kanan | Mods for Mabinogi using Javascript

by cursey JavaScript Version: Current License: Unlicense

X-Ray Key Features Code Snippets Community Discussions(7)Vulnerabilities Install Support

kandi X-RAY | kanan Summary

kanan is a JavaScript library. kanan has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

Mods for Mabinogi using JavaScript.

Support

Quality

Security

License

Reuse

Support

kanan has a low active ecosystem.

It has 53 star(s) with 31 fork(s). There are 20 watchers for this library.

It had no major release in the last 6 months.

There are 50 open issues and 67 have been closed. On average issues are closed in 22 days. There are 2 open pull requests and 0 closed requests.

It has a neutral sentiment in the developer community.

The latest version of kanan is current.

Quality

kanan has 0 bugs and 7 code smells.

Security

kanan has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

kanan code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

kanan is licensed under the Unlicense License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

kanan releases are not available. You will need to build from source code and install.

Installation instructions are available. Examples and code snippets are not available.

kanan saves you 177 person hours of effort in developing the same functionality from scratch.

It has 439 lines of code, 22 functions and 89 files.

It has high code complexity. Code complexity directly impacts maintainability of the code.

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kanan Key Features

No Key Features are available at this moment for kanan.

kanan Examples and Code Snippets

No Code Snippets are available at this moment for kanan.

Community Discussions

Trending Discussions on kanan

Laravel 8 - Upload multiple files at the same time with different inputs

How to make div stay in place when another div is hidden?

Get Id From AJAX Response And Use The Id For Select2

Find user has both the permission in SQL query

Cannot Locate text Widget with 3rd party Library

I am sending registration activation email using celery in django but celery gives some error

Why does my code generate different results each time i run it? (Python)

QUESTION

Laravel 8 - Upload multiple files at the same time with different inputs

Asked 2022-Jan-07 at 03:12

I have many input files with different names, but when I upload only one file is saved, that's the reason why?

_form.blade.php :

...

ANSWER

Answered 2022-Jan-07 at 03:12

Looks like you're using the right function in the first example, but the wrong function in the others.

In 'tampak depan', you're using $request->file(), but in the others you're using $request->post().

Change those to $request->file() and they should work.

Source https://stackoverflow.com/questions/70616075

QUESTION

How to make div stay in place when another div is hidden?

Asked 2021-Jun-20 at 09:14

I have 5 div(s) and a button below those div(s). I want to hide those div(s) before I click the button to show the div one by one but the problem is when I hide the div(s), the button below will change the position to the top position of the hidden div.

HTML:

...

ANSWER

Answered 2021-Jun-20 at 08:12

Instead of performing hide(), you can try to change the visibility to hidden using css(). Setting the visibility to hidden will not affect the position of others elements.

JQuery:

Source https://stackoverflow.com/questions/68053808

QUESTION

Get Id From AJAX Response And Use The Id For Select2

Asked 2021-Apr-17 at 05:30

I write HTML code in controller

...

ANSWER

Answered 2021-Apr-17 at 05:26

Your server return json as response so add dataType: 'json' to your ajax call. Then , append data return to your dataUserElement i.e : data.html and finally intialize your select2 .

Demo Code :

Source https://stackoverflow.com/questions/67133635

QUESTION

Find user has both the permission in SQL query

Asked 2021-Feb-17 at 12:18

A user table has id and user_name and a second table which has user-related permission user_id and perm_id

User Table

id user_name 1 Ashok 2 Anil 3 Sunil 4 kanan

Permission Table

user_id perm_id 1 2 1 4 1 7 1 10 2 7 2 10 3 5 3 7

Now the problem that needs to find is

User must have perm_id=7 and must not have perm_id=10 however, can have other perm_ids like 1,2,3,11, etc in the permission table is type "USER_TYPE_A".
User must have both the perm_id in (7,10) in the permission table is type "USER_TYPE_B".
User must not fall under 1 and 2 criteria which means Must not have both the perm_id in (7,10) is type "USER_TYPE_C".

Now, have to write the query which will show user_name along with User_type.

What will be the best way to get a result please suggest. Thanks:)

...

ANSWER

Answered 2021-Feb-17 at 10:05

If I understad well, you need to check the permissions' types for each user and then implement some logic based on the result; if so, this could be a way:

Source https://stackoverflow.com/questions/66239313

QUESTION

Cannot Locate text Widget with 3rd party Library

Asked 2020-Nov-06 at 08:12

Im writing Integration Test using Flutter Driver for the app that utilizes CoachMark library (https://pub.dev/packages/tutorial_coach_mark)

i want to click the text to close the CoachMark, but when i tried to inspect it using VSCode's widget inspector, the text didn't show up on the widget tree, when i hover the inspector to that text, it points to MaterialApp root widget (see screenshot)

These are methods i tried to locate them with no luck:

find.byType('Text')
find.text('OKE')
find.byType('RichText')
and even this nested, confusing finder

return find.descendant(of: find.byType('Align'), matching: find.descendant(of:find.byType('SafeArea'), matching: find.descendant(of:find.byType('AnimatedOpacity'), matching: find.descendant(of:find.byType('InkWell'), matching: find.descendant(of: find.byType('Padding'),matching: find.text('OKE'))))));

The reason why i tried using the 4th method is when i tried to dive into the library code itself, it builds the widget something like this

...

ANSWER

Answered 2020-Nov-06 at 08:12

i found the problem here.. flutter driver itself is frame synchronyzed, so in this COachMark library i have to wait until there are no pending frames..

i changed my code from this

Source https://stackoverflow.com/questions/64682323

QUESTION

I am sending registration activation email using celery in django but celery gives some error

Asked 2020-Nov-05 at 07:50

I am sending a registration activation email using celery in Django. forms.py

...

ANSWER

Answered 2020-Nov-04 at 11:52

Replace :

Source https://stackoverflow.com/questions/64678689

QUESTION

Why does my code generate different results each time i run it? (Python)

Asked 2020-May-15 at 01:51

here is my code

...

ANSWER

Answered 2020-May-15 at 01:51

remove set in your if set(kanan) == {"K","H"} or set(kanan) == {"K","S"}:.

Source https://stackoverflow.com/questions/61810144

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install kanan

Add Python 3.x to PATH. Add Python to environment variables.
Download the repository by clicking the green Clone or Download button, and extract it anywhere on your computer. Alternatively you can download it through the Github desktop application.
Download Python 3.5 x86-64 (the 64 bit version) from python.org (near the bottom) or use this direct link.
While installing Python, make sure you check the box that says Add Python 3.x to PATH or Add Python to environment variables, depending on the version you downloaded.
To make sure Python was installed correctly, open a command prompt from the start menu and type python --version and you should get a response.

Support

Contributions are welcome. If you are contributing a patch that you aren't the original author of, please give credits at the top of the file. If a patch has been added and you are the original author of it or know who is, open an issue so proper credits may be given (or issue a pull request).

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