linked-list | ↔️ LinkedList & DoublyLinkedList implementation in javascript | Frontend Utils library

 by   datastructures-js JavaScript Version: v6.1.0 License: MIT

kandi X-RAY | linked-list Summary

kandi X-RAY | linked-list Summary

linked-list is a JavaScript library typically used in User Interface, Frontend Utils applications. linked-list has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can install using 'npm i @datastructures-js/linked-list' or download it from GitHub, npm.

LinkedList & DoublyLinkedList implementation in javascript
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              linked-list has a low active ecosystem.
              It has 27 star(s) with 10 fork(s). There are 3 watchers for this library.
              There were 1 major release(s) in the last 12 months.
              There are 0 open issues and 3 have been closed. On average issues are closed in 249 days. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of linked-list is v6.1.0

            kandi-Quality Quality

              linked-list has no bugs reported.

            kandi-Security Security

              linked-list has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              linked-list is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              linked-list releases are available to install and integrate.
              Deployable package is available in npm.
              Installation instructions are not available. Examples and code snippets are available.

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            linked-list Key Features

            No Key Features are available at this moment for linked-list.

            linked-list Examples and Code Snippets

            No Code Snippets are available at this moment for linked-list.

            Community Discussions

            QUESTION

            Why is the output an empty list, when I call a function that skips nodes in a linked-list?
            Asked 2021-Jun-15 at 10:52

            I am writing code to answer the following LeetCode question:

            Given the head of a linked list and an integer val, remove all the nodes of the linked list that has Node.val == val, and return the new head

            Example 1 ...

            ANSWER

            Answered 2021-Jun-15 at 10:52

            Some issues in your code (as it was first posted):

            • return skipper(prev,curr) is going to exit the loop, but there might be more nodes to be removed further down the list. skipper only takes care of a sub sequence consisting of the same value, but it will not look beyond that. The list is not necessarily sorted, so the occurrences of the value are not necessarily grouped together.

            • Be aware that the variable prev in skipper is not the same variable as the other, outer prev. So the assignment prev=curr in skipper is quite useless

            • Unless the list starts with the searched value, dummy.next will always remain None, which is what the function returns. You should initialise dummy so it links to head as its next node. In your updated code you took care of this, but it is done in an obscure way (in the else part). dummy should just be initialised as the head of the whole list, so it is like any other node.

            In your updated code, there some other problems as well:

            • while prev.next: risks to be an infinite loop, because it continues while prev is not the very last node, but it also doesn't move forward in that list if its value is not equal to the searched value.

            I would suggest doing this without the skipper function. Your main loop can just deal with the cases where current.val == val, one by one.

            Here is the corrected code:

            Source https://stackoverflow.com/questions/67982630

            QUESTION

            Use stack memory as heap memory without UB
            Asked 2021-Jun-12 at 21:43

            I am working in an environment where I cannot use heap memory but only stack memory. To not be constrained by the #[no_std] enviroment I tried to use stack memory as heap memory with the linked-list-allocator crate. This was my approach.

            ...

            ANSWER

            Answered 2021-Apr-02 at 10:11

            After looking into the code and finding what looks a lot like the default entry point I'll put what I think is the confirmation of my guess as an answer: the global_allocator must be fully initialised before main, because the default entry point relies on it and allocates: https://github.com/rust-lang/rust/blob/master/library/std/src/rt.rs#L40-L45

            Source https://stackoverflow.com/questions/66917240

            QUESTION

            Batch array, associative array, and how to navigate in array
            Asked 2021-May-21 at 08:21

            How can I call in batch a multiple level of array ?

            I want to create an array of unique value with multiples data, then I will manage to make an associative array after unyfing the values.

            I have a csv file with lot of value like this :

            ...

            ANSWER

            Answered 2021-May-21 at 08:21

            when a variable that requires delayed expansion to access is composed of additional delayed variables, an additional for loop can be used to access sub variables:

            Source https://stackoverflow.com/questions/67628963

            QUESTION

            how do java set judge the similar ListNode
            Asked 2021-May-18 at 11:58

            when I'm solving the problem Intersection of Two Linked Lists from Leetcode, I found that the HashSet solution doesn't work on my computer. The return result is always null, but it works well on Leetcode.

            ...

            ANSWER

            Answered 2021-May-18 at 11:53

            The problem is not from HashSet on your Computer but it's from the input examples, make sure that you used the same ListNode Instances for the Intersection part on the 2 LinkedList for example

            Source https://stackoverflow.com/questions/67585153

            QUESTION

            What Does `--contains` Option Do in `git for-each-ref`?
            Asked 2021-May-12 at 07:21

            What does the --contains option do in git for-each-ref?

            Does it only return a reference if its revlist has the commit specified after the --contains option on the command line? (e.g. Does git for-each-ref refs/heads --contains feature/test only return those heads that contain the commit feature/test in their revlist? (i.e. the list of commits between them and the first commit, namely git rev-list ))?

            The Git docs (v. 2.31.1; see here) are actually outdated: the Notes section at the bottom states you can use the --merged and --no-merged options together, but this was made incompatible with this commit.

            The definition provided in the docs is ambiguous: it reuses the word "contains" without clarifying what is meant by that. A reference is a name that points to only one SHA. The idea of "contains" suggests a reference refers to multiple commits, which only makes sense in the context of its git rev-list.

            A commit can come after or before another (simply by time of commit), but if it is not reachable from that commit (i.e. if the commit is not merged into its branch), then the commit has no knowledge of it, so it can't be said to "contain" it.

            This is why --merged and --no-merged together made sense: it would return the commits reachable from (at least one of) --merged and none of --no-merged.

            What is meant by "contains"?..."has immediate parent X"? "has ancestor X"? "has cousin X"?

            UPDATE:

            It does seem I was using an older version of Git. Using both --merged and --no-merged together was incompatible in v2.28.1, but is now compatible in v2.31.1. Hence, the Git docs are not outdated.

            It also seems this commit was made on Mar 21, 2017, so well before v2.31.1 (not sure which version exactly it was committed with).

            Second, it does seem @LeGEC's answer makes sense (vis-a-vis --contains/--no-contains means "give me refs that have this commit after them" and --merged/--no-merged means "give me refs that have this commit before them".

            Still, it would be nice if the Git documentation could be given further clarified. Using the word in the definition as they've done is very vague.

            Because Git is a Directed Acyclic Graph (DAG), commits point to other commits in linked-list-fashion in one direction: backwards in time towards their ancestors. Hence, the names --merged/--no-merged and their description in terms of "reachability" make sense.

            Does "contains" mean "after and reachable" (i.e. children), or simply "after" (i.e. commits made later in time)?

            Since this is a plumbing command (which are used in custom scripts), I need to know exactly what it does and how it works so that my scripts won't have any unexpected side effects.

            ...

            ANSWER

            Answered 2021-May-12 at 07:21

            Perhaps I misunderstood your question, please update your question if relevant.

            The documentation gives a correct (but perhaps succinct ?) description of these options,
            here is one way to word it differently :

            • --merged develop means "comes before develop"
            • --no-merged master means "doesn't come before master"
            • --contains feature1 means "comes after feature1"
            • --no-contains feature2 means "doesn't come after feature2"

            These 4 options are actually compatible :

            Source https://stackoverflow.com/questions/67492785

            QUESTION

            Scan chars from user linked list of
            Asked 2021-May-11 at 16:53

            I'm supposed to write a function that scan input from user till enter and enter it to linked list. I cant scan it into a String and than put it in a list.

            I wrote this code and doesn't enter the chars to linked list and doesn't exit from the console till I press Exit.

            ...

            ANSWER

            Answered 2021-May-11 at 08:50

            For this call of scanf

            Source https://stackoverflow.com/questions/67483010

            QUESTION

            CS50 pset5 Speller [2021] - " :( program is free of memory errors"
            Asked 2021-May-11 at 16:48

            I get error ":( program is free of memory errors valgrind tests failed; see log for more information."

            Here is my code:

            ...

            ANSWER

            Answered 2021-May-11 at 16:48

            QUESTION

            split linked list of chars in C
            Asked 2021-May-10 at 15:42

            I'm supposed to write a function called - "disAssemblyList" that gets a linked list of chars(without a dummy element). The function should move a nodes with big letters to "bigLetter" linked list (without a dummy element) , move nodes with small letters to "smallLetter" linked list, nums to "nums" linked list and other chars keep into original list.

            I need to pass by reference the smallLetter, bigLetter and nums linked lists and return the list with other chars.

            I need to scan the original list. The original list can be empty.

            for example:

            An original linked list:

            ...

            ANSWER

            Answered 2021-May-10 at 15:30

            I have not looked through all your code because as I have understood the question is about one function implementation that splits an original list to some other lists.

            Though I am sure that there are drawbacks in your code as for example the function print_CharList outputs internal codes of characters instead of characters stored in a list themselves.

            Source https://stackoverflow.com/questions/67471317

            QUESTION

            Question about about splitted Linked list
            Asked 2021-May-06 at 21:17

            I've got this question where I'm supposed to write a function called - "createList" that gets a linked list(without a dummy element) of ints. The function should remove every element that is bigger than the previous one and the next one. Also, I have to make a new linked list (without a dummy element) where I place all the removed elements from the original linked list. (The elements should stay in the same order that they appeared in the original linked list). (createlist is createListEx4() in my code)

            For instance, an original linked list : 3->6->1->9->8->4->5;

            would be updated to : 3->1->8->4;

            The "removed elements" linked list would be: 6->9->5;

            The function will return a pointer to the "removed elements" linked list

            I wrote this code and I cant seem to understand how to make it work. There is a memory leak while I print the "removed elements" linked list, and doesn't return the correct elements.

            ...

            ANSWER

            Answered 2021-May-06 at 16:46

            Your code is much more complicated than need and also contains a number of logical errors.

            For instance, you shouldn't use malloc and free when moving node from one list to the other. Just change pointers.

            And this part from the start of createListEx4

            Source https://stackoverflow.com/questions/67420766

            QUESTION

            How does this recursive function to reverse a linked list work?
            Asked 2021-May-05 at 20:38

            I found the function below that reverses a linked list recursively:

            ...

            ANSWER

            Answered 2021-May-05 at 11:45

            Actually, I don't understand that function. First, you should only need to be passing to such a function the head of the list; I don't know why argument end is being passed or why it even needs to be passed. Also, argument self suggests that this is a method that is part of a class definition that is not being shown. Let's start anew:

            Here is a simple class for defining a node that can be linked to another node and be tagged with a "name" for identification. We also include a small function to walk the linked list to print out the nodes:

            Source https://stackoverflow.com/questions/67399657

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install linked-list

            You can install using 'npm i @datastructures-js/linked-list' or download it from GitHub, npm.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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