euclid | : pencil2 : Euclidean geometry in javascript

You can do this using a recursive approach in following fashion:

The declaration long gcd(long p, long q, long *x, long *y) says the last two parameters of gcd are pointers. So you must pass it pointers to existing long; you cannot pass it values such as 0 and 1.

To do that, define two long objects in main, possibly also called x and y, such as long x = 0, y = 1;. Then pass pointers to those objects to gcd, as with gcd(34398, 2132, &x, &y);.

Further, you must put the declaration of gcd before any use of it.

Defining gcd inside main is an extension to the C standard. That extension is useful in situations where the nested function needs certain context from its containing function. There is no need for that here, so the function should be defined in the ordinary way. Move the entire definition of gcd from inside main to before main.

There is no reason to use floor in floor(p / q), because p and q have integer type and integer division will be performed. There will be no fraction part for floor to remove. It can actually make the result wrong if the double type has less precision than the long type. So just use p/q.

There is also no reason to use recursion in this code. It is wasteful and not pedagogical in this situation. (Referring to the book Programming Challenges, the author says “Euclid’s algorithm is recursive…” However, I have a 2003 English translation of Euclid’s Elements, circa 300 BCE. Looking at Euclid’s GCD algorithm in Book VII, Propositions 1 and 2, I would say it is iterative, not recursive. In its cumbersome way, as seen through modern eyes, it describes doing things repeatedly, not reapplying the whole algorithm de novo.)

to understand what your code is doing you can use a debugger like gdb. but there is another way if you don't know how to use a debugger or you just don't like it and that is printing the values where it can show us some information. I think the code below can show you what you like to see.

I don't know if you can write it as an apomorphism, but I do see a way you can write it as a hylomorphism:

There is problem in how divides is being called. I think in ensures clauses you meant divides(k, a) instead of divides(a, k) similarly for divides(b, k) and divides(gcd(a, b), k).

One way to go about this after recursive call to dividesLemma(a, b - a) is to use postcondition of method. Here we know forall k such that k divides a and k divides b - a implies k divides gcd(a, b-a). Using this information we try to prove required postcondition (code or proof is straightforward to follow)

you could try to add a column in the cancelButton section

Check this code,let me know this work for you

for more details check this link cupertino Widgets also refer cupertino-ios-style-actionsheet

Just find GCD of the results (GCD of array would be GCD of GCDs of left and right half of the array).

You can use slice() method to divide the array in chunks.