create | Midgard Create , a generic web editing interface for any CMS | Content Management System library
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kandi X-RAY | create Summary
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QUESTION
I want to add jitpack.io as a repository in my gradle file. This is my gradle root file:
...ANSWER
Answered 2021-Sep-16 at 11:02Android introduced a new way to define repositories.
Remove the dependencyResolutionManagement
block from the setting.gradle
file to have your project work the old way.
QUESTION
I am getting this create React app error again and again even after doing the uninstall part.
npm uninstall -g create-react-app
up to date, audited 1 package in 570ms
found 0 vulnerabilities
npx create-react-app test-app
...Need to install the following packages: create-react-app Ok to proceed? (y) y
You are running
create-react-app
4.0.3, which is behind the latest release (5.0.0).We no longer support global installation of Create React App.
Please remove any global installs with one of the following commands:
- npm uninstall -g create-react-app
- yarn global remove create-react-app
The latest instructions for creating a new app can be found here: https://create-react-app.dev/docs/getting-started/
ANSWER
Answered 2022-Jan-01 at 22:34You will have to clear the npx cache to make it work.
You can locate the location of the folder where create-react-app is installed using npm ls -g create-react-app
.
Also, to clear the cache, refer to this answer in How can I clear the central cache for `npx`?
QUESTION
I created the default IntelliJ IDEA React project and got this:
...ANSWER
Answered 2021-Nov-15 at 00:32Failed to construct transformer: Error: error:0308010C:digital envelope routines::unsupported
The simplest and easiest solution to solve the above error is to downgrade Node.js to v14.18.1. And then just delete folder node_modules
and try to rebuild your project and your error must be solved.
QUESTION
My bitbucket password is correct because I can easily login with this password. When I try to push a project or file to bitbucket it shows Invalid credentials error.
...ANSWER
Answered 2022-Mar-07 at 11:47Go to credential Manager -> Windown Credential -> Add a generic credential fill up the fields Network address: git:https://bitbucket.org Username: App Password: Solver from Here
QUESTION
I have been using github actions for quite sometime but today my deployments started failing. Below is the error from github action logs
...ANSWER
Answered 2022-Mar-16 at 07:01First, this error message is indeed expected on Jan. 11th, 2022.
See "Improving Git protocol security on GitHub".
January 11, 2022 Final brownout.
This is the full brownout period where we’ll temporarily stop accepting the deprecated key and signature types, ciphers, and MACs, and the unencrypted Git protocol.
This will help clients discover any lingering use of older keys or old URLs.
Second, check your package.json
dependencies for any git://
URL, as in this example, fixed in this PR.
As noted by Jörg W Mittag:
For GitHub Actions:There was a 4-month warning.
The entire Internet has been moving away from unauthenticated, unencrypted protocols for a decade, it's not like this is a huge surprise.Personally, I consider it less an "issue" and more "detecting unmaintained dependencies".
Plus, this is still only the brownout period, so the protocol will only be disabled for a short period of time, allowing developers to discover the problem.
The permanent shutdown is not until March 15th.
As in actions/checkout issue 14, you can add as a first step:
QUESTION
I have newly installed
...ANSWER
Answered 2021-Jul-28 at 07:22You are running the project via Java 1.8 and add the --add-opens
option to the runner. However Java 1.8 does not support it.
So, the first option is to use Java 11 to run the project, as Java 11 can recognize this VM option.
Another solution is to find a place where --add-opens
is added and remove it.
Check Run configuration in IntelliJ IDEA (VM options field) and Maven/Gradle configuration files for argLine
(Maven) and jvmArgs
(Gradle)
QUESTION
I'm trying to access appsettings.json in my Asp.net core v6 application Program.cs file, but in this version of .Net the Startup class and Program class are merged together and the using and another statements are simplified and removed from Program.cs. In this situation, How to access IConfiguration or how to use dependency injection for example ?
Edited : Here is my default Program.cs that Asp.net 6 created for me
...ANSWER
Answered 2021-Sep-30 at 11:13Assuming an appsettings.json
QUESTION
I am having problems with npx create-react-app involving global installs. My confusion arises because as far as I'm aware the create-react-app package is not installed on my machine.
Some Details:
I start a react project (with typescript template) as I have previously and recently done on this same machine a number of times:
npx create-react-app --template typescript .
I get this prompt from the terminal
Need to install the following packages: create-react-app Ok to proceed? (y)
I press y to confirm it's okay to proceed. (If I press n, the process terminates with the following error: npm ERR! canceled
.) The terminal then displays the following message
ANSWER
Answered 2021-Dec-21 at 14:45You can try to locate the installed version by running:
QUESTION
Following a previous question of mine, most comments say "just don't, you are in a limbo state, you have to kill everything and start over". There is also a "safeish" workaround.
What I fail to understand is why a segmentation fault is inherently nonrecoverable.
The moment in which writing to protected memory is caught - otherwise, the SIGSEGV
would not be sent.
If the moment of writing to protected memory can be caught, I don't see why - in theory - it can't be reverted, at some low level, and have the SIGSEGV converted to a standard software exception.
Please explain why after a segmentation fault the program is in an undetermined state, as very obviously, the fault is thrown before memory was actually changed (I am probably wrong and don't see why). Had it been thrown after, one could create a program that changes protected memory, one byte at a time, getting segmentation faults, and eventually reprogramming the kernel - a security risk that is not present, as we can see the world still stands.
- When exactly does a segmentation fault happen (= when is
SIGSEGV
sent)? - Why is the process in an undefined behavior state after that point?
- Why is it not recoverable?
- Why does this solution avoid that unrecoverable state? Does it even?
ANSWER
Answered 2021-Dec-10 at 15:05When exactly does segmentation fault happen (=when is SIGSEGV sent)?
When you attempt to access memory you don’t have access to, such as accessing an array out of bounds or dereferencing an invalid pointer. The signal SIGSEGV
is standardized but different OS might implement it differently. "Segmentation fault" is mainly a term used in *nix systems, Windows calls it "access violation".
Why is the process in undefined behavior state after that point?
Because one or several of the variables in the program didn’t behave as expected. Let’s say you have some array that is supposed to store a number of values, but you didn’t allocate enough room for all them. So only those you allocated room for get written correctly, and the rest written out of bounds of the array can hold any values. How exactly is the OS to know how critical those out of bounds values are for your application to function? It knows nothing of their purpose.
Furthermore, writing outside allowed memory can often corrupt other unrelated variables, which is obviously dangerous and can cause any random behavior. Such bugs are often hard to track down. Stack overflows for example are such segmentation faults prone to overwrite adjacent variables, unless the error was caught by protection mechanisms.
If we look at the behavior of "bare metal" microcontroller systems without any OS and no virtual memory features, just raw physical memory - they will just silently do exactly as told - for example, overwriting unrelated variables and keep on going. Which in turn could cause disastrous behavior in case the application is mission-critical.
Why is it not recoverable?
Because the OS doesn’t know what your program is supposed to be doing.
Though in the "bare metal" scenario above, the system might be smart enough to place itself in a safe mode and keep going. Critical applications such as automotive and med-tech aren’t allowed to just stop or reset, as that in itself might be dangerous. They will rather try to "limp home" with limited functionality.
Why does this solution avoid that unrecoverable state? Does it even?
That solution is just ignoring the error and keeps on going. It doesn’t fix the problem that caused it. It’s a very dirty patch and setjmp/longjmp in general are very dangerous functions that should be avoided for any purpose.
We have to realize that a segmentation fault is a symptom of a bug, not the cause.
QUESTION
In the following code, I create two lists with the same values: one list unsorted (s_not), the other sorted (s_yes). The values are created by randint(). I run some loop for each list and time it.
...ANSWER
Answered 2021-Nov-15 at 21:05Cache misses. When N
int objects are allocated back-to-back, the memory reserved to hold them tends to be in a contiguous chunk. So crawling over the list in allocation order tends to access the memory holding the ints' values in sequential, contiguous, increasing order too.
Shuffle it, and the access pattern when crawling over the list is randomized too. Cache misses abound, provided there are enough different int objects that they don't all fit in cache.
At r==1
, and r==2
, CPython happens to treat such small ints as singletons, so, e.g., despite that you have 10 million elements in the list, at r==2
it contains only (at most) 100 distinct int objects. All the data for those fit in cache simultaneously.
Beyond that, though, you're likely to get more, and more, and more distinct int objects. Hardware caches become increasingly useless then when the access pattern is random.
Illustrating:
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