world | An Animated Globe in 1024 Bytes of JavaScript

 by   aemkei JavaScript Version: Current License: No License

kandi X-RAY | world Summary

kandi X-RAY | world Summary

world is a JavaScript library. world has no bugs, it has no vulnerabilities and it has low support. You can download it from GitHub.

An Animated Globe in 1024 Bytes of JavaScript
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            kandi-support Support

              world has a low active ecosystem.
              It has 149 star(s) with 9 fork(s). There are 10 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 0 open issues and 1 have been closed. On average issues are closed in 619 days. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of world is current.

            kandi-Quality Quality

              world has no bugs reported.

            kandi-Security Security

              world has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              world does not have a standard license declared.
              Check the repository for any license declaration and review the terms closely.
              OutlinedDot
              Without a license, all rights are reserved, and you cannot use the library in your applications.

            kandi-Reuse Reuse

              world releases are not available. You will need to build from source code and install.
              Installation instructions are not available. Examples and code snippets are available.

            Top functions reviewed by kandi - BETA

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            Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of world
            Get all kandi verified functions for this library.

            world Key Features

            No Key Features are available at this moment for world.

            world Examples and Code Snippets

            Hello World
            mavendot img1Lines of Code : 9dot img1no licencesLicense : No License
            copy iconCopy
            package rxjava.examples;
            
            import io.reactivex.rxjava3.core.*;
            
            public class HelloWorld {
                public static void main(String[] args) {
                    Flowable.just("Hello world").subscribe(System.out::println);
                }
            }
            
              
            Hello World
            mavendot img2Lines of Code : 9dot img2no licencesLicense : No License
            copy iconCopy
            package rxjava.examples;
            
            import io.reactivex.rxjava3.core.*;
            
            public class HelloWorld {
                public static void main(String[] args) {
                    Flowable.just("Hello world").subscribe(System.out::println);
                }
            }
            
              
            Display a hello world with the specified name
            javadot img3Lines of Code : 11dot img3License : Permissive (MIT License)
            copy iconCopy
            public String greet(String name) {
            
                    HelloWorld helloWorld = new HelloWorld() {
                    	@Override
                        public String greet(String name) {
                            return "Welcome to " + name;
                        }
            
                    };
                    return helloWorld.  
            Get a dictionary of all coverage stats from the world .
            pythondot img4Lines of Code : 10dot img4License : Permissive (MIT License)
            copy iconCopy
            def world_covid19_stats(url: str = "https://www.worldometers.info/coronavirus") -> dict:
                """
                Return a dict of current worldwide COVID-19 statistics
                """
                soup = BeautifulSoup(requests.get(url).text, "html.parser")
                keys = soup.fin  
            Find expiring hello world .
            javadot img5Lines of Code : 9dot img5License : Permissive (MIT License)
            copy iconCopy
            public String findExpiringHelloWorld() {
                    String cacheKey = "expiring-hello";
                    String helloWorld = simpleHelloWorldCache.get(cacheKey);
                    if (helloWorld == null) {
                        helloWorld = repository.getHelloWorld();
                        s  

            Community Discussions

            QUESTION

            Does opening a file in a child process create a separate entry in the system open file table in the kernel?
            Asked 2021-Jun-15 at 23:17

            I understand that after calling fork() the child process inherits the per-process file descriptor table of its parent (pointing to the same system-wide open file tables). Hence, when opening a file in a parent process and then calling fork(), both the child and parent can write to that file without overwriting one another's output (due to a shared offset in the open-file table entry).

            However, suppose that, we call open() on some file after a fork (in both the parent and the child). Will this create a separate entries in the system-wide open file table, with a separate set of offsets and read-write permission flags for the child (despite the fact that it's technically the same file)? I've tried looking this up and I don't seem to be able to find a clear answer.

            I'm asking this mainly since I was playing around with writing to files, and it seems like only one the outputs of the parent and child ends up in the file in the aforementioned situation. This seemed to imply that there are separate entries in the open file table for the two separate open calls, and hence separate offsets, so the slower process overwrites the output of the other process.

            To illustrate this, consider the following code:

            ...

            ANSWER

            Answered 2021-May-03 at 20:22

            There is a difference between a file and a file descriptor (FD).

            All processes share the same files. They don't necessarily have access to the same files, and a file is not its name, either; two different processes which open the same name might not actually open the same file, for example if the first file were renamed or unlinked and a new file were associated with the name. But if they do open the same file, it's necessarily shared, and changes will be mutually visible.

            But a file descriptor is not a file. It refers to a file (not a filename, see above), but it also contains other information, including a file position used for and updated by calls to read and write. (You can use "positioned" read and write, pread and pwrite, if you don't want to use the position in the FD.) File descriptors are shared between parent and child processes, and so the file position in the FD is also shared.

            Another thing stored in the file descriptor (in the kernel, where user processes can't get at it) is the list of permitted actions (on Unix, read, write, and/or execute, and possibly others). Permissions are stored in the file directory, not in the file itself, and the requested permissions are copied into the file descriptor when the file is opened (if the permissions are available.) It's possible for a child process to have a different user or group than the parent, particularly if the parent is started with augmented permissions but drops them before spawning the child. A file descriptor for a file opened in this manner still has the same permissions uf it is shared with a child, even if the child would itself be able to open the file.

            Source https://stackoverflow.com/questions/67375028

            QUESTION

            How does a linux C/C++ system() command work?
            Asked 2021-Jun-15 at 21:30

            Or, more specifically, does it use the default shell, or actually running the actual file. Example: system("echo Hello, World!"). Would this run using, lets say Bash, or would this run by telling to kernal to run a command? Also, is this on topic, or would this fit better somewhere else?

            ...

            ANSWER

            Answered 2021-Jun-15 at 21:28

            man system is your friend here. This is what is says on my system:

            The system() library function uses fork(2) to create a child process that executes the shell command specified in command using execl(3) as follows:

            Source https://stackoverflow.com/questions/67993603

            QUESTION

            Getting an error "TypeError: Cannot read property 'split' of undefined"
            Asked 2021-Jun-15 at 20:51

            I am working in react application and founded this stubborn thing. This is my state in react to which i am working on

            ...

            ANSWER

            Answered 2021-Jun-15 at 20:51

            You seem to be confusing useState with the class component's state.

            Running setState({ testInfo: testInfoArray }); sets the entire state to { testInfo: testInfoArray }, removing state.selectedParagraph entirely, causing it to be undefined.

            You'll want to use useState multiple times, like this:

            Source https://stackoverflow.com/questions/67993048

            QUESTION

            ReactJS: TypeError: Cannot read property 'latitude' of undefined
            Asked 2021-Jun-15 at 18:50

            I am trying to check if latitude and longitude exist in my SQL database, as currently when they are undefined, it leaves my web app blank on load with the following error TypeError: Cannot read property 'latitude' of undefined

            My code was originally

            ...

            ANSWER

            Answered 2021-Jun-15 at 18:36

            Looking at error TypeError: Cannot read property 'latitude' of undefined. My guess is value of device.deviceData is undefined.

            So,Please do verify with console.log(device) if deviceData field exists in device.

            And, to fix above issue you can try

            Source https://stackoverflow.com/questions/67991606

            QUESTION

            Apereo CAS HTML template does not seem to load
            Asked 2021-Jun-15 at 18:37

            So I initialized CAS using cas-initializr with the following command inside the cas folder:

            ...

            ANSWER

            Answered 2021-Jun-15 at 18:37

            Starting with 6.4 RC5 (which is the version you run as of this writing and should provide this in your original post):

            The collection of thymeleaf user interface template pages are no longer found in the context root of the web application resources. Instead, they are organized and grouped into logical folders for each feature category. For example, the pages that deal with login or logout functionality can now be found inside login or logout directories. The page names themselves remain unchecked. You should always cross-check the template locations with the CAS WAR Overlay and use the tooling provided by the build to locate or fetch the templates from the CAS web application context.

            https://apereo.github.io/cas/development/release_notes/RC5.html#thymeleaf-user-interface-pages

            Please read the release notes and adjust your setup.

            All templates are listed here: https://apereo.github.io/cas/development/ux/User-Interface-Customization-Views.html#templates

            Source https://stackoverflow.com/questions/67979701

            QUESTION

            Pusher Undefined property: stdClass::$channels in Laravel Lumen
            Asked 2021-Jun-15 at 16:42

            I'm making a POC with Lumen and Vue.JS. For now it just has to send a "hello world" message from the Lumen back-end to the Vue.JS front-end (which works). I have made an event which is triggered upon loading the page like this:

            ...

            ANSWER

            Answered 2021-Jun-15 at 16:42

            Fix composer.json

            I have created an issue on the PHP package: https://github.com/pusher/pusher-http-php/issues/295

            It is true this version is broken, but the fix should be in the composer.json file. Mine looked like this:

            Source https://stackoverflow.com/questions/66624416

            QUESTION

            Micronaut Read Timeout with HttpClient
            Asked 2021-Jun-15 at 16:31

            I'm struggling to use the Micronaut HTTPClient for multiple calls to a third-party REST service without receiving a io.micronaut.http.client.exceptions.ReadTimeoutException

            To remove the third-party dependency, the problem can be reproduced using a simple Micronaut app calling it's own service.

            Example Controller:

            ...

            ANSWER

            Answered 2021-Jun-15 at 09:51

            If this isn't going to throw an exception then I don't know what is going to.

            This is caused by using blocking code within Netty's event loop.

            The code over here is making a blocking request 20 times in a row which cause the machine to break. I don't know what data is coming from the client but I would never recommend to do it in this manner.

            Source https://stackoverflow.com/questions/67973867

            QUESTION

            My JCheckBox program only displays one box. Why is that?
            Asked 2021-Jun-15 at 14:34

            I am attempting to add another checkbox to this program but for some reason it will not display when I run the program. Only the check box for the blue pill displays. I have attempted to add a couple things or change the way the program is structured, but nothing I have done so far has helped.

            Code Below:

            ...

            ANSWER

            Answered 2021-Jun-15 at 04:38

            When you're stuck on a problem, it never hurts to go back and consult the documentation.

            You'll find information like this:

            A border layout lays out a container, arranging and resizing its components to fit in five regions: north, south, east, west, and center. Each region may contain no more than one component, and is identified by a corresponding constant: NORTH, SOUTH, EAST, WEST, and CENTER. When adding a component to a container with a border layout, use one of these five constants...

            When you add your button, you do this:

            Source https://stackoverflow.com/questions/67979964

            QUESTION

            How to make map draggable in D3v6
            Asked 2021-Jun-15 at 12:55

            I have a Drilldown world map(continent map + country map) where the second map(the country map) is zoomed-in onload by using fitExtent function. Since it is zoomed-in, I wanted to implement a draggable feature where I can drag the map and see other part of the map.

            ...

            ANSWER

            Answered 2021-Jun-15 at 12:55
            var svg = d3.select("#mapDiv")
                .append("svg")
                .attr("width", width)
                .attr("height", height)
                .style("background-color", "white")
                .style("border", "solid 1px black")
                .call(d3.zoom()
                    .on("zoom", function (event) {
                        svg.attr("transform", event.transform)
                    })
                    .scaleExtent([1, 1])
                )
                .append("g");
            

            Source https://stackoverflow.com/questions/67938213

            QUESTION

            How is this code snippet an example of incorrect synchronization?
            Asked 2021-Jun-15 at 12:46

            I am trying to understand the example with incorrect sync code from The Go Memory Model.

            Double-checked locking is an attempt to avoid the overhead of synchronization. For example, the twoprint program might be incorrectly written as:

            ...

            ANSWER

            Answered 2021-Jun-14 at 19:18

            According to the Go memory model:

            https://golang.org/ref/mem

            There are no guarantees that one goroutine will see the operations performed by another goroutine unless there is an explicit synchronization between the two using channels, mutex. etc.

            In your example: the fact that a goroutines sees done=true does not imply it will see a set. This is only guaranteed if there is explicit synchronization between the goroutines.

            The sync.Once probably offers such synchronization, so that's why you have not observed this behavior. There is still a memory race, and on a different platform with a different implementation of sync.Once, things may change.

            Source https://stackoverflow.com/questions/67975948

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install world

            You can download it from GitHub.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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