sideline | desktop application

Don't know if this is exact enough. It doesn't necessarily cut all instances that are within 1 second but some small tweaks would do the trick. Also, I'm kind of assuming that you care more about "width/height" and "left/top" groupings than any combo of the four. Regardless, you just have to do this transform over again for any groups you really care about, up to all permutations. For the sake of brevity I left out the "left/top" grouping but it's just a repeat of this.

The observed effect is due to immediate apply to bound string state and immediate react/rebuild of view.

To bring desired behavior beck we need to postpone somehow state update and thus give a chance for SecuredField/UITextField to update self without synchronisation with state.

Here is a demo of possible direction (it is not ideal, but a way to go). Tested with Xcode 12.1 / iOS 14.1.

The syntax means a lookahead matching an empty character class. Observe that an empty character class also never matches:

I think that quotes, commas and parentheses should be avoided in an id. So use this line:

You need to update your HTML its not valid HTML and for line you can use border property check below snippet.

let posX = rect.top;

You are setting the X coordinate as the top, and the Y coordinate as the left. They should be flipped since you are using the width to calculate X (left-right) and height to calculate Y (top-bottom).

You can see that the bugs often travel way beyond the bottom of the screen because their vertical range is the same as the width of the screen.

First, I want to clarify the planes of reference:

1. The video you have is a 2D projection (viewing plane) of the 3D world, as a plane perpendicular to the centerline of the camera lens.
2. The shot arc is embedded in a plane (shot plane) which is perpendicular to the real-world (3D) floor, defined by the point of release (shooter's hand) and point of contact (backboard).

The shot arc you see on the video is from the projection of that shot plane onto the viewing plane.

I want to make sure we're clear with respect to your most recent comment: So let's say I can estimate the shooting location on the court (x,y). using the laws of physics I can say where the ball is in each frame (x,y) wise and then from that and the pixel coordinates I can extract the height coordinate?

1. You can, indeed, estimate the (x,y) coordinate. However, I would not ascribe my approach to "the laws of physics". I would use analytic geometry.
2. You can estimate, with good accuracy, the 3D coordinates of both the release point (from the known (x, y, 0) position of the shooter's feet) and the end point on the backboard (whose corners are known).
3. Drop a perpendicular from each of these points to the floor (z=0). That line on the floor is the vertical projection of the arc to the floor -- these are the (x,y) coordinates of the ball in flight.
4. For each video frame, drop a projected perpendicular from the ball's image to that line on the floor ... that gives you the (x,y) coordinates of the ball, for what it's worth.
5. You have the definition (equation) of the view plane, the viewpoint (camera), and the arc plane. To determine the ball's position for each video frame, draw a line from the viewpoint, through the ball's image on the view plane. Determine the intersection of this line with the arc plane. That gives you the 3D coordinates of the ball in that frame.

Does that clarify a useful line of attack?

I find it easier to work with vector equations since the algebra will be rotation-invariant (hence you don't have to re-write the code to deal with e.g. a "horizontal" parabola).

1. Curve representation + Intersection test

Consider a quadratic Bezier curve with endpoints A, C, control point B and parameter t:

And an infinite line with source O, direction D and parameter s:

Equating P and R give a pair of quadratic simultaneous equations, which can be re-arranged to eliminate s and find the parabolic parameter t:

Solve this quadratic equation for t, and only accept real roots in the range [0, 1]. This ensures that any intersection point is always on the segment itself.

2. Dealing with line segments

You can also restrict the intersection point to a line segment, by computing s from t using the equations above, and limiting its value - which equals the distance along the line from O if D is normalized.

3. Computing the control point B

Note that a general value of the control point B will not give a symmetrical parabola. To compute B for a general symmetric curve:

Defining the variables:

• M: midpoint of AB
• n: clockwise normal to the direction AC
• q: signed bulge distance - absolute value is the distance from M to the midpoint of the curve
• k: signed distance from M to B

A surprisingly simple result.

4. Sample C# (-style) code

i have used pseudo classes to achieve it. hope it helps. thanks