examples and Code Snippets
Community Discussions
Trending Discussions on borrowers
QUESTION
To illustrate the necessity of Rc
, the Book presents the following snippet (spoiler: it won't compile) to show that we cannot enable multiple ownership without Rc
.
ANSWER
Answered 2021-May-29 at 15:24With "ordinary" borrows you can very roughly think of a statically proven order-by-relationship, where the compiler needs to prove that the owner of something always comes to life before any borrows and always dies after all borrows died (a
owns String
, it comes to life before b
which borrows a
, then b
dies, then a
dies; valid). For a lot of use-cases, this can be done, which is Rust's insight to make the borrow-system practical.
There are cases where this can't be done statically. In the example you've given, you're sort of cheating, because all borrows have a 'static
-lifetime; and 'static
items can be "ordered" before or after anything out to infinity because of that - so there actually is no constraint in the first place. The example becomes much more complex when you take different lifetimes (many List<'a>
, List<'b>
, etc.) into account. This issue will become apparent when you try to pass values into functions and those functions try to add items. This is because values created inside functions will die after leaving their scope (i.e. when the enclosing function returns), so we cannot keep a reference to them afterwards, or there will be dangling references.
Rc
comes in when one can't prove statically who is the original owner, whose lifetime starts before any other and ends after any other(!). A classic example is a graph structure derived from user input, where multiple nodes can refer to one other node. They need to form a "born after, dies before" relationship with the node they are referencing at runtime, to guarantee that they never reference invalid data. The Rc
is a very simple solution to that because a simple counter can represent these relationships. As long as the counter is not zero, some "born after, dies before" relationship is still active. The key insight here is that it does not matter in which order the nodes are created and die because any order is valid. Only the points on either end - where the counter gets to 0 - are actually important, any increase or decrease in between is the same (0=+1+1+1-1-1-1=0
is the same as 0=+1+1-1+1-1-1=0
) The Rc
is destroyed when the counter reaches zero. In the graph example this is when a node is not being referred to any longer. This tells the owner of that Rc
(the last node referring) "Oh, it turns out I am the owner of the underlying node - nobody knew! - and I get to destroy it".
QUESTION
I have a 'borrower' table that is joined to a 'loan' table. I am trying to return all borrowers that DO NOT have a loan on a certain day. This is the code I have so far and I have hit a bit of a wall as this seems to be the way to go about this, admittedly I am quite new to SQL and I may be far off but any help would be greatly appreciated. I return all the borrowers using this code, rather than 60 or so that I should. Thankyou!
...ANSWER
Answered 2021-May-20 at 10:19Your query will look for all loans on any other day; so it would only exclude anyone who only had a book on that day. If you changed the first line to:
QUESTION
I'm currently working on an application for my end-of-year school project and have stumbled on an issue that I can't quite think up a solution for. My application uses a database that stores records of loans issued. In one of my forms, panels are added dynamically for each borrower in my borrowers database which has a unique loan ID. Each panel contains info retrieved from the respective record from the database along with a combo box containing amounts of dollars and a button directly next to it, allowing a lender to lend the money specified in the combo box to the borrower contained on that panel. Once that button is pressed, a new record is supposed to be inserted into another table that contains all the transactions made through the platform, which has a unique transaction ID, and is related to the table of borrowers through the loan ID.
What I'm thinking about doing is having each button of each panel have the property LoanID, which stores the LoanID of the loan on that panel, which then is able to take in the amount specified within the combo box on that particular panel; however, I don't know how to go about doing this.
...ANSWER
Answered 2021-Apr-28 at 14:41You are almost there.
You already create a TBorrower that includes the LoanID you need, but you are freeing this after you have created the panel.
Option 1 - use the Tag property of the TPanel to hold the LoandID (it's a NativeInt).
Option 2 - Create a custom TPanel class (which you may aready be doing in CreateNewPanel), but which includes a property for the TBorrower, and then save the TBorrower to the TPanel. Remember to free the TBorrower when you free the custom TPanel.
Option 3 - as fpiette has suggested, use a TFrame instead of a custom TPanel.
TFrame is similar to TForm, except it needs to be shown in a Form, you don't use it in isolation. So all of the methods you want to code can be part of the TFrame class.
QUESTION
Example of an object in the books array:
...ANSWER
Answered 2021-Apr-04 at 22:58I suggest something like the following, based on the assumption that the borrower's ID exists in the accounts
array.
I'm not sure what you want to sort by, but the code below assumes you are sorting by company in ascending order; if it is not the case, you may adapt to fit your needs.
QUESTION
I am using laravel notifications with queues. Here's my code:
...ANSWER
Answered 2021-Mar-27 at 15:24It is because you have two channels (see the via
method) on your notification class. Assuming you're using the database
connection (check your .env
for the value of QUEUE_CONNECTION) for queueing, you just need to have mail
as your channel.
QUESTION
I supplied all the values, but I get this Error !!! Why? I tried some ways but none of them worked for me ...
here is the code :
...ANSWER
Answered 2021-Mar-12 at 08:16The binding 5 value is 'duedate' and your params dict about that is:
QUESTION
I currently working on an example using the Decorator Pattern. My current code looks like this:
...ANSWER
Answered 2021-Mar-07 at 16:21Make NumCopies
virtual and override the behaviour in your decorator base class.
Side note about decorator pattern:
In a decorator pattern the abstract class LibraryItem
should have been an interface. That the decorator is required to implement.
QUESTION
I have two dataframes: lenders and borrowers. I want to combine values from lenders to borrowers, as below.
...ANSWER
Answered 2021-Jan-26 at 01:45I don't think there's a good way to do this using pandas join functions, it's really a problem where you should iterate over a list of borrowers. The below does what you are after:
QUESTION
I have a worksheet function that automatically calls CopyValues once dropdown in E4 changes on Sheet Debt Detail. This macro only runs if the sheet name is "Debt Detail" otherwise it is going to Exit Sub. This macro worked well until now. I added another sheet called "Borrower Statement", which is supposed to call BorrowerStatementCall if E4 changes in Sheet Borrower Statement.
I need to modify the existing Workbook function to accomplish this. Below is the existing code. Any help and suggestions on how to accomplish this would be appreciated:
...ANSWER
Answered 2020-Nov-25 at 13:29Some suggestions on your code:
- Indent your code
- Use at least some error handling if you're turning off screenupdating and other stuff
- No need for the Call statement
Code:
QUESTION
I'm trying to figure out the best way to match a pattern that I'm looking for in some documents. The main line that I am interested in is the line:
"FOR PURPOSES OF WRITING THIS LOAN DOCUMENT, DRSI IS THE GRANTEE OF WRIT"
While in some documents it appears in complete bold face, it does not necessarily have to, so I am not relying on that attribute of the text. However, it certainly comes in a separate paragraph, with the title "DSRI" and the paragraph's content is essentially always the same.
Does anyone have a good regex for the single sentence that I need to find?
...WORDS USED OFTEN IN THIS DOCUMENT
Words used in multiple sections of this document are defined below. Other words are defined in Sections 1, 2, 3, 4. Certain rules about the usage of words used in this document are also provided in Section 20.
(A) "Loan Document" means this instrument, which is dated August 1, 2011. The term "Loan Document" includes any Addendums recorded with this Loan Document
(B) "Borrower" means JOHN A. SMITH
who sometimes will be called "Borrower" and sometimes simply "I" or "me". "Borrower" is granting a loan under this Loan Document. "Borrower" is not necessarily the same as the Person or Persons who signed the Document. The obligations of Borrowers who did not sign the Document are explained further in Section 23.
###POSSIBLE NEW PAGE######
(C) "DRSI" is Document Reading services, INC. DRSI is a separate corporation that is acting solely as nominee for Lender and Lender's successors and assigns. DRSI is organized and existing under the laws of California, and has an address and telephone number of P.O. Box 1111, Oakland, CA 1111-1111, tel(111) 111-DRSI. FOR PURPOSES OF WRITING THIS LOAN DOCUMENT, DRSI IS THE GRANTEE OF WRIT.
(D) "Lender" means LendersCorp, Inc.
Lender is a corporation or association which exists under the laws of Illinois
Lender's address is 1111 Maine St, Maine City, IL 11111-1111Except as provided in Sections 2 and 10, the term "Lender" may include any Person who takes ownership of this Loan and this Loan Document.
(E) "Loan" means the loan signed by John A. SMITH
and dated August 1, 2011 .This Loan shows that its signer or signers owe Lender
ANSWER
Answered 2020-Sep-29 at 15:41Try this:
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