functor

by allouis JavaScript Version: Current License: No License

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kandi X-RAY | functor Summary

functor is a JavaScript library. functor has no bugs, it has no vulnerabilities and it has low support. You can download it from GitHub.

functor

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Support

functor has a low active ecosystem.

It has 5 star(s) with 0 fork(s). There are no watchers for this library.

It had no major release in the last 6 months.

functor has no issues reported. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of functor is current.

Quality

functor has no bugs reported.

Security

functor has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

License

functor does not have a standard license declared.

Check the repository for any license declaration and review the terms closely.

Without a license, all rights are reserved, and you cannot use the library in your applications.

Reuse

functor releases are not available. You will need to build from source code and install.

Installation instructions are not available. Examples and code snippets are available.

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functor Key Features

No Key Features are available at this moment for functor.

functor Examples and Code Snippets

No Code Snippets are available at this moment for functor.

Community Discussions

Trending Discussions on functor

Why does my variadic template instantiation not work?

Lifetime of get method in postgres Rust

Why we need to put parenthesis when giving a template type

Use of std::forward with Eigen::Ref objects

OCaml serializing a (no args) variant as a "string enum" (via Yojson)

Haskell monadic parser with anamorphisms

Reference to an array of unknown bound (C++)

Why do I need to call the constructor again in the definition of fmap even when I don't apply the f argument?

How to specify typecllass function type to operate on RoseTree nodes?

Unions Data.Map singletons inside an IO

QUESTION

Why does my variadic template instantiation not work?

Asked 2021-Jun-14 at 10:56

I am revisiting C++ after a long hiatus, and I would like to use templates to design the known "map" function -- the one which applies a specified function to every element of some specified "iterable" object.

Disregarding the fact my map doesn't return anything (a non-factor here), I have managed to implement what I wanted if the function passed to "map" does not need to accept additional arguments:

...

ANSWER

Answered 2021-Jun-13 at 20:41

A simple way to fix this would be to deduce the non-type template parameter for the function, and reorder the template parameter list

Source https://stackoverflow.com/questions/67962170

QUESTION

Lifetime of get method in postgres Rust

Asked 2021-Jun-14 at 07:09

Some Background (feel free to skip):

I'm very new to Rust, I come from a Haskell background (just in case that gives you an idea of any misconceptions I might have).

I am trying to write a program which, given a bunch of inputs from a database, can create customisable reports. To do this I wanted to create a Field datatype which is composable in a sort of DSL style. In Haskell my intuition would be to make Field an instance of Functor and Applicative so that writing things like this would be possible:

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ANSWER

Answered 2021-Jun-10 at 12:54

So I seem to have fixed it, although I'm still not sure I understand exactly what I've done...

Source https://stackoverflow.com/questions/67920269

QUESTION

Why we need to put parenthesis when giving a template type

Asked 2021-Jun-13 at 20:31

Hello I am trying to understand this piece of code:

...

ANSWER

Answered 2021-Jun-13 at 20:31

Why we need to put parenthesis when giving a template type sort(a.begin(), a.end(), greater());

std::greater is a class template. std::greater is an instance of that class template, and is a type (more specifically, a class type). std::greater() is a temporary object (an instance of the type that is the instance of the template). The parentheses are syntax for value initialisation.

It is not possible to pass a type as an argument to a function (however, it would be possible to pass a type as a template argument to a function template). It is possible to pass a temporary object as an argument to a function.

So, we use the parentheses so that an object is created that we pass as an argument.

PS: I said object which is a class specific term but I think in structures, it may be called that way in c++.

If by structure you mean a struct: Structs are classes (that have been declared with the class-key struct).

Instances of all types are objects in C++.

Source https://stackoverflow.com/questions/67961986

QUESTION

Use of std::forward with Eigen::Ref objects

Asked 2021-Jun-13 at 07:44

I have a functor Foo defined as follows:

...

ANSWER

Answered 2021-Jun-13 at 07:44

Source https://stackoverflow.com/questions/67953171

QUESTION

OCaml serializing a (no args) variant as a "string enum" (via Yojson)

Asked 2021-Jun-12 at 11:52

Say I am building a record type:

...

ANSWER

Answered 2021-Jun-06 at 18:50

Regarding the last error, it's because OCaml requires a 'stable path' to types inside modules so it can refer to them. A stable path is a named path to a type, e.g. Fruit.t.

By contrast, StrEnum(struct type t = ... end).t is not a stable path because the type t is referencing a type t in the module literal which does not have a name.

Long story short, you basically can't skip defining the variant module separately. But it's simple to do it in two steps:

Source https://stackoverflow.com/questions/67861549

QUESTION

Haskell monadic parser with anamorphisms

Asked 2021-Jun-11 at 01:28

My problem is how to combine the recursive, F-algebra-style recursive type definitions, with monadic/applicative-style parsers, in way that would scale to a realistic programming language.

I have just started with the Expr definition below:

...

ANSWER

Answered 2021-Jun-10 at 17:15

If you need a monadic parser, you need a monad in your unfold:

Source https://stackoverflow.com/questions/67924053

QUESTION

Reference to an array of unknown bound (C++)

Asked 2021-Jun-10 at 22:48

I have a templated class used for modelling views on objects, like std::shared_ptr and std::weak_ptr but without any owning semantics. The class internally holds a pointer to the viewed object and a functor which is called on class destruction (It is useful for reference counting the viewed object, or for thread-safe locking and releasing of the viewed resource).

Like the standard library counterparts, I would like my class to behave as expected when the owned object is an array (T[]). The problem I am facing comes from the fact that a pointer to an array of unknown bound is, by my understanding, illegal C++. More specifically, given that the template parameter of the class T is, say, int[], when in my class I write:

...

ANSWER

Answered 2021-Jun-10 at 22:48

The problem I am facing comes from the fact that a pointer to an array of unknown bound is, by my understanding, illegal C++.

You're mistaken. Pointer to an array of unknown bound is not illegal in C++.

I am in fact invoking undefined behaviour. (Or, possibly, some non-standard compiler extension?)

Neither (as long as the pointer is valid). The shown function is standard conforming even if T is an array of unknown bound.

why are pointers and references to arrays of unknown bound illegal?

They aren't illegal.

_{There used to be a special case that pointers and references to arrays of unknown bound were illegal as function parameters. That was made legal in a defect resolution in 2014}

Source https://stackoverflow.com/questions/67928583

QUESTION

Why do I need to call the constructor again in the definition of fmap even when I don't apply the f argument?

Asked 2021-Jun-06 at 22:33

I have no idea why fmap _ a = a below is illegal. Here is the code:

...

ANSWER

Answered 2021-Jun-05 at 19:51

You need to call the constructor anew to create a new value, so it will have a different type than the one you've started with.

Source https://stackoverflow.com/questions/67851549

QUESTION

How to specify typecllass function type to operate on RoseTree nodes?

Asked 2021-Jun-04 at 05:52

I have following code:

...

ANSWER

Answered 2021-Jun-04 at 01:54

data RoseTree a = RoseTree { value :: a, children :: [RoseTree a]}

class Find a where
  findBiggest :: DetectionType a -> a -> Int

instance Find NodeRoseTree where
  findBiggest detectionType (RoseTree node []) = if is detectionType node

Source https://stackoverflow.com/questions/67829409

QUESTION

Unions Data.Map singletons inside an IO

Asked 2021-May-29 at 14:13

I am struggling with applying Data.Map.unions to a list of Data.Map singletons wrapped in an IO. Here is my code:

...

ANSWER

Answered 2021-May-29 at 14:13

The lambda expression:

Source https://stackoverflow.com/questions/67752191

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install functor

You can download it from GitHub.

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