aeiou | node.js web interface to silly text to speech things
kandi X-RAY | aeiou Summary
kandi X-RAY | aeiou Summary
aeiou is a web-based API for text-to-speech using the DECTalk engine. You may recognize this particular speech-synthesis engine from various videogames and YouTube videos. In order to install it, you need Windows (or Wine on Linux) and a copy of DECTalk (I’m using version 4.61). See [decwav/README.md] decwav/README.md) for instructions on how to build decwav.exe, which the webserver uses to process text-to-speech requests. Please contact me if you would like to try out the copy I am hosting.
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QUESTION
I have to retrieve distinct entities from a column, all of which start with a vowel. The query looks like this :
...ANSWER
Answered 2021-Jun-12 at 16:36You can use regular expressions:
QUESTION
I am trying to build a regex that finds the number of syllables in a word with the following conditions:
- Vowels are counted as syllables.
- Two or more consecutive vowels are counted as one syllable
- Ignore 'e' if it is the last letter in a word (don't count it as a syllable)
- Vowels are: 'a', 'e', 'i', 'o', 'u', and 'y'.
I came up with [e][aeiou]*(?=[a-z])|[aiouy][aiouy]*(?=[a-z ])
, which you can test here. As seen in the test, the word 'they' comes up as two separate matches (e and y are counted separately), which is an issue. How can this be solved?
Also, if possible, it would be great if there is an explanation to regex solutions.
...ANSWER
Answered 2021-May-29 at 04:29This is what I ended up with, but I am sure it can be very improved.
QUESTION
I'm working on making a discord bot that deletes every message that contains vowels (I know its weird, but its just for a joke between my friends and I). The way I'm checking if a message has a vowel is using regex, and I'm trying to refine my regex so it allows for emojis(their names may contain vowels).
What I need the regex to do is match any string with vowels in it, something like :
...ANSWER
Answered 2021-May-25 at 04:26What if you just made sure there was whitespace (or start-of-line) in front of the word?
(?:^|\s)\w*?[aeiou]\w*
As opposed to testing for something that's always in the emoji, you can test for something that's never in it.
QUESTION
Query the list of CITY names from STATION which have vowels (i.e., a, e, i, o, and u) as both their first and last characters. Your result cannot contain duplicates.
I tried to run this query but it is returning an empty output
...ANSWER
Answered 2021-May-23 at 11:08The LIKE
pattern you are using is an extension only supported by SQL Server (and Sybase). In MySQL, you can use regular expressions:
QUESTION
I am trying to iterate over an array of strings and remove those whose first letter is not a vowel. I know that there are more succinct ways of achieving this, e.g. #select, but I don't understand why the below does not work. Can someone please explain what's wrong with this code:
...ANSWER
Answered 2021-May-09 at 19:41That's because you're removing elements from array
at the same time you iterate over it;
First iteration:
QUESTION
I have a long set of sentences and I need to print the sentences with the least number of vowels. Use the following code I found the least number of vowels, there are several sentences with that least number of vowels. When I use str_view_all to display the sentences I need to use a pattern in the argument. If I do it the following way, it only displays 1 sentence.
...ANSWER
Answered 2021-May-02 at 15:08Here is a base R option using gsub
+ nchar
+ min
QUESTION
Do you how can I get this result with Regex? In literal words, I want each groups of successives vowels with the maximum of consonants surrounding them (backward or foreward).
Example :
...ANSWER
Answered 2021-Apr-27 at 01:09You can put the part of the regex that you want to be made non-exclusive in a lookaround pattern so that it leaves that portion of the search buffer for the next match. Since your rule appears to be that vowels do not overlap between matches while the surrounding consonants can, you can group the consonants after vowels in a lookahead pattern, while putting vowels and any preceding consonants in another capture group, and then concatenate the 2 matching groups into a string for output:
QUESTION
i have figured out a way to replace vowels into * but it only converts the first line
input: break robert yeah
output: br**k
here is the code
...ANSWER
Answered 2021-Mar-25 at 03:32Your code works as you want (in:break robert yeah out: br**k r*b*rt y**h) on my env(Windows10, java1.8.0_271), maybe you can set a breakpoint on enterWord = enterWord.replaceAll("[aeiou]", "*");
and check is the enterWord
recived whole input string.
QUESTION
Is there a Python library that contains a variable which contains vowels, e.g. 'aeiou'
, ['a', 'e', 'i', 'o', 'u']
or something like that? in the string
library there is ascii_lowercase
variable with the English alphabet, but extracting vowels and consonants from it requires hard-coding the 'aeiou'
-like constant. Can we avoid that?
Edit: Answering to questions in comments:
Yes, the use-case is to replace
ANSWER
Answered 2021-Mar-13 at 10:27A vowel list is not in the standard python library, but a quick way generate a vowel list is:
vowels = set("aeiou")
QUESTION
cin.get(a, 256);
for(int i = 0; i < strlen(a); i++){
if(strchr("aeiou", a[i])){
s = 0;
strcpy(substr, empty);
isubstr = 0;
}
else{
s++;
substr[isubstr++] = a[i];
if(s > maax || s == maax){
maax = s;
memset(show, 0, 256);
strcpy(show, substr);
}
}
}
cout << show;
...ANSWER
Answered 2021-Mar-12 at 22:52For starters you should write a function that finds such a longest sequence of consonants.
You provided an incomplete code so it is difficult to analyze it. For example it is not seen where and how variables substr
and empty
used in this call
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