startpoint | startpoint是一个身份系统,提供用户、树形结构组、token等API。
kandi X-RAY | startpoint Summary
kandi X-RAY | startpoint Summary
startpoint是一个身份系统,提供用户、树形结构组、token等API。
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of startpoint
startpoint Key Features
startpoint Examples and Code Snippets
public static boolean isValid(String startPoint, HashSet flights) {
if (flights.isEmpty())
return true;
for (Flight i : flights) {
if (startPoint.equals(i.start)) {
return true;
}
Community Discussions
Trending Discussions on startpoint
QUESTION
I have simple app below, in SwiftUI, it throw an error like "Cannot convert value of type" I was use AppView(count: 5, total: 10)
, still same, but I did not understand very well, which point I miss, any idea will be appreciated.
Code:
...ANSWER
Answered 2021-May-26 at 09:19The problem is that you aren't actually passing in any values to your AppView
init in your AppView_Previews
, you just specified the input argument types. You need to pass in concrete values.
QUESTION
Given a start and end point in xaml, I can draw a straight line.
...ANSWER
Answered 2021-Jun-08 at 12:32QUESTION
I'm still learning on the job and my question may seem stupid.
I've got a list of movies and on the tap I want to show card of the selected movie.
So I've got my ResultsView
...ANSWER
Answered 2021-Jun-07 at 08:58Instead of using isPresented
for .sheet
you can use .sheet(item:, content:)
and pass the whole result
object
QUESTION
I want to access query strings from url in nuxtjs page. this is the page url with query strings -
...ANSWER
Answered 2021-Jun-06 at 10:24from the template you can access to it from $route
object like $route.query
and from the vue instance you can write this.$route.query
also you can check the $route
object from vue dev tools. check out the picture below:
to pass the queries to data object you can just write:
QUESTION
For a school project I have to create an application using some map (google maps or openstreetmap). My choice is to use OpenStreetMap because it's free.
So I have a form, in this form I need to click on a map to get the long/lat I want.
But I don't know how to set the onclicklistener correctly.
This is my activity :
...ANSWER
Answered 2021-Jun-05 at 14:05Ok I found by myserlf, here is the solution if someone else need :
QUESTION
The combo box closes when I try to move the slider. I tried different methods but nothing helps, in particular putting all the content inside the ToggleButton
...ANSWER
Answered 2021-Jun-01 at 14:44Do you have only one item in your ComboBox? The built-in behavior of a ComboBox after an item is selected is to collapse. Selecting an element is the transfer of focus, including to any of its child elements. As soon as you click on the Slider it receives focus, the item is selected and the CombobBox collapses.
In general, it looks like some kind of nonsense, complete . ComboBox is for selecting items from a list of items that you don't even have. If you just need to hide-reveal a set of elements, then use Expander.
If you need something different, then explain normally and in detail what you want to implement.
The answer is supplemented by an explanation for additional details in the question:
I'm trying to make a context menu where I can move the slider and so that it doesn't close, the expander doesn't fit because I don't need to move the elements of my window, but open on top of it
In WPF, elements are selected based on their behavior logic. And their visual appearance is set by styles and/or templates.
ComboBox behavior: when you click on it, expand the list, when you click on an item in the list, select it and collapse the list.
Do you need this behavior?
Not.
Hence you don't need a ComboBox.
Most likely, judging by your description, you need a combination of ToggleButton and Popup.
A simple example:
QUESTION
In my WPF application I have an animation of a certain element. The element to be animated looks like this.
...ANSWER
Answered 2021-May-31 at 12:05Notice in the working example you have a transparent brush set to the Stroke property.
But in the first example, nothing is set to this property.
Hence it is null.
And null has no properties to animate them.
You can explicitly set SolidColorBrush instance in this property, give this instance a name, and access its Color property directly.
It will be much easier than all these casts.
Example:
QUESTION
I'm trying to build a view that is a rounded rectangle in a bar chart, with a gradient that gets progressively darker the higher value
is (value is on a 0-10.0 scale). But I can't seem to figure how how to use UnitPoint
here for endPoint to get the correct point where the gradient should end. In other words if value = 5.0, I want the gradient to show the top of the bar as half way to the gradient's darkest color, or said another way the gradient's darkest color is always at 10.0 and the bar's color will only show as high as the bar is.
ANSWER
Answered 2021-May-26 at 20:39I think your best bet is to "mask" the gradient, rather than trying to calculate the endPoint
.
Here's an example with 5 "bars" in an HStack
- the first bar has a max value of 10
, then the bars' values go 9, 7.5, 5, 2
:
Sample code:
QUESTION
For all period elements I need to use a generic url, which is stored in parallel level in same JSON data / XML map. I am therefor trying to navigate to the element "url", using current node as startpoint. I can do that using the index number but not the key name.
I activate test-3 but commented-out the other tests, since test-3 gives wanted result.
Question: Is it possible to query using key name instead of index number, towards a XML map?
If its not possible to use relative navigation in map, then I am fine with other ways of querying the element "url".
JSON:
...ANSWER
Answered 2021-May-23 at 09:01You can use /*:map/*:string[@key = 'url']
or declare the fn
namespace (with e.g. xmlns:fn="http://www.w3.org/2005/xpath-functions"
) and use it instead of the wildcard with e.g. /fn:map/fn:string[@key = 'url']
.
Or upwards with e.g. ../../fn:string[@key = 'url']
.
QUESTION
I am trying to render a linear gradient on a rectangle. Here is the code:
...ANSWER
Answered 2021-May-19 at 08:22What a fun problem :)
The "naive" approach would be to render the gradient as a square and then either rotate it or squeeze or stretch it to fit the rectangle. Rotating requires more maths so here's the "squeezing" version:
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